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lions [1.4K]
2 years ago
8

Windows is displaying an error about incompatible hardware. You enter BIOS/UEFI setup to change the boot priority order so that

you can boot from the Windows setup DVD to troubleshoot the system. However, when you get to the Boot screen, you find that the options to change the boot priority order are grayed out and not available. What is most likely the problem?a. You signed in to BIOS/UEFI with the user power-on password rather than the supervisor power-on password.
b. A corrupted Windows installation does not allow you to make changes in BIOS/UEFI setup.
c. Motherboard components are malfunctioning and will not allow you to change BIOS/UEFI options.
d. The keyboard and mouse are not working.
Computers and Technology
1 answer:
Irina18 [472]2 years ago
4 0

Answer:

A

Explanation:

The most likely cause of the problem is that You signed in to BIOS/UEFI with the user power-on password rather than the supervisor power-on password. The User password only enables the machine to boot while the supervisor password allows entering the BIOS settings.

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Declare a struct named PatientData that contains two integer data members named heightInches and weightPounds. Sample output for
boyakko [2]

Answer:

struct PatientData{

   int heightInches, weightPounds;

};

Explanation:

In order to declare the required struct in the question, you need to type the keyword <em>struct</em>, then the name of the struct - <em>PatientData</em>, <em>opening curly brace</em>, data members - <em>int heightInches, weightPounds;</em>, <em>closing curly brace</em> and <em>a semicolon</em> at the end.

Note that since the object - lunaLovegood, is declared in the main function, we do not need to declare it in the struct. However, if it was not declared in the main, then we would need to write <em>lunaLovegood</em> between the closing curly brace and the semicolon.

8 0
2 years ago
A hotel salesperson enters sales in a text file. Each line contains the following, separated by semicolons: the name of the clie
timama [110]

Answer:

see explaination

Explanation:

Java code

//Header file section

import java.util.Scanner;

import java.io.*;

//main class

public class SalesTestDemo

{

//main method

public static void main(String[] args) throws IOException

{

String inFile;

String line;

double total = 0;

Scanner scn = new Scanner(System.in);

//Read input file name

System.out.print("Enter input file Name: ");

inFile = scn.nextLine();

FileReader fr = new FileReader(new File(inFile));

BufferedReader br = new BufferedReader(fr);

System.out.println("Name \t\tService_Sold \tAmount \tEvent Date");

System.out.println("=====================================================");

line = br.readLine();

//Each line contains the following, separated by semicolons:

//The name of the client, the service sold

//(such as Dinner, Conference, Lodging, and so on)

while(line != null)

{

String temp[] = line.split(";");

for(int i = 0; i < temp.length; i++)

{

System.out.print(temp[i]+"\t");

if(i == 1)

System.out.print("\t");

}

//Calculate total amount for each service category

total += Double.parseDouble(temp[2]);

System.out.println();

line = br.readLine();

}

//Display total amount

System.out.println("\nTotal amount for each service category: "+total);

}

}

inputSale.txt:

Peter;Dinner;1500;30/03/2016

Bill;Conference;100.00;29/03/2016

Scott;Lodging;1200;29/03/2016

Output:

Enter input file Name: inputSale.txt

Name Service_Sold Amount Event Date

=====================================================

Peter Dinner 1500 30/03/2016

Bill Conference 100.00 29/03/2016

Scott Lodging 1200 29/03/2016

Total amount for each service category: 2800.0

3 0
1 year ago
Let's assume that the smallest possible message is 64 bytes (including the 33-byte overhead). if we use 100base-t, how long (in
Ostrovityanka [42]

As we know that 10-bAse data travels at the rate of 10 mbps, therefore at 1 sec we have 10240 bytes.

We have to calculate for 64 bytes travelling in one second. Multiply both sides by 64.

64 sec = 10240 x 64 bytes

64 bytes = 64 / 10240 sec

Now we have to calculate for light of speed

1 sec = 186000 miles

Substitute this value to the formula above

64 bytes = 64 / 10240 x 1 sec = 64 / 10240 x 186000 miles = 64 / 10240 x 186000 x 5280 feet = 6138x10^3 feet

Therefore, 64 bytes is equal to 6138 x 10^3 feet long message

3 0
1 year ago
What is the output of 1101 x 10 == 11000 + 10?
Marta_Voda [28]
== is an operator that returns a boolean if both operand are equal.

1101 * 10 is 11010

11000 + 10 is 11010


11010 == 11010

Thus the output would be True.
5 0
1 year ago
3.14 LAB: Simple statistics for Python
Ad libitum [116K]

Answer:

Following are the correct python code to this question:

n1 = float(input('Input first number: '))#input first number  

n2 = float(input('Input second number: '))#input second number  

n3 = float(input('Input third number: '))#input third number  

n4 = float(input('Input fourth number: '))#input fourth number  

average = (n1+n2+n3+n4)/4 #calculate input number average

product = n1*n2*n3*n4 # calculate input number product

print('product: {:.0f}  average: {:.0f}'.format(round(product),round(average))) #print product and average using round function

print('product: {:.3f}  average: {:.3f}'.format(product,average)) #print product and average value

Output:

Please find the attachment.

Explanation:

The description of the above python code can be defined as follows:

  • In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
  • In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
  • In the last line, the print method is used, which prints its variable value by using a round and format method.

8 0
2 years ago
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