<em>Intrusion means unauthorized and harmful activities happening in your system. Any irregularities in the system is considered as intrusion and therefore monitored by administrators and can be detected using Intrusion Detection System.
</em>
<em>Examples of Intrusion attacks in a network are:
</em>
- <em>Denial of Service (Dos) - denial of service means flooding the system causing it to crash and unable to respond to a service request. Normally, a DoS attack is facilitated by numbers of hosts sending enormous request to a victim computer. The requests can be in a form of code that would flood the system and making it to unresponsive. </em>
- <em>Man in the Middle Attack (MiM) - a hacker would be in the middle of the communication between a client computer and a server computer. The hacker can mimic IPs within the network and steal information then sends it to the intended receiver. </em>
- <em>SQL Injection - For websites that runs database like SQL, a code by the hacker can be added to the website and making him gained access to the database information successfully.</em>
Answer:
The answer is the last option
Answer:
C code explained below
Explanation:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int userNum;
bool isPositive;
bool isEven;
scanf("%d", &userNum);
isPositive = (userNum > 0);
isEven = ((userNum % 2) == 0);
if(isPositive && isEven){
printf("Positive even number");
}
else if(isPositive && !isEven){
printf("Positive number");
}
else{
printf("Not a positive number");
}
printf("\n");
return 0;
}
Explanation:
Execution step:
1. Starting the program
2. It will get the animal name
3. Check whether the animal eats only plants. Then it prints "Herbivore". If the condition is false, it prints "carnivore".
4. Stop the program
To identify input, output and decision:
Start and Stop (oval): These are neither input nor output
Does it eat only plants?: Decision making statement ("d")
Read the names of the animals(Parallelogram): Input ("i")
Print Herbivore, Print Carnivore: Output "o"
Scenario 1: Input is lion
1. Start
2. Reads the input as "lion"
3. Check if lion eats only plants. So here it is false
4. Print "Carnivore"
5. Stop
Scenario 1: Input is Elephant
1. Start
2. Reads the input as "Elephant"
3. Check if lion eats only plants. So here it is true
4. Print "Herbivore"
5. Stop
Answer:
linkedListOperations = linkedListLibrary.InsertSorted(currNode, linkedListOperations); // this is right
linkedListLibrary.InsertSorted(currNode, linkedListOperations); // half right, it count how much operation but it doesn't store it anywhere in main.
vectorOperations = vectorLibrary.InsertSorted(tempBook, vectorOperations); // this is right
vectorLibrary.InsertSorted(tempBook, vectorOperations); // half right, it count how much operation but it doesn't store it anywhere in main.
cout << "Number of linked list operations: " << linkedListOperations << endl;
cout << "Number of vector operations: " << vectorOperations << endl;
Explanation:
The first, you are calling InsertSorted with linkedListLibrary and than you can store the number of operation inside the "linkedListOperations" variable. Then you do the same with vectorLibrary.
