Answer:
19.71 ms
Explanation:
The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.
Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms
Head movement time from track 8 to track 9 = seek time = 2 ms
rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms
The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms
An attribute of a website that will indicate a more reliable source of information is when the site ends in ".edu". It is a top-level domain for education. It would mean that this particular site is linked to universities, colleges or other educational sites thus it gives more information that is real and factual.
Answer:
Please check options are not given. Please check explanation for corrected version.
Explanation:
Options are not mentioned. Please post the complete question.
However, if "below" is removed, the question makes sense. I am taking it that way.
Dichotomous question means those questions which has two outcomes: true or false.
For the given condition, this is possible only if:
- coin shows head and dice shows 1
- coin shows head and dice shows 2
- head, 3
- head, 4
- head, 5
- head, 6
- tails, and all above cases
However, each time, each mentioned condition should be strictly followed.
And fewer outcome than 1 is virtually or realistically impossible, as both coin and dice will roll out one outcome in any condition certainly.
Solution :
class Employee:
#Define the
#constructor.
def __
__(
, ID_number, 
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict
I think select the video insert select the movie option under illustrations resize the video player then select the insert tab i’m not 100 percent sure tho
