Answer:
19.71 ms
Explanation:
The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.
Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms
Head movement time from track 8 to track 9 = seek time = 2 ms
rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms
The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms
Answer:
method for user authentication to the network
Provide detailed information about a user
Explanation:
An in AD, a user account consists of all the information that includes user names, passwords, and groups. All these information defines a domain user in which a user account has membership access to. With the advanced features of Kerbos, mutual authentication in user accounts to a service is achieved.
Answer:
d. broad needs and few customers.
Explanation:
This strategy is based on creation of unique and valuable persons.
Broad needs and few customers (Wealth Management )
Wealth management is a service that combines to address the needs of clients. Wealth Management utilizes financial discipline such as financial and investment , accounting and tax.This service is appropriate for individuals with broad array of diverse needs.
Answer:
array = input("Enter the list of computer memory: ").split(',')
int_arr = [int(x) for x in array]
segment = int(input("Enter the length of segment to analyze: "))
list_len = len(int_arr)
segList = []
mini = []
for x,i in enumerate(int_arr):
seg = int_arr[i-1:segment+i-1]
if len(seg) == segment:
segList.append(seg)
for x in segList:
mini.append(min(x))
result = mini.index(min(mini))
print("Segment with the minimum memory is: ",segList[result])
Explanation:
The python program prints out the segment after analysis, with the smallest disk memory space. The code gets the array of computer rows from the user input and segments the array with the number of segment input, then the minimum is compared for all segments in the network.
Answer:
I think the answer is going to be paragraph
