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Scrat [10]
2 years ago
7

Write a MATLAB function named lin_spaced_vector with two inputs and one return value. The first input will be a single real numb

er representing a lower bound The second input will be a single real number representing an upper bound The return value must be a list of 200 numbers evenly spaced between the lower bound and the upper bound.

Computers and Technology
1 answer:
ycow [4]2 years ago
4 0

Explanation:

==================  

lin_spaced_vector.m  

==================  

function out=lin_spaced_vector(in1,in2)%defining function

out=linspace(in1,in2,200);%200 spaced numbers between in1 and in2

end​

===================  

Executable File

===================

clear all%clears history

clc%clears screen

lin_spaced_vector(1,10)%calling function​

clear all

clc

lin_spaced_vector(1,10)

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Modify the TimeSpan class from Chapter 8 to include a compareTo method that compares time spans by their length. A time span tha
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Answer:

Check the explanation

Explanation:

Here is the modified code for

TimeSpan.java and TimeSpanClient.java.

// TimeSpan.java

//implemented Comparable interface, which has the compareTo method

//and can be used to sort a list or array of TimeSpan objects without

//using a Comparator

public class TimeSpan implements Comparable<TimeSpan> {

   private int totalMinutes;

   // Constructs a time span with the given interval.

   // pre: hours >= 0 && minutes >= 0

   public TimeSpan(int hours, int minutes) {

        totalMinutes = 0;

        add(hours, minutes);

   }

   // Adds the given interval to this time span.

   // pre: hours >= 0 && minutes >= 0

   public void add(int hours, int minutes) {

        totalMinutes += 60 * hours + minutes;

   }

   // Returns a String for this time span such as "6h15m".

   public String toString() {

        return (totalMinutes / 60) + "h" + (totalMinutes % 60) + "m";

   }

   // method to compare this time span with other

   // returns a negative value if this time span is shorter than other

   // returns 0 if both have same duration

   // returns a positive value if this time span is longer than other

   public int compareTo(TimeSpan other) {

        if (this.totalMinutes < other.totalMinutes) {

            return -1; // this < other

        } else if (this.totalMinutes > other.totalMinutes) {

            return 1; // this > other

        } else {

            return 0; // this = other

        }

   }

}

// TimeSpanClient.java

public class TimeSpanClient {

   public static void main(String[] args) {

        int h1 = 13, m1 = 30;

        TimeSpan t1 = new TimeSpan(h1, m1);

        System.out.println("New object t1: " + t1);

        h1 = 3;

        m1 = 40;

        System.out.println("Adding " + h1 + " hours, " + m1 + " minutes to t1");

        t1.add(h1, m1);

        System.out.println("New t1 state: " + t1);

        // creating another TimeSpan object, testing compareTo method using the

        // two objects

        TimeSpan t2 = new TimeSpan(10, 20);

        System.out.println("New object t2: " + t2);

        System.out.println("t1.compareTo(t2): " + t1.compareTo(t2));

        System.out.println("t2.compareTo(t1): " + t2.compareTo(t1));

        System.out.println("t1.compareTo(t1): " + t1.compareTo(t1));

   }

}

/*OUTPUT*/

New object t1: 13h30m

Adding 3 hours, 40 minutes to t1

New t1 state: 17h10m

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t1.compareTo(t2): 1

t2.compareTo(t1): -1

t1.compareTo(t1): 0

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2 years ago
This program finds the sum and average of three numbers. What are the proper codes for Lines a and b?
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Answer:

The Proper codes in Line a and Line b is given below

average=Sum/3  

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Explanation:

In the given question it calculated the sum but the program does not calculate the average of the 3 numbers.The average of the 3 number is calculated by using average=Sum/3   statement so we add this code in Line a then After that print the value of average by using the print function so we add this code in Line b.

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For drivers under 21, the penalties for driving with an illegal BAL include _____.
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Answer:

void showSeatingChart(const string [][COLS], int);

Explanation:

void showSeatingChart(const string [][COLS], int);

The above function showSeatingChart() will display the 2D array of seating chart.

The return type of this function is void because it does not need to retun anything.

The parameter of the function is a 2D array which is seatingChart[ROWS][COLS].

The type of this 2D array is string that means it is a 2D array of string. It will contain string elements.

To declare a prototype of a function, there should be a semi-colon (;) at the end of declaration.

The definition of the function should be given outside main() function and declaration of the function should be above the main() function or at the beginning of the program with declaration of constant variables.

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2 years ago
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int) You are the head of a division of a big Silicon Valley company and have assigned one of your engineers, Jim, the job of dev
sergeinik [125]

Answer:

Correct option is E

Explanation:

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Thus, number of operations for a text with n=10 words is 2\cdot 10^2+2^{10}=1224 operation

Each operation takes one nanosecond, so we need 1224 nanoseconds for Jim's algorithm

b) If n=50, number of operations required is 2\cdot 50^2+2^{50}\approx 1.12589990681\times 10^{15}

To amount of times required is 1.12589990681\times 10^{15} nanoseconds which is

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The time in seconds, our algortihm runs is \frac{1125899.90685}{24\cdot 60\cdot 60}=13.0312 days

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c) In this case, computing order of number of years is more important than number of years itself

We note that n=100 so that 2(100)^2+2^{100}\approx 1.267650600210\times 10^{30} operation (=time in nanosecond)

Which is 1.267650600210\times 10^{21} seconds

So that the time required is 1.4671881947\times 10^{16} days

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\frac{1.4671881947\times 10^{16}}{365}=4.0197\times 10^{13} years

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