Answer:
The following are the code to this question:
code:
System.out.println(x); //use print method to print value.
Explanation:
In the given question, it simplifies or deletes code in the 11th line. This line has a large major statement.
In the case, the tests fail because only 1 line of output is required by the tester, but two lines are obtained instead.
It's to demonstrate that the input/output or testing requirements function throughout the model.
Answer:
double ComputeGasVolume(double pressure, double temperature, double moles){
double volume = moles*GAS_CONST*temperature/pressure;
return volume;
}
Explanation:
You may insert this function just before your main function.
Create a function called ComputeGasVolume that takes three parameters, pressure, temperature, and moles
Using the given formula, PV = nRT, calculate the volume (V = nRT/P), and return it.
<u>Answer:</u>
<em>1. The loop will run unless the value of answer equals to Capital N.</em> The method equals is “case-sensitive” that is lower case letter and upper case letters are considered different. That “a” and “A” means the same to us, but for the method equals it is different and equals method will return false if the case is not matching.
<em>2. a (int)(Math.random() * (upper − lower) ) + lower </em>
Since we need to consider the lower limit value together to get the desired results we need to add the value of lower limit to the multiplied answer.
<em>3. b while(userGuess != secretNumber || userGuess >= lowerLimit && userGuess <= upperLimit)</em>
Here the program is required to check the while loop and exit when user guess the number or we can say the loop should continue until the user guess the number, so that is why we have taken <em>userGuess!=secretNumber. </em>Next the loop should be exited if it is not within the range or we can say that the loop should run only if the guessed number is within the upper and lower limit.<em> That is why we have opted for the condition userGues>=lowerlimit && userGuess<=upperlimit.</em> Why we have taken && as the operator is that, it’s a range of values so && operator best suit for this kind of logical condition.
Answer:
Answered below
Explanation:
// Python implementation
incrementAmount = 5
basePrice = 10
price = 0
arrivalHour = int(input("Enter arrival hour 0-12: ")
if arrivalHour < 0 or arrivalHour > 12:
print ("Invalid hour")
if arrivalHour == 0:
price = basePrice
else:
price = arrivalHour * incrementAmount
totalPrice = price + basePrice
if totalPrice > 53:
totalPrice = 53
print ("Your bill is $totalPrice")
