Answer: Decoupling action of the process address space refers to the physical memory of the device getting decoupled to provide address translation in automatic way. The benefit of this method is as follows:-
- Faster starting up of the program
- The physical address space gets managed on its own
- Helps in execution of large program when the main memory of the machine is of smaller size in comparison with program
Answer:
B decelerate
Explanation:
Deceleration will help in avoiding you from loosing control of the vehicle
Answer:
The answer is "Using the DoD 5220.22-M method and Degauss media with a magnet".
Explanation:
The "DoD Standard" is a term used during the data sanitizing industry and refers to DoD 5220.22-M. The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.
The sparging eliminates statistics to entirely delete the gravitational flux from electronic media. Hard drives as well as other data storage devices, for example, computer tapes, retain magnetic data. It could no longer be seen as storage after a disk is degaussed.
Sending potentially sensitive information by email
Potentially sensitive information can be sent via Email only if the Email is encrypted
Explanation:
No doubt Email is an inexpensive efficient means of communicating quickly. But it is prone to hacking and it is not a secure mechanism. In order to add security ,the Email needs to be sent in an encrypted form. Banking and HIPAA regulations require the emails to be sent in encrypted form as it is a secure mechanism. Even if one has the consent from the client , the Email has to be in encrypted. Even if the Organization's e-mail system has appropriate firewalls and related infrastructure , the golden rule is to send encrypted format Emails.
Answer:
CPU need 50% much faster
disk need 100% much faster
Explanation:
given data
workload spend time CPU = 60%
workload spend time I/O = 40%
achieve overall system speedup = 25%
to find out
How much faster does CPU need and How much faster does the disk need
solution
we apply here Amdahl’s law for the overall speed of a computer that is express as
S = 
.............................1
here f is fraction of work i.e 0.6 and S is overall speed i.e 100% + 25% = 125 % and k is speed up of component
so put all value in equation 1 we get
S =
1.25 = 
solve we get
k = 1.5
so we can say CPU need 50% much faster
and
when f = 0.4 and S = 125 %
put the value in equation 1
S =
1.25 = 
solve we get
k = 2
so here disk need 100% much faster
