Email client as port 25 is the default port for an email server.
Answer:validity
Explanation:
Because it dont sound right
Microsoft Online is free to use. It includes Microsoft Excel, Word, One - Note and PowerPoint. Microsoft Outlook (email app) is free as well, although it is a seperate download.
Another way to go is via Google docs, The Google drive is rather large and safe to store reports, docs, images, etc.
Both Microsoft online and Google Docs are accessible to use on virtually any device as in: PCs, Laptops, Tablets, Androids and Iphones.
Answer:
In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.
Explanation:
We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).
Using First-fit
First-fit means you assign the first available memory that can fit a process to it.
- 115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).
- 500KB will fit into the second partition. So, F2 will have a remaining free space of 100KB (600 - 500)
- 358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)
- 200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)
- 375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)
Using Best-fit
Best-fit means you assign the best memory available that can fit a process to the process.
- 115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)
- 500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)
- 358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)
- 200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)
- 375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)
Using Worst-fit
Worst-fit means that you assign the largest available memory space to a process.
- 115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)
- 500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)
- 358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)
- 200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)
- 375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.
Answer:
The program to this question as follows:
Program:
x=int(input('Input the first number: ')) #defining variable x and input value by user
y=int(input('Input the second number: ')) #defining variable y and input value by user
if x > y: #if block to check value x>y
max=x #define variable max that hold variable x value
print('max number is: ', x) #print value
else: #else block
max=y #define variable max that holds variable y value
print('max number is: ', y) #print value
Output:
Input the first number: 22
Input the second number: 33
max number is: 33
Explanation:
In the above code two-variable, "x and y" is defined, which holds a value, which is input by the variable. In the next step, the if block statement is used that can be described as follows:
- In the if block, it will check x is greater than y it will define a variable, that is "max", that holds variable x value and prints its value.
- In the else block, if the above condition is false it uses the max variable, that holds variable y value and prints its value.
