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lesantik [10]
2 years ago
10

Given an int variable k, an int array incompletes that has been declared and initialized, an int variable studentID that has bee

n initialized, and an int variable numberOfIncompletes, write code that counts the number of times the value of studentID appears in incompletes and assigns this value to numberOfIncompletes. You may use only k, incompletes, studentID, and numberOfIncompletes. SUBMIT
Computers and Technology
1 answer:
Feliz [49]2 years ago
7 0

Answer:

check the explanation

Explanation:

Variables when it comes to programming are used to store data to be documented and manipulated in a computer program. They can also be used for labeling stored data with a descriptive name and any other needed details, so that the programs can be comprehended more understandably by the reader and ourselves.

to solve the question, we will write this set of codes;

numberOfIncompletes = 0;

for(k = 0; k < incompletes.length; k++)

{

       if(incompletes[k] == studentID)

           numberOfIncompletes++;

}

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Design an application for Bob's E-Z Loans. The application accepts a client's loan amount and monthly payment amount. Output the
zmey [24]

Answer:

part (a).

The program in cpp is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   std::cout << "Loan balance: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>0)

   {

       if(balance<payment)    

         { payment = balance;}

       else

       {  

           std::cout << balance <<"\t\t\t"<< payment << std::endl;

           balance = balance - payment;

       }

   }

   return 0;

}

part (b).

The modified program from part (a), is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   double charge=0.01;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   balance = balance +( balance*charge );

   std::cout << "Loan balance with 1% finance charge: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>payment)

   {

           std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

           balance = balance +( balance*charge );

           balance = balance - payment;

       }

   if(balance<payment)    

         { payment = balance;}          

   std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

   return 0;

}

Explanation:

1. The variables to hold the loan balance and the monthly payment are declared as double.

2. The program asks the user to enter the loan balance and monthly payment respectively which are stored in the declared variables.  

3. Inside a while loop, the loan balance and monthly payment for each month is computed with and without finance charges in part (a) and part (b) respectively.

4. The computed values are displayed for each month till the loan balance becomes zero.

5. The output for both part (a) and part (b) are attached as images.

4 0
2 years ago
Write code that determines the number of full days represented by the number of hours stored in the variable hours and stores th
taurus [48]

Answer:

hours = 50

full_days = int(hours / 24)

print("The number of full days in " + str(hours) + " hours is " + str(full_days))

Explanation:

Initialize the hours

Since there are 24 hours in a full day, divide the hours by 24. Note that you need to typecast it to the int, because the result is a decimal value by default

Print the values as requested

4 0
2 years ago
Write the definition of a class Telephone. The class has no constructors, one instance variable of type String called number, an
balu736 [363]

Answer:

The definition of a class Telephone is given as  

public class Telephone // class telephone

{

String number; // variable  number of type string

static int quantity = 250; // variable  quantity  of type int

static double total = 1565.92;  // variable  total  of type double

}

Explanation:

Following is the description of Statement

  • Create a class "Telephone" by using the keyword class.In that class we declared data member .
  • We declared a variable "number" of type "string" which has no constructor.
  • We declared a variable  "quantity" of type "int" which is a static type variable. The static type variable retains the value during the program execution.
  • We declared a variable  "total" of type "double" which is a static type variable. The static type variable retain the value during the program execution .
5 0
2 years ago
To gain experience of using and combing different sorting algorithms: election sort, insertion sort, merge sort, and quick sort.
ch4aika [34]

Answer:

Motivation? The search problem.

Sorting algorithms: insertion sort, shellsort, heapsort, mergesort, quicksort, bubblesort

At the very least, "general purpose" sorting algorithms require O(n log n) comparisons

Explanation:

3 0
2 years ago
Problem 2 - K-Best Values - 30 points Find the k-best (i.e. largest) values in a set of data. Assume you are given a sequence of
masya89 [10]

Answer:

See explaination

Explanation:

/**KBestCounter.java**/

import java.util.ArrayList;

import java.util.List;

import java.util.PriorityQueue;

public class KBestCounter<T extends Comparable<? super T>>

{

PriorityQueue heap;

int k;

public KBestCounter(int k)

{

heap = new PriorityQueue < Integer > ();

this.k=k;

}

//Inserts an element into heap.

//also takes O(log k) worst time to insert an element

//into a heap of size k.

public void count(T x)

{

//Always the heap has not more than k elements

if(heap.size()<k)

{

heap.add(x);

}

//if already has k elements, then compare the new element

//with the minimum element. if the new element is greater than the

//Minimum element, remove the minimum element and insert the new element

//otherwise, don't insert the new element.

else if ( (x.compareTo((T) heap.peek()) > 0 ) && heap.size()==k)

{

heap.remove();

heap.add(x);

}

}

//Returns a list of the k largest elements( in descending order)

public List kbest()

{

List al = new ArrayList();

int heapSize=heap.size();

//runs O(k)

for(int i=0;i<heapSize;i++)

{

al.add(0,heap.poll());

}

//Restoring the the priority queue.

//runs in O(k log k) time

for(int j=0;j<al.size();j++) //repeats k times

{

heap.add(al.get(j)); //takes O(log k) in worst case

}

return al;

}

}

public class TestKBest

{

public static void main(String[] args)

{

int k = 5;

KBestCounter<Integer> counter = new KBestCounter<>(k);

System.out.println("Inserting 1,2,3.");

for(int i = 1; i<=3; i++)

counter.count(i);

System.out.println("5-best should be [3,2,1]: "+counter.kbest());

counter.count(2);

System.out.println("Inserting another 2.");

System.out.println("5-best should be [3,2,2,1]: "+counter.kbest());

System.out.println("Inserting 4..99.");

for (int i = 4; i < 100; i++)

counter.count(i);

System.out.println("5-best should be [99,98,97,96,95]: " + counter.kbest());

System.out.println("Inserting 100, 20, 101.");

counter.count(100);

counter.count(20);

counter.count(101);

System.out.println("5-best should be [101,100,99,98,97]: " + counter.kbest());

}

}

5 0
2 years ago
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