<u>Answer:</u>
<em>int fNumber,scndNumber = -1, </em>
<em>dup = 0;
</em>
<em>do {
</em>
<em>cin >> fNumber;
</em>
<em>if ( scndNumber == -1) {
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>else {
</em>
<em>if ( scndNumber == fNumber )
</em>
<em>duplicates++;
</em>
<em>else
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>} while(fNumber > 0 ); </em>
<em>cout << dup;
</em>
<u>Explanation:</u>
Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>
<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.
Answer:
Uneven use of resources
Explanation:
Potential problem associated with supporting multi - user operation without hardware support is:
Uneven use of resources: In a situation where we assign a set of resources to user 1 and if a new user comes, then it would be difficult to allocate new resources to him. The processor would get confused between the two users. And the tasks would not be completed. This can affect task processing.
Answer:
public class GetInfo{
Beverage[] beverages=new Beverage[100];
int i=0;
GetInfo(Beverage b){
beverages[i]=b;
i++;
}
public void Display(){
for(int i=0;i<beverages.length;i++)
cout<<beverage[i].tostring();
}
Explanation:
we are taking Beverages array to store all values and in constructor we are adding that to the list and Display() function prints the vale
