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Mars2501 [29]
2 years ago
7

(1) Prompt the user to enter five numbers, being five people's weights. Store the numbers in an array of doubles. Output the arr

ay's numbers on one line, each number followed by one space. (2 pts) Ex: Enter weight 1: 236.0 Enter weight 2: 89.5 Enter weight 3: 142.0 Enter weight 4: 166.3 Enter weight 5: 93.0 You entered: 236.0 89.5 142.0 166.3 93.0 (2) Also output the total weight, by summing the array's elements. (1 pt) (3) Also output the average of the array's elements. (1 pt) (4) Also output the max array element. (2 pts) Ex: Enter weight 1: 236.0 Enter weight 2: 89.5 Enter weight 3: 142.0 Enter weight 4: 166.3 Enter weight 5: 93.0 You entered: 236.0 89.5 142.0 166.3 93.0 Total weight: 726.8 Average weight: 145.35999999999999 Max weight: 236.0
Computers and Technology
1 answer:
Mashutka [201]2 years ago
6 0

Answer:

weights = []

total = 0

max = 0

for i in range(5):

   weight = float(input("Enter weight " + str(i+1) + ": "))

   weights.append(weight)

   total += weights[i]

   if weights[i] > max:

       max = weights[i]

average = total / 5

print("Your entered: " + str(weights))

print("Total weight: " + str(total))

print("Average weight: " + str(average))

print("Max weight: " + str(max))

Explanation:

Initialize the variables

Create a for loop that iterates 5 times

Get the values from the user

Put them inside the array

Calculate the total by adding each value to the total

Calculate the max value by comparing each value

When the loop is done, find the average - divide the total by 5

Print the results

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They can be used to compare a certain region before and after disaster.

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.Ten pounds of candy were prepared for the school party.
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There were 16 bags of lollipops and 17 of tootsie

Explanation:

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A drive is small enough to be carried in one's pocket.
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1 year ago
Jim is writing a program to calculate the wages of workers in a teddy bear factory.
34kurt

Answer:

The algorithm is as follows;

1. Start

2. Input TeddyBears

3. Input Hours

4. WagebyTeddy = 2 * TeddyBears

5. WagebyHour = 5 * Hours

6. If WagebyHour > WagebyTeddy then

6.1 Print WagebyHour

7. Else

7.1. Print WagebyTeddy

8. Stop

Explanation:

The following variables are used;

TeddyBears -> Number of teddy bears made

Hours -> Number of Hours worked

WagebyTeddy -> Wages for the number of teddy bears made

WagebyHour -> Wages for the number of hours worked

The algorithm starts by accepting input for the number of teddy bears and hours worked from the user on line 2 and line 3

The wages for the number of teddy bears made  is calculated on line 4

The wages for the number of hours worked  is calculated on line 5

Line 6 checks if wages for the number of hours is greated than wages for the number of bears made;

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3 0
2 years ago
Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating charac
elena-s [515]

Answer:

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate \lambda = 24 customers per hour or 0.4 customers per minute

Service rate \mu​ = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system , P0 = 1 - \lambda / \mu

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b.) The average number of customers waiting

Lq = \lambda^2 / [\mu(\mu - \lambda)] = 242 / [36 * (36 - 24)] = 1.33

c.) The average number of customers in the system.

L = Lq + \lambda / \mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = \lambda / [\mu(\mu - \lambda)] = 24 / [36 * (36 - 24)] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1/\mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667

3 0
2 years ago
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