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Lesechka [4]
2 years ago
14

____ is a program placed on a computer without the user's knowledge that secretly collects information about the user

Computers and Technology
1 answer:
Scrat [10]2 years ago
7 0
<span>Spyware is a program placed on a computer without the user's knowledge that secretly collects information about the user.
</span><span>The spyware gathers information and can send this information to another program or entity which can take control over the device or use personal information to harm the user. </span>
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15. It is the process of capturing data or translating information to recording format
Helen [10]

Answer:

A Documentation, hope this helps.

5 0
2 years ago
Choose the correct function to convert the user’s response to the number 3.5. &gt;&gt;&gt; answer = input("How much does the sam
FromTheMoon [43]

Answer:

The answer to the given question is given bellow in the explanation section:

Explanation:

<p>This is python code</p>

<p>In python when you enter input into the input function as given:</p>

<code> answer = input("How much does the sample weigh in grams? ") </code>

I will be taken as string.

So I have to convert this string to number format here the given data is float value i-e 3.5

so let convert it. using float function.

<code> answer = float (input("How much does the sample weigh in grams? ") )  </code>

6 0
2 years ago
Read 2 more answers
Define a function ComputeGasVolume that returns the volume of a gas given parameters pressure, temperature, and moles. Use the g
lara [203]

Answer:

double ComputeGasVolume(double pressure, double temperature, double moles){

   double volume = moles*GAS_CONST*temperature/pressure;

    return volume;        

}

Explanation:

You may insert this function just before your main function.

Create a function called ComputeGasVolume that takes three parameters, pressure, temperature, and moles

Using the given formula, PV = nRT, calculate the volume (V = nRT/P), and return it.

6 0
2 years ago
This question involves the creation of user names for an online system. A user name is created based on a user’s first and last
Evgen [1.6K]

Answer:

See explaination

Explanation:

import java.util.*;

class UserName{

ArrayList<String> possibleNames;

UserName(String firstName, String lastName){

if(this.isValidName(firstName) && this.isValidName(lastName)){

possibleNames = new ArrayList<String>();

for(int i=1;i<firstName.length()+1;i++){

possibleNames.add(lastName+firstName.substring(0,i));

}

}else{

System.out.println("firstName and lastName must contain letters only.");

}

}

public boolean isUsed(String name, String[] arr){

for(int i=0;i<arr.length;i++){

if(name.equals(arr[i]))

return true;

}

return false;

}

public void setAvailableUserNames(String[] usedNames){

String[] names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

for(int i=0;i<usedNames.length;i++){

if(isUsed(usedNames[i],names)){

int index = this.possibleNames.indexOf(usedNames[i]);

this.possibleNames.remove(index);

names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

}

}

}

public boolean isValidName(String str){

if(str.length()==0) return false;

for(int i=0;i<str.length();i++){

if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

return false;

}

return true;

}

public static void main(String[] args) {

UserName person1 = new UserName("john","smith");

System.out.println(person1.possibleNames);

String[] used = {"harta","hartm","harty"};

UserName person2 = new UserName("mary","hart");

System.out.println("possibleNames before removing: "+person2.possibleNames);

person2.setAvailableUserNames(used);

System.out.println("possibleNames after removing: "+person2.possibleNames);

}

}

8 0
2 years ago
At which stage should James, a website designer, gather information about the website he wants to create, and at which stage sho
viva [34]
<h2>Answer: James should gather information in the <u><em>Learning</em></u> phase and begin the site’s coding in the <u><em>Development</em></u> phase.</h2>

8 0
2 years ago
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