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Nataly_w [17]
1 year ago
15

A shop will give discount of 10% if the cost of purchased quantity is more than 1000. Ask user for quantity suppose, one unit wi

ll cost 100. Judge and print total cost for user.
Computers and Technology
1 answer:
UkoKoshka [18]1 year ago
4 0

Answer:

The program in Python is as follows:

qty = int(input("Quantity: "))

price = 100 * qty

if qty >1000:

    price = (100 - 0.10 * 100) * qty

print("Cost: "+str(price))

Explanation:

This prompts the user for the quantity

qty = int(input("Quantity: "))

This calculates the price or cost, without discount

price = 100 * qty

This checks if the quantity is greater than 1000

if qty >1000:

If yes, this calculates the price or cost, after discount

    price = (100 - 0.10 * 100) * qty

This prints the calculated cost

print("Cost: "+str(price))

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Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer
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Answer:

Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

Explanation:

The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

for the case i = n-2, invariant p is product of a[0], a[1], a[2] .... a[n-3].a[n-2]. It is the product of (n-1) terms. In while loop, incrementing the value of i, so i=n-1

And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

If i = n , n - i = 0 , it will violate condition of while loop, so, the while loop will terminate at i = n at this time loop invariant P = a[0].a[1].a[2]....a[n-2].a[n-1]

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