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Scrat [10]
1 year ago
7

Write a MATLAB function named lin_spaced_vector with two inputs and one return value. The first input will be a single real numb

er representing a lower bound The second input will be a single real number representing an upper bound The return value must be a list of 200 numbers evenly spaced between the lower bound and the upper bound.

Computers and Technology
1 answer:
ycow [4]1 year ago
4 0

Explanation:

==================  

lin_spaced_vector.m  

==================  

function out=lin_spaced_vector(in1,in2)%defining function

out=linspace(in1,in2,200);%200 spaced numbers between in1 and in2

end​

===================  

Executable File

===================

clear all%clears history

clc%clears screen

lin_spaced_vector(1,10)%calling function​

clear all

clc

lin_spaced_vector(1,10)

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Design an application for Bob's E-Z Loans. The application accepts a client's loan amount and monthly payment amount. Output the
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Answer:

part (a).

The program in cpp is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   std::cout << "Loan balance: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>0)

   {

       if(balance<payment)    

         { payment = balance;}

       else

       {  

           std::cout << balance <<"\t\t\t"<< payment << std::endl;

           balance = balance - payment;

       }

   }

   return 0;

}

part (b).

The modified program from part (a), is given below.

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   //variables to hold balance and monthly payment amounts

   double balance;

   double payment;

   double charge=0.01;

   //user enters balance and monthly payment amounts

   std::cout << "Welcome to Bob's E-Z Loans application!" << std::endl;

   std::cout << "Enter the balance amount: ";

   cin>>balance;

   std::cout << "Enter the monthly payment: ";

   cin>>payment;

   balance = balance +( balance*charge );

   std::cout << "Loan balance with 1% finance charge: " <<" "<< "Monthly payment: "<< std::endl;

   //balance amount and monthly payment computed

   while(balance>payment)

   {

           std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

           balance = balance +( balance*charge );

           balance = balance - payment;

       }

   if(balance<payment)    

         { payment = balance;}          

   std::cout << balance <<"\t\t\t\t\t"<< payment << std::endl;

   return 0;

}

Explanation:

1. The variables to hold the loan balance and the monthly payment are declared as double.

2. The program asks the user to enter the loan balance and monthly payment respectively which are stored in the declared variables.  

3. Inside a while loop, the loan balance and monthly payment for each month is computed with and without finance charges in part (a) and part (b) respectively.

4. The computed values are displayed for each month till the loan balance becomes zero.

5. The output for both part (a) and part (b) are attached as images.

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2 years ago
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(Very interesting question you had. Hope this answer helps)

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Because this is a on your own problem, it cannot be solved. You must speak to it after the person says something.

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Answer is productivity

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3.14 LAB: Simple statistics for Python
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Answer:

Following are the correct python code to this question:

n1 = float(input('Input first number: '))#input first number  

n2 = float(input('Input second number: '))#input second number  

n3 = float(input('Input third number: '))#input third number  

n4 = float(input('Input fourth number: '))#input fourth number  

average = (n1+n2+n3+n4)/4 #calculate input number average

product = n1*n2*n3*n4 # calculate input number product

print('product: {:.0f}  average: {:.0f}'.format(round(product),round(average))) #print product and average using round function

print('product: {:.3f}  average: {:.3f}'.format(product,average)) #print product and average value

Output:

Please find the attachment.

Explanation:

The description of the above python code can be defined as follows:

  • In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
  • In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
  • In the last line, the print method is used, which prints its variable value by using a round and format method.

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2 years ago
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