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Lesechka [4]
2 years ago
14

In this problem, you will derive the efficiency of a CSMA/CD-like multiple access protocol. In this protocol, time is slotted an

d all adapters are synchronized to the slots. Unlike slotted ALOHA, however, the length of a slot (in seconds) is much less than a frame time (the time to transmit a frame). Let S be the length of a slot. Suppose all frames are of constant length L = kRS, where R is the transmission rate of the channel and k is a large integer. Suppose there are N nodes, each with an infinite number of frames to send. We also assume that dprop < s,="" so="" that="" all="" nodes="" can="" detect="" a="" collision="" before="" the="" end="" of="" a="" slot="" time.="" the="" protocol="" is="" as="">
⢠If, for a given slot, no node has possession of the channel, all nodes contend for the channel; in particular, each node transmits in the slot with probability p. If exactly one node transmits in the slot, that node takes possession of the channel for the subsequent k â 1 slots and transmits its entire frame.

If some node has possession of the channel, all other nodes refrain from transmitting until the node that possesses the channel has finished transmitting its frame. Once this node has transmitted its frame, all nodes contend for the channel.

Note that the channel alternates between two states: the productive state, which lasts exactly k slots, and the nonproductive state, which lasts for a random number of slots. Clearly, the channel efficiency is the ratio of k/(k + x), where x is the expected number of consecutive unproductive slots

a. For fixed N and p, determine the efficiency of this protocol.
b. For fixed N, determine the p that maximizes the efficiency.
c. Using the p (which is a function of N) found in (b), determine the efficiency as N approaches infinity
d. Show that this efficiency approaches 1 as the frame length becomes large
Computers and Technology
1 answer:
tatuchka [14]2 years ago
5 0

Answer:

He is correct

Explanation:

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AnnyKZ [126]

Answer: parallel processing

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alukav5142 [94]

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Enter a formula in cell G5 that calculates the difference between the attendance totals for 2018 and 2017. Copy the formula to t
Allushta [10]
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4 0
2 years ago
There is a function we are providing in for you in this problem called square. It takes one integer and returns the square of th
anastassius [24]

Answer:

xyz = 25  

result = square(xyz)

print(result)

The above code assigns the value 25 to variable xyz as 5*5=25. Then next statement is a function call to square() function passing xyz to this function in order to compute the square of 25. The output is:

625

Explanation:

The above code can also be written as:

xyz = 5*5

result = square(xyz)

print(result)

The difference is that xyz is assiged 5*5 which is equal to 25 so the output produced will be the same i.e.  625.

The result variable is used to store the value of square of 25 after the square() method computes and returns the square of 25. So print(result) prints the resultant value stored in the result variable i.e. 625

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2 years ago
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