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Murljashka [212]
1 year ago
15

5.William travels a lot on business purpose. He needs to regularly communicate with his business partner. He also needs to send

out weekly reports to his boss while he is travelling. Which web-based application best suits William's needs? ____________ is the best web-based application for William. He can access this application via the Internet using a _____________.
Computers and Technology
1 answer:
FromTheMoon [43]1 year ago
4 0

Microsoft Online is free to use. It includes Microsoft Excel, Word, One - Note and PowerPoint.  Microsoft Outlook (email app) is free as well, although it is a seperate download.

Another way to go is via Google docs, The Google drive is rather large and safe to store reports, docs, images, etc.

Both Microsoft online and Google Docs are accessible to use on virtually any device as in: PCs, Laptops, Tablets, Androids and Iphones.


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All the employees of Delta Corporation are unable to access the files stored in the server. What do you think is the reason behi
CaHeK987 [17]
C serve crash hope this is correct
5 0
1 year ago
Import java.util.scanner; public class sumofmax { public double findmax(double num1, double num2) { double maxval; // note: if-e
jeyben [28]

Here you go,


Import java.util.scanner

public class SumOfMax {

   public static double findMax(double num1, double num2) {

       double maxVal = 0.0;

       // Note: if-else statements need not be understood to

       // complete this activity

       if (num1 > num2) { // if num1 is greater than num2,

           maxVal = num1; // then num1 is the maxVal.

       }

       else { // Otherwise,

           maxVal = num2; // num2 is the maxVal.

       }

       return maxVal;

   }

   public static void main(String[] args) {

       double numA = 5.0;

       double numB = 10.0;

       double numY = 3.0;

       double numZ = 7.0;

       double maxSum = 0.0;

       /* Your solution goes here */

       maxSum = findMax(numA, numB); // first call of findMax

       maxSum = maxSum + findMax(numY, numZ); // second call

       System.out.print("maxSum is: " + maxSum);

       return;

   }

}

/*

Output:

maxSum is: 17.0

*/

6 0
2 years ago
Which phrase best describes a scenario in Excel 2016?
Airida [17]

Answer:

what are the phrases?

Explanation:

6 0
2 years ago
. Create a text file that contains your expenses for last month in the following categories: • Rent • Gas • Food • Clothing • Ca
Whitepunk [10]

Answer:

  1. from matplotlib import pyplot as plt
  2. with open("text.txt") as file:
  3.    data = file.readlines()
  4.    category = []
  5.    amount = []
  6.    for row in data:
  7.        values = row.split(" ")
  8.        category.append(values[0])
  9.        amount.append(float(values[1]))
  10.    
  11. figure = plt.figure()
  12. ax = figure.add_axes([0,0,1,1])
  13. ax.axis('equal')
  14. ax.pie(amount, labels = category, autopct='%1.2f%%')
  15. plt.show()

Explanation:

Firstly, we need to import matplotlib library (Line 1).

Next, open a file stream and use readlines method to read the data from the text file (Line 4). Presume the data read from the text files are as follows:

Rent 450

Gas 150

Food 500

Clothing 120

Car 600

Create two lists, category and amount (Line 5-6). Use a for loop to traverse through the read data and use split method to break each row of data into two individual items. The first item is added to category list whereas the second item is added to amount list (Line 7 - 10).

Next, create a plot figure and then add the axes (Line 12 - 13). We can use the pie method to generate a pie chart (Line 15) by setting the amount list as first argument and category list as value of labels attributes. The output pie chart can be found in the attachment.

7 0
2 years ago
Design a class named Person and its two subclasses named Student and Employee. Make Faculty and Staff subclasses of Employee. A
harina [27]

Answer:

se explaination

Explanation:

//Design a class named Person

public class Person

{

//A person has a name, address, phone number, and email address.

String name;

String address;

String phone;

String email;

//Constructor with arguments

public Person(String pname,String paddress,String phNum,String pemail)

{

name=pname;

address=paddress;

phone=phNum;

email=pemail;

}

// toString() method to return the name

public String toString()

{

return getClass().getName()+" "+name;

}

}

---------------------------------------------------------

//Student.java

public class Student extends Person

{

//A student has a class status

//(freshman,sophomore, junior, or senior).

//Define the status as a constant.

final int freshman =1;

final int sophomore =2;

final int junior=3;

final int senior=4;

String status="freshman";

//Constructor with arguments

public Student(String name, String address,String phonenumber, String email, int Status)

{

super(name,address,phonenumber,email);

if(Status == 1)

{

status = "freshman";

}

if(Status == 2)

{

status = "sophomore";

}

if(Status == 3)

{

status = "junior";

}

if(Status == 4)

{

status = "Senior";

}

status = "Student";

}

public String toString()

{

return super.toString() + " " + status;

}

}

------------------------------------------------------

//Employee.java

public class Employee extends Person

{

//An employee has an office, salary, and date hired.

String office;

double salary;

java.util.Date dateHired;

//Constructor with arguments

public Employee(String name,String address,String phonenumber,String email,String off,double sal)

{

super(name,address,phonenumber,email);

office=off;

salary=sal;

}

public String toString()

{

return (super.toString() + " " + office +" " + salary);

}

}

--------------------------------------------------------

//Faculty.java

public class Faculty extends Employee

{

//A faculty member has office hours and a rank.

String officeHours;

String rank;

//Constructor with arguments

public Faculty(String name,String address,String phonenumber,String email,String off,int salary,String offHours,String ranks)

{

super(name,address,phonenumber,email,off,salary);

officeHours=offHours;

rank=ranks;

}

public String toString()

{

return (super.toString() + " " + officeHours +" " + rank);

}

}

-----------------------------------------------------------------------------

//Staff.java

public class Staff extends Employee

{

//A staff member has a title

String title;

//Constructor with arguments

public Staff(String name,String address,String phonenumber,String email,String off,int salary,String ti t)

{

super(name,address,phonenumber,email,off,salary);

title=ti t;

}

public String toString()

{

return (super.toString() + " " + title);

}

}

3 0
2 years ago
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