Answer:
4-Well first of all for the "VR" problem it could be a problem, because people could forget about there actual life and not be able to much of anything when needed.
1-the first one you are going to have to answer.
2-If you have different files then you aren't stumbling through multiple different links and could have trouble with finding what is needed.
3-the third one you are going to have to answer.
5-If I were you I would help them the best way you could so they can actually know how to do their job.
The answer is B: Yahoo! mail
Donna is able to install Yahoo! mail as an app on her portable devices like phones and tablets and be able to organize her Google mails, Outlook, and yahoo accounts. The beauty of it is that you are able to sign in with any account (non-Yahoo emails). anywhere and at any time. It also provides 1000 GB of free secure cloud storage.
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
Answer: setJMenubar
Explanation:Menus that are component of the Menu bar that display the options and tools for any function that can be performed in the system have the connection with the window in the field of java through the command of the setJMenubar. It is the command which is given to execute to bring the menu to the particular frame and get it attached according to the JFrame. Therefore, the correct option is setJMenubar.
Answer:
Please check options are not given. Please check explanation for corrected version.
Explanation:
Options are not mentioned. Please post the complete question.
However, if "below" is removed, the question makes sense. I am taking it that way.
Dichotomous question means those questions which has two outcomes: true or false.
For the given condition, this is possible only if:
- coin shows head and dice shows 1
- coin shows head and dice shows 2
- head, 3
- head, 4
- head, 5
- head, 6
- tails, and all above cases
However, each time, each mentioned condition should be strictly followed.
And fewer outcome than 1 is virtually or realistically impossible, as both coin and dice will roll out one outcome in any condition certainly.
