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aniked [119]
2 years ago
14

Complete this truth Table. Write a program that you can enter from the keyboard, a 1 or 0 into three Boolean variables, A,B,C. W

rite an if statement that tests the condition ( (A or B ) and C ). Run the program 8 separate times, testing each of the following 8 combinations. Write the results below in the following truth table.
Module 9-Alternative Sequences and Complex logical Criteria v17 (1).pdf. Adobe Acrobat Reader DC
File Edit View Window Help
Home Tools Module 9 - Altema...X
A B C (A or B ) (A or B ) and C
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1

Computers and Technology
1 answer:
SSSSS [86.1K]2 years ago
8 0

Answer:

Following are the code to this question:

#include<stdio.h>//defining header file

int AND(int x,int y) //defining a method AND that hold two variable in its parameter

{

if(x==1 && y==1)//defining if block to check x and y value is equal to 1

{

return 1;//return value 1

}

else //defining else block

{

   return 0;//return value 0

}

}

int OR(int x,int y)//defining method OR that hold two variable in its parameter

{

if(x==0&&y==0)//defining if block to check x and y value is equal to 1

{

return 0;//return value 0

}

else //defining else block

{

   return 1;//return value 1

}

}

int main()//defining main method

{

int a,b,c;//defining integer variable  

int k=1;//defining integer variable k that holds a value 1

while(k<=8)//defining while loop for 8 time input

{

printf("Please insert 3 numbers in (0 0r 1):\n ");//print message

scanf("%d%d%d", &a, &b, &c);//input value

k++;//increment the value of k by 1

printf("value: %d\n",AND(OR(a,b),c));

}

return 0;

}

Output:

please find the attachment.

Explanation:

In the above-given C language code two methods "AND and OR" is declared, holds two integer variable "x and y" in its parameters, inside the method a conditional it used that can be defined as follows:

  • In the AND method, inside a conditional statement, if block check x and y both value is same that is 1 it will return 1 or it will goto else block in this it will return value 0.      
  • In the OR method, inside a conditional statement, if block check x and y both value is the same, that is 0 it will return 0 or it will goto else block in this it will return value 1.
  • In the main method, four integers "a,b,c, and k" is declared in which variable "a, b, c" is used in the loop for 8 times input values from the user and print method is used to call the method and prints its return values.

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Problem 2 - K-Best Values - 30 points Find the k-best (i.e. largest) values in a set of data. Assume you are given a sequence of
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Answer:

See explaination

Explanation:

/**KBestCounter.java**/

import java.util.ArrayList;

import java.util.List;

import java.util.PriorityQueue;

public class KBestCounter<T extends Comparable<? super T>>

{

PriorityQueue heap;

int k;

public KBestCounter(int k)

{

heap = new PriorityQueue < Integer > ();

this.k=k;

}

//Inserts an element into heap.

//also takes O(log k) worst time to insert an element

//into a heap of size k.

public void count(T x)

{

//Always the heap has not more than k elements

if(heap.size()<k)

{

heap.add(x);

}

//if already has k elements, then compare the new element

//with the minimum element. if the new element is greater than the

//Minimum element, remove the minimum element and insert the new element

//otherwise, don't insert the new element.

else if ( (x.compareTo((T) heap.peek()) > 0 ) && heap.size()==k)

{

heap.remove();

heap.add(x);

}

}

//Returns a list of the k largest elements( in descending order)

public List kbest()

{

List al = new ArrayList();

int heapSize=heap.size();

//runs O(k)

for(int i=0;i<heapSize;i++)

{

al.add(0,heap.poll());

}

//Restoring the the priority queue.

//runs in O(k log k) time

for(int j=0;j<al.size();j++) //repeats k times

{

heap.add(al.get(j)); //takes O(log k) in worst case

}

return al;

}

}

public class TestKBest

{

public static void main(String[] args)

{

int k = 5;

KBestCounter<Integer> counter = new KBestCounter<>(k);

System.out.println("Inserting 1,2,3.");

for(int i = 1; i<=3; i++)

counter.count(i);

System.out.println("5-best should be [3,2,1]: "+counter.kbest());

counter.count(2);

System.out.println("Inserting another 2.");

System.out.println("5-best should be [3,2,2,1]: "+counter.kbest());

System.out.println("Inserting 4..99.");

for (int i = 4; i < 100; i++)

counter.count(i);

System.out.println("5-best should be [99,98,97,96,95]: " + counter.kbest());

System.out.println("Inserting 100, 20, 101.");

counter.count(100);

counter.count(20);

counter.count(101);

System.out.println("5-best should be [101,100,99,98,97]: " + counter.kbest());

}

}

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