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Vladimir79 [104]
2 years ago
9

When ____ occur during preliminary debugging, dummy print statements—statements that are temporarily inserted into the code to d

isplay status information on the screen—can be used to help locate the error.
Computers and Technology
1 answer:
ANEK [815]2 years ago
4 0

Answer:

Logic error.

Explanation:

When a logic error occurs sometimes it becomes difficult to locate the error in the code.So to locate the error dummy print used to see which loop,if,else,switch case etc. is executing or not.

for example:-

for(int i=0;i<45;i++)

{

if(i!=1)

{

   continue;

}

cout<<i<<endl;

}

we wanted the loop to print all value of i except 1 but it is printing only 1.We can use dummy print statement for this code in if condition.for(int i=0;i<45;i++)

{cout<<"Loop"<<endl;

if(i!=1)

{

cout<<"Printing"<<endl;

   continue;

}

cout<<i<<endl;

}

We see that the loop is printed 45 times and printing 44 times.We found that the condition in if statement is wrong.It hould be '==' instead of '!='.

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15. It is the process of capturing data or translating information to recording format
Helen [10]

Answer:

A Documentation, hope this helps.

5 0
2 years ago
The Windows ________ is a hierarchical database that stores system configuration information. It maintains files used to control
Diano4ka-milaya [45]

Answer:

Registry

Explanation:

Windows Registry is used to store the configuration and setting information for hardware and software program which is critical for Windows operation. The registries are structured in hierarchical database model.  

Basically, hierarchical database model is akin to a tree format which consist of the parent nodes and their child nodes.  For example, a node named as HKEY_LOCAL_MACHINE can possess child nodes HARDWARE, SOFTWARE AND SYSTEM.

The node in the tree is also termed as a key.

8 0
2 years ago
Consider a short, 10-meter link, over which a sender can transmit at a rate of 150 bits/sec in both directions. Suppose that pac
Katarina [22]

Answer:

The Tp value 0.03 micro seconds as calculated in the explanation below is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP.

Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

Explanation:

Given details are below:

Length of the link = 10 meters

Bandwidth = 150 bits/sec

Size of a data packet = 100,000 bits

Size of a control packet = 200 bits

Size of the downloaded object = 100Kbits

No. of referenced objects = 10

Ler Tp to be the propagation delay between the client and the server, dp be the propagation delay and dt be the transmission delay.

The formula below is used to calculate the total time delay for sending and receiving packets :

d = dp (propagation delay) + dt (transmission delay)

For Parallel downloads through parallel instances of non-persistent HTTP :

Bandwidth = 150 bits/sec

No. of referenced objects = 10

For each parallel download, the bandwith = 150/10

  = 15 bits/sec

10 independent connections are established, during parallel downloads,  and the objects are downloaded simultaneously on these networks. First, a request for the object was sent by a client . Then, the request was processed by the server and once the connection is set, the server sends the object in response.

Therefore, for parallel downloads, the total time required  is calculated as:

(200/150 + Tp + 200/150 + Tp + 200/150 + Tp + 100,000/150 + Tp) + (200/15 + Tp + 200/15 + Tp + 200/150 + Tp + 100,000/15 + Tp)

= ((200+200+200+100,00)/150 + 4Tp) + ((200+200+200+100,00)/15 + 4Tp)

= ((100,600)/150 + 4Tp) + ((100,600)/15 + 4Tp)

= (670 + 4Tp) + (6706 + 4Tp)

= 7377 + 8 Tp seconds

Thus, parallel instances of non-persistent HTTP makes sense in this case.

Let the speed of propogation  of the medium be 300*106 m/sec.

Then, Tp = 10/(300*106)

               = 0.03 micro seconds

The Tp value 0.03 micro seconds as calculated above is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP. Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

4 0
2 years ago
1. Consider a client and a server connected through one router. Assume the router can start transmitting an incoming packet afte
mezya [45]

Answer:

As the total bytes are L, when h bytes out of L are sent from client to router the router immediately send these h bytes forward to next router. Thus simultaneously another set of h bytes reaches the router and therefore many actions are being performed in a simultaneous way.  

Explanation:

For finding end to end delay, calculations are done and briefed.

All the paper work along with explanation is attached for better understanding.

5 0
2 years ago
Kris, an IT manager at Park Infosystems, is handling four projects simultaneously. Each project has loaned and shared resources
Natalija [7]

Answer:

many-to-many relationship

Explanation:

They are different types of relationship between projects. A many-to-many relationship occurs when a row in a table associates with many related rows in another table. For example the relationship between an employee and a project, An employee can work on many projects and a project can have many employees working on it.

8 0
2 years ago
Read 2 more answers
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