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amm1812
2 years ago
5

Given x and y, each associated with an int, write a fragment of code that associates the larger of these with another variable n

amed max.
Computers and Technology
1 answer:
solmaris [256]2 years ago
8 0

Answer:

The program to this question as follows:

Program:

x=int(input('Input the first number: ')) #defining variable x and input value by user

y=int(input('Input the second number: ')) #defining variable y and input value by user

if x > y: #if block to check value x>y

   max=x #define variable max that hold variable x value

   print('max number is: ', x) #print value

else: #else block

   max=y  #define variable max that holds variable y value

   print('max number is: ', y) #print value

Output:

Input the first number: 22

Input the second number: 33

max number is:  33

Explanation:

In the above code two-variable, "x and y" is defined, which holds a value, which is input by the variable. In the next step, the if block statement is used that can be described as follows:

  • In the if block, it will check x is greater than y it will define a variable, that is "max", that holds variable x value and prints its value.
  • In the else block, if the above condition is false it uses the max variable, that holds variable y value and prints its value.
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Answer:

def print_pattern():

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"use the ______ element to create logical areas on a web page that are embedded within paragraphs or other block formatting elem
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Answer:

"use the span element to create logical areas on a web page that are embedded within paragraphs or other block formatting elements."

Explanation:

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5 0
2 years ago
You are given an array x of string elements along with an int variable n that contains the number of elements in the array. You
Slav-nsk [51]

Answer:

The code to this question can be given as:

Code:

int i,j,count_previous=0,count_next=0; //define variable

for (j=0; j<n; j++) //loop for array

{

if (x[0]==x[j]) //check condition

{

count_previous++; //increment value by 1.

}

}

for (i=0; i<n; i++) //loop

{

for (j=0; j<n; j++)

{

if (x[i]==x[j]) //check condition

{

count_next++; //increment value by 1.

}

}

if (count_previous>count_next) //check condition

{

mode=x[i-1];

}

else

{

mode=x[i];

count_previous=count_next; //change value.

count_next= 0 ; //assign value.

}

}

Explanation:

In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.

8 0
2 years ago
What is the area of a parallelogram whose vertices are A(−1, 12) , B(13, 12) , C(2, −5) , and D(−12, −5) ? Enter your answer in
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2 years ago
Read 2 more answers
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Answer:

Explanation:

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           }

       }

       

       return (min, max);

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