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1 year ago

What is Accenture's role in Multi-party Systems?

Computers and Technology

1 answer:

Maslowich1 year ago

7 0

Answer:

helping a single company develop a data ingress platform

Explanation:

Accenture's role in Multi-party Systems is "helping a single company develop a data ingress platform."

This is evident in the fact that Accenture formed a strategic alliance with Marco Polo Network in recent times. The purpose of the alliance is to create a single data ingress platform for many connections. That is those on the network can easily install, either on-prem or through the cloud such as the Marco Polo platform, and then later incorporates the data into the enterprise resource planning system.

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Show how to define a view tot_credits (year, num_credits), giving the total number of credits taken by students in each year

andreev551 [17]

Hi! I'm a Digital Marketer Intern at hotels.ng and I have a moderate knowledge on programming.

First, your question is not very explanatory. The term "view" is often used in back-end web development. A view is simply a Python function that takes a Web request and returns a Web response.

But I'm not sure this is what you want, so I'll just go ahead and write a python function involving class to return the total number of credits taken by a student.

I'll answer this question using Python.

class student(object):

credits = None

year = None

def num_credits(self):

#get credit value

self.credits = input("Enter the total number of credits: " )

pass

def getYear(self):

self.year = input("Enter current year: ")

pass

def tot_credits(self):

TotalCredits = tempTotalCredits + self.num_credits

print "Your total credits are :"+" "+str(TotalCredits)

3 0

2 years ago

An aviation tracking system maintains flight records for equipment and personnel. The system is a critical command and control s

sergeinik [125]

Answer:

offline backup solution

Explanation:

In such a scenario, the best option would be an offline backup solution. This is basically a local and offline server that holds all of the flight record data that the cloud platform has. This offline backup server would be updated frequently so that the data is always up to date. These servers would be owned by the aviation company and would be a secondary solution for the company in case that the cloud platform fails or the company cannot connect to the cloud service for whatever reason. Being offline allows the company to access the database regardless of internet connectivity.

5 0

2 years ago

B.) Define latency and jitter for service flow in a fixed wireless system.

yuradex [85]

The answer would be between the base station and the subscriber station.

7 0

2 years ago

To use the Web, each client computer requires a data link layer software package called a Web browser. True False

Luden [163]

Answer:

The answer is "False"

Explanation:

The data link layer is the protocol layer within a program, which controls data movement into a physical wireless connection. This layer is a second layer, that is also known as a collection of communications applications.

The server network, in which many clients request, and receive service from a centralized server.

This system provides an interface, that enables a user to request server services and view the server returns results, that's why it is wrong.

6 0

2 years ago

A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, an

yulyashka [42]

The question is incomplete. It can be found in search engines. However, kindly find the complete question below:

Question

Cites as a pitfall the utilization of a subset of the performance equation as a performance metric. To illustrate this, consider the following two processors. P1 has a clock rate of 4 GHz, average CPI of 0.9, and requires the execution of 5.0E9 instructions. P2 has a clock rate of 3 GHz, an average CPI of 0.75, and requires the execution of 1.0E9 instructions. 1. One usual fallacy is to consider the computer with the largest clock rate as having the largest performance. Check if this is true for P1 and P2. 2. Another fallacy is to consider that the processor executing the largest number of instructions will need a larger CPU time. Considering that processor P1 is executing a sequence of 1.0E9 instructions and that the CPI of processors P1 and P2 do not change, determine the number of instructions that P2 can execute in the same time that P1 needs to execute 1.0E9 instructions. 3. A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, and consider that the processor with the largest MIPS has the largest performance. Check if this is true for P1 and P2. 4. Another common performance figure is MFLOPS (millions of floating-point operations per second), defined as MFLOPS = No. FP operations / (execution time x 1E6) but this figure has the same problems as MIPS. Assume that 40% of the instructions executed on both P1 and P2 are floating-point instructions. Find the MFLOPS figures for the programs.

Answer:

(1) We will use the formula:

CPU time = number of instructions x CPI / Clock rate

So, using the 1 Ghz = 10⁹ Hz, we get that

CPU time₁ = 5 x 10⁹ x 0.9 / 4 Gh

= 4.5 x 10⁹ / 4 x 10⁹Hz = 1.125 s

and,

CPU time₂ = 1 x 10⁹ x 0.75 / 3 Ghz

= 0.75 x 10⁹ / 3 x 10⁹ Hz = 0.25 s

So, P2 is actually a lot faster than P1 since CPU₂ is less than CPU₁

(2)

Find the CPU time of P1 using (*)

CPU time₁ = 10⁹ x 0.9 / 4 Ghz

= 0.9 x 10⁹ / 4 x 10⁹ Hz = 0.225 s

So, we need to find the number of instructions₂ such that CPU time₂ = 0.225 s. This means that using (*) along with clock rate₂ = 3 Ghz and CPI₂ = 0.75

Therefore, numbers of instruction₂ x 0.75 / 3 Ghz = 0.225 s

Hence, numbers of instructions₂ = 0.225 x 3 x 10⁹ / 0.75 = 9 x 10⁸

So, P1 can process more instructions than P2 in the same period of time.

(3)

We recall that:

MIPS = Clock rate / CPI X 10⁶

So, MIPS₁ = 4GHZ / 0.9 X 10⁶ = 4 X 10⁹HZ / 0.9 X 10⁶ = 4444

MIPS₂ = 3GHZ / 0.75 X 10⁶ = 3 x 10⁹ / 0.75 X 10⁶ = 4000

So, P1 has the bigger MIPS

(4)

We now recall that:

MFLOPS = FLOPS Instructions / time x 10⁶

= 0.4 x instructions / time x 10⁶ = 0.4 MIPS

Therefore,

MFLOPS₁ = 1777.6

MFLOPS₂ = 1600

Again, P1 has the bigger MFLOPS

3 0

1 year ago