Answer:
The minimum number of bits necessary to address 8K words is 13.
Explanation:
You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.
8000 words can be addressed with
units. Now you have to find the value of n that approximates to the number of words.
So you can see that 13 bits are needed to address 8K words.
<span>When you examine a computer chip under a microscope, you will see </span>integrated circuits.
Maturity Stage – During the maturity stage, the product is established and the aim for the manufacturer is now to maintain the market share they have built up. This is probably the most competitive time for most products and businesses need to invest wisely in any marketing they undertake. They also need to consider any product modifications or improvements to the production process which might give them a competitive advantage. i think this would be the best time for the company to purchase an emerging technology.
Answer:
The description for the given question is described in the explanation section below.
Explanation:
Depending on the needs of the device programmers these OS have various locking frameworks. Spinlocks become beneficial for preemptive multitasking processes during which a thread will operate in such an active loop instead of risking a rest queue latency. Mutexes become beneficial to utility lockers.
- Solaris 2 employs flexible mutexes, indicating something like this on preemptive multitasking computers, the mutex is introduced with either a spinning switch.
- Semaphores and state variations are much more effective methods for consistency where a commodity needs to be managed for such a prolonged period of time because spinning is unstable over a prolonged time.
In java...
public boolean checkSquare(int n){
int actualNumber = n;
int squareRoot = (int)Math.sqrt(n);
int squaredNumber = Math.pow(squareRoot,2);
if(squaredNumber==actualNumber){
return true;
} else {
return false;
}
}