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2 years ago

What is retrieved from a search containing two terms separated by the AND operator?

Computers and Technology

1 answer:

egoroff_w [7]2 years ago

8 0

Answer:

A AND B= 1 or 0

1 1 1

0 1 0

1 0 0

0 0 0

So, as explained above if both are 1 we then only get 1, or else we get 0 always in case of AND which is a logical operator, whose output can be 0 or 1 only. This is being depicted above.

Explanation:

If both are 1 we get 1 or always else, we get the output =0.

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Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combinin

Dmitry_Shevchenko [17]

Answer:

Follows are the code to this question:

#include<iostream>//defining header file

using namespace std;// use package

int main()//main method

{

int red,green,blue,x;//declaring integer variable

cin>> red >>green>>blue;//use input method to input value

if(red<green && red<blue)//defining if block that check red value is greater then green and blue

{

x = red;//use x variable to store red value

}

else if(green<blue)//defining else if block that check green value greater then blue

{

x= green; //use x variable to store green value

}

else//defining else block

{

x=blue;//use x variable to store blue value

}

red -= x;//subtract input integer value from x

green -=x; //subtract input integer value from x

blue -= x;//subtract input integer value from x

cout<<red<<" "<<green<<" "<<blue;//print value

return 0;

}

Output:

130 50 130

80 0 80

Explanation:

In the given code, inside the main method, four integers "red, green, blue, and x" are defined, in which "red, green, and blue" is used for input the value from the user end. In the next step, a conditional statement is used, in the if block, it checks red variable value is greater than then "green and blue" variable. If the condition is true, it will store red variable value in "x", otherwise, it will goto else if block.

In this block, it checks the green variable value greater than the blue variable value. if the condition is true it will store the green variable value in x variable.
In the next step, else block is defined, that store blue variable value in x variable, at the last step input variable, is used that subtracts the value from x and print its value.

5 0

2 years ago

Write an expression that continues to bid until the user enters 'n'.

alisha [4.7K]

Answer:

Add this while statement to the code:

while(keep_going!='n'):

#the program keeps asking user to continue bidding until the user enter 'n' to stop.

Here is the code for ACTIVITY 53.3. While loop: Insect growth:

num_insects = int(input())

while num_insects <= 100:

print(num_insects, end=' ')

num_insects = num_insects * 2

Explanation:

Here is the complete code for 1)

import random

random.seed (5)

keep_going='-'

next_bid = 0

while(keep_going!='n'):

next_bid = next_bid + random.randint(1, 10)

print('I\'ll bid $%d!' % (next_bid))

print('continue bidding?', end='')

keep_going = input()

Here the the variable keep_going is initialized to a character dash keep_going='-'

The statement keep_going = input() has an input() function which is used to take input from user and this input value entered by user is stored in keep_going variable. while(keep_going!='n'): is a while loop that keeps iterating until keep_going is not equal to 'n'. print('continue bidding?', end='') statement prints the continue bidding? message on the output screen. For example the user enters 'y' when this message appears on screen. So keep_going = 'y' . So the operation in this statement next_bid = next_bid + random.randint(1, 10) is executed in which next_bid is added to some randomly generated integer within the range of 1 to 10 and print('I\'ll bid $%d!' % (next_bid)) prints the result on the screen. Then the user is prompted again to continue biffing. Lets say user enters 'n' this time. So keep_going = 'n'. Now the while loop breaks when user enters 'n' and the program ends.

num_insects = int(input()) #the user is prompted to input an integer

while num_insects <= 100: #the loop keeps iterating until value of num_insects exceeds 100

print(num_insects, end=' ') #prints the value of num_insects

num_insects = num_insects * 2 #the value of num_insects is doubled

For example user enters 8. So

num_insects = 8

Now the while loop checks if this value is less than or equal to 100. This is true because 8 is less than 100. So the body of while loop executes:

print(num_insects, end=' ') statement prints the value of num_insects

So 8 is printed on the screen.

num_insects = num_insects * 2 statement doubles the value of num_insects So this becomes:

num_insects = 8 * 2

num_insects = 16

Now while loop checks if 16 is less than 100 which is again true so next 16 is printed on the output screen and doubled as:

num_insects = 16 * 2

num_insects = 32

Now while loop checks if 32 is less than 100 which is again true so next 32 is printed on the output screen and doubled as:

num_insects = 32 * 2

num_insects = 64

Now while loop checks if 64 is less than 100 which is again true so next 64 is printed on the output screen and doubled as:

num_insects = 64 * 2

num_insects = 128

Now while loop checks if 128 is less than 100 which is false so the program stops and the output is:

8 16 32 64

The programs along with their output is attached.

7 0

2 years ago

In __________ mode, the data within an ip packet is encrypted, but the header information is not.

Anvisha [2.4K]

Answer:

Transport mode

Explanation:

The host-to-host transport mode of internet protocol security (IPsec) is mostly used between two host devices or between a user and a server. When you go online and Google something, what you have done is send a packet request to a server. The IPsec’s transport mode offers secure protection to parts of this IP packet. The packet consists of the original IP header and an IP payload (TCP header and data). In transport mode, only the IP payload is encrypted. The original IP header is not.

6 0

2 years ago

A large software development company employs 100 computer programmers. Of them, 45 areproficient in Java, 30 in C, 20 in Python,

melisa1 [442]

Answer:

18, 13, 19

Explanation:

Number of computer programmers proficient only in Java = 45 - ( 1+1+6) = 37

Number of computer programmers proficient only in C++ = 30 - (6+1+5) = 18

Number of computer programmers proficient only in python = 20 - ( 1+1+5) = 13

Number of computer programmers are not proficient in any of these three languages = 100 - ( 37 + 18 + 13 + 1+ 1+ 5+ 6 ) = 100 - 81 = 19

4 0

2 years ago

_____________ helps to control and limit the number of consecutive request failures that cross a threshold. Review breaker Micro

True [87]

Answer:

Circuit breaker

Explanation:

Circuit breaker -

It is a type of electrical switch , whose main function is to protect the electrical circuit by the process of short circuit or overloading , is referred to as a circuit breaker .

The circuit breaker , as the name suggests , disrupts the circuit as soon as there is the condition of overloading or short circuit , and thereby saves the appliances .

Hence , from the given information of the question,

The correct term is circuit breaker .

5 0

2 years ago