Write a MATLAB function named lin_spaced_vector with two inputs and one return value. The first input will be a single real numb
er representing a lower bound The second input will be a single real number representing an upper bound The return value must be a list of 200 numbers evenly spaced between the lower bound and the upper bound.
1 answer:
Explanation:
==================
lin_spaced_vector.m
==================
function out=lin_spaced_vector(in1,in2)%defining function
out=linspace(in1,in2,200);%200 spaced numbers between in1 and in2
end
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Executable File
===================
clear all%clears history
clc%clears screen
lin_spaced_vector(1,10)%calling function
clear all
clc
lin_spaced_vector(1,10)
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Answer:
This is your corrected code and the output of each test example. I have also added comments with the provided code to make the code understandable. I have also changed itype variable to from int to String in order to print the account type (Savings or Checking) in output.
import java.util.*;
public class bank{ //class name
public static void main (String [] args) //start of main function body
{int num,error=1; //declare variables
String itype=" "; //stores Checking or Savings account type
char type =0; //type variable which is one of savings S or checking C
double min,cur =0,balance =0,rate=0;
//declare variables for minimum balance, current balance, interest rate
Scanner in=new Scanner(System.in);
System.out.println("Enter account number: "); //prompts user to enter acc no
num=in.nextInt(); //reads input account number
while(error==1) {
//asks user to enter account type C or S
System.out.println("Enter account type(s-savings or c-checking):");
type=in.next().charAt(0); //reads the input character of account type
if(type=='c'||type=='C') //if user inputs c or C
{itype= "Checking"; //set itype to Checking when user input c or C
error=0; //set value of error to 0 means user entered valid type input
rate=3/100.; } // Savings accounts receives 3% interest
else if(type=='s'||type=='S') //if user enters S or s that shows Savings account
{itype= "Savings"; //set itype to Savings when user input s or S
error=0; //set error to 0 means there is no error
rate=4/100.; } //Savings accounts receives 4% interest
if(error==1) //in case of error in giving input
System.out.println("Invalid type-re enter"); } //asks user to input again
System.out.println("Enter minimum balance: "); //asks user to enter min bal
min=in.nextDouble(); //reads value of input minimum balance
System.out.println("Enter current balance: ");
// reads value of input current balance
cur=in.nextDouble();
balance = cur;
if(itype=="Checking") //if the account type is checking
{ if(cur>min+5000) //Checking accounts interest is 5%
{rate=5/100.;
cur=cur+rate*cur; //computes new balance
System.out.printf("New balance: $%.2f\n", cur);} //returns new balance value
/*If a customer’s balance falls below the minimum balance, there is a service charge of $25.00 for checking accounts */
else if(cur<min)
{cur-=25;
System.out.printf("New balance: $%.2f\n", cur);} returns the value of new
}
if(itype=="Savings"){ //if account type is Savings
/*If a customer’s balance falls below the minimum balance, there is a service charge of $10.00 for savings accounts */
if(cur<min)
{cur-=10;
System.out.printf("New balance: $%.2f\n", cur);}
else
//Savings accounts receive 4% interest
{cur=cur+rate*cur;
System.out.printf("New balance: $%.2f\n", cur);}}
/* as the program should output account number, account type, current balance, and new balance so i have commented out the extra print statements below */
//System.out.printf("After interest and fees your balance is = $%.2f\n",cur);
System.out.println("Account Number: " + num);
System.out.println("Account type: " + itype);
System.out.printf("Current balance: $%.2f\n ", balance); //the result is //displayed up to 2 decimal place .2f } }
Explanation:
Following is the output of each test example:
46728 S 1000 2700
Account Number: 46728
Account type: Savings
Current balance: $2700.00
New balance: $2808.00
87324 C 1500 7689
Account Number: 87324
Account type: Checking
Current balance: $7689.00
New balance: $8073.45
79873 S 1000 800
Account Number: 79873
Account type: Savings
Current balance: $800.00
New balance: $790
89832 C 2000 3000
Account Number: 89832
Account type: Checking
Current balance: $3000.00
New balance: $3090.00
98322 C 1000 750
Account Number: 98322
Account Type: Checking
Current balance: $1000.00
New Balance: $725.00
Answer:
The question given is incomplete as it does not contains the image. I have found the image of the question and it is attached below.
The solution of the question is also attached below in the image.
I hope it will help you!
Explanation:
