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posledela
2 years ago
15

A variable like userNum can store a value like an integer. Extend the given program to print userNum values as indicated. (1) Ou

tput the user's input.Enter integer: 4 You entered: 4(2) Extend to output the input squared and cubed. Hint: Compute squared as userNum * userNum. (Submit for 2 points, so 4 points total).Enter integer: 4 You entered: 44 squared is 16 And 4 cubed is 64!!(3) Extend to get a second user input into userNum2. Output sum and product. (Submit for 1 point, so 5 points total).Enter integer: 4 You entered: 44 squared is 16 And 4 cubed is 64!! Enter another integer: 5 4 + 5 is 9 4 * 5 is 20import java.util.Scanner;public class OutputWithVars {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);int userNum = 0;System.out.println("Enter integer: ");userNum = scnr.nextInt();return;}}
Computers and Technology
1 answer:
UNO [17]2 years ago
6 0

Answer:

Write the following lines of code just before the return statement

//1

       System.out.println("You entered "+userNum);        

       // 2

       System.out.println(userNum+" squared is "+(Math.pow(userNum, 2))+" and "+userNum+" cubed is "+(Math.pow(userNum, 3)));

       //3

       int userNum2 = 0;

       System.out.print("Enter another integer: ");

       userNum2 = scnr.nextInt();

int sum = userNum + userNum2;

       System.out.println(userNum+" + "+userNum2+" is "+sum);

int product = userNum * userNum2;

       System.out.println(userNum+" * "+userNum2+" is "+product);

Explanation:

I continued the program from where you stopped in the question

The explanation has been added as an attachment

Download docx
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Following are groups of three​ phrases, which group states three ways to improve your​ concentration?
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1 year ago
Write code that uses the input string stream inss to read input data from string userinput, and updates variables usermonth, use
mr Goodwill [35]

Answer:

It will be a java code.

Explanation:

import java.util.Scanner;

public class StringInputStream {

    public static void main (String [] args) {

        Scanner inSS = null;

        String userInput = "Jan 12 1992";

        inSS = new Scanner(userInput);`

        String userMonth = "";

        int userDate = 0;

        int userYear = 0;

        /* Your solution goes here  */

        System.out.println("Month: " + userMonth);

        System.out.println("Date: " + userDate);

        System.out.println("Year: " + userYear);

        return;

   }

}

3 0
2 years ago
Read 2 more answers
Instead of sending an entire file in one big chunk across the​ Internet, __________ is used which dices the file up into little
azamat

Answer:

TCP/IP

Explanation:

TCP/IP which stands for Transmission Control Protocol and Internet Protocol are network protocols which divide your message into smaller chunks or fragments known as network packets and sends them out onto the Internet. When the chunks arrive at the intended destination, TCP/IP on the receiving end reassembles the network packets into the original message.

TCP/IP are the main protocols used for sending data over the internet.

7 0
2 years ago
Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re
aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)    

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=2.938

The sample deviation calculated s=0.472

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.78

Now we have everything in order to replace into formula (1):

2.938-2.78\frac{0.472}{\sqrt{5}}=2.351    

2.938+2.78\frac{0.472}{\sqrt{5}}=3.525    

So on this case the 95% confidence interval would be given by (2.351;3.525)    

5 0
2 years ago
You have enabled IPv6 on two of your routers, but on the interfaces you have not assigned IPv6 addresses yet. You are surprised
babymother [125]

Answer:

You have enabled IPv6 on two of your routers, but on the interfaces you have not assigned IPv6 addresses yet. You are surprised to learn that these two machines are exchanging information over those interfaces. How is this possible?

a. Due to anycast addressing

b. Due to ICMPv6

c. Due to the NATv6 capability

d. Due to the link-local IPv6 addresses

The correct answer is D. Due to the link-local addresses

Explanation:

LINK-LOCAL ADDRESS

Link-local addresses are addresses that can be used for unicast communications on a confined LAN segment.  The requirement with these addresses is that they are only locally-significant (i.e., restricted to a single LAN broadcast domain) and are never used to source or receive communications across a layer-3 gateway.

Typically, link-local IPv6 addresses have “FE80” as the hexadecimal representation of the first 10 bits of the 128-bit IPv6 address, then the least-significant 64-bits of the address are the Interface Identifier (IID).  Depending on the IID algorithm the node’s operating system is using, the IID may use either modified EUI-64 with SLAAC, the privacy addressing method (RFC 4941)), or the newly published Stable SLAAC IID method(RFC 8064).

When a host boots up, it automatically assigns an FE80::/10 IPv6 address to its interface.  You can see the format of the link-local address below. It starts with FE80 and is followed by 54 bits of zeros. Lastly, the final 64-bits provide the unique Interface Identifier.

FE80:0000:0000:0000:abcd:abcd:abcd:abcd

Link-local IPv6 addresses are present on every interface of IPv6-enabled host and router.  They are vital for LAN-based Neighbor Discovery communication.  After the host has gone through the Duplicate Address Detection (DAD) process ensuring that its link-local address (and associated IID) is unique on the LAN segment, it then proceeds to sending an ICMPv6 Router Solicitation (RS) message sourced from that address.

IPv6 nodes send NS messages so that the link-layer address of a specific neighbor can be found. There are three operations in which this message is used:

▪   For detecting duplicate address

▪   Verification of neighbor reachability

▪   Layer 3 to Layer 2 address resolution (for ARP replacement)  ARP is not included in IPv6 as a protocol but rather the same functionality is integrated into ICMP as part of neighbor discovery. NA message is the response to an NS message.  From the figure the enabling of interaction or communication between neighbor discoveries between two IPv6 hosts can be clearly seen.

3 0
2 years ago
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