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Scrat [10]
2 years ago
7

Write a MATLAB function named lin_spaced_vector with two inputs and one return value. The first input will be a single real numb

er representing a lower bound The second input will be a single real number representing an upper bound The return value must be a list of 200 numbers evenly spaced between the lower bound and the upper bound.

Computers and Technology
1 answer:
ycow [4]2 years ago
4 0

Explanation:

==================  

lin_spaced_vector.m  

==================  

function out=lin_spaced_vector(in1,in2)%defining function

out=linspace(in1,in2,200);%200 spaced numbers between in1 and in2

end​

===================  

Executable File

===================

clear all%clears history

clc%clears screen

lin_spaced_vector(1,10)%calling function​

clear all

clc

lin_spaced_vector(1,10)

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rite a method so that the main() code below can be replaced by simpler code that calls method calcMilesTraveled(). Original main
weeeeeb [17]

Complete Question

Write a method so that the main() code below can be replaced by the simpler code that calls method calcMiles() traveled.

Original main():

public class Calcmiles {

public static void main(string [] args) {

double milesperhour = 70.0;

double minutestraveled = 100.0;

double hourstraveled;

double milestraveled;

hourstraveled = minutestraveled / 60.0;

milestraveled = hourstraveled * milesperhour;

System.out.println("miles: " + milestraveled); } }

Answer:

import java.util.Scanner;

public class CalcMiles

{

public double CalculateMiles (double miles, double minutes)

{ //Method CalculateMiles defined above

//Declare required variables.

double hours = 0.0;

double mile = 0.0;

//Calculate the hours travelled and miles travelled.

hours = minutes / 60.0;

mile = hours * miles;

//The total miles travelled in return.

return mile;

}

public static void main(String [] args)

{

double milesPerHour = 70.0;

double minsTravelled = 100.0;

CalculateMiles timetraveles = new CalculateMiles();

System.out.println("Miles: " + timetravels.CalculateMiles(milesPerHour, minsTraveled));

}

}

//End of Program

//Program was written in Java

//Comments are used to explain some lines

Read more on Brainly.com - brainly.com/question/9409412#readmore

7 0
2 years ago
Which mechanisms do we use to transport binary data and memory addresses?
Sav [38]

Answer:

The External Data Bus  is used to transport binary data and Address bus is used to transport memory addresses.

Explanation:

  • External Data Bus is a combination of data bus and external bus. Data bus is used to carry data and instructions between two or more components in the system e.g. CPU and all other computer components.
  • External bus is also called expansion bus. It is used to connect external components to the computer. Its a communication medium between CPU and other components. These components can be peripheral device like USB or flash memory.
  • So External Data Bus is used to transport data between CPU and external components. It is a primary communication pathway for data in a computer. The external data components are connected to this bus and the instruction or data on this bus is available to all external components. But the data communication is slower as compared to that of internal bus.
  • Address Bus carries physical location or address of data and transports memory addresses. Processor uses address bus when it wants to read data from memory or write data to the memory by sending a read/write signal by placing the read/write address of the specific memory location on the address bus.

 

6 0
2 years ago
What is the argument in this function =AVERAGE(F3:F26)
monitta
The argument for the function would be answer "D".
5 0
2 years ago
Given an n-element array X, algorithm D calls algorithm E on each element X[i]. Algorithm E runs in O(i) time when it is called
krek1111 [17]

Answer:

O(n^2)

Explanation:

The number of elements in the array X is proportional to the algorithm E runs time:

For one element (i=1) -> O(1)

For two elements (i=2) -> O(2)

.

.

.

For n elements (i=n) -> O(n)

If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)  

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2 years ago
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svp [43]

Answer:

Explanation:

import java.Util;

public class Eggs{

public static void main (String [] args)

{

int noOfEggs, dozen, units;

float total;

Scanner input = new Scanner(System.in);

noOfEggs = input.nextInt();

if(noOfEggs < 0)

{

System.out.print("Invalid");

}

else

{

if(noOfEggs >= 12)

{

dozen = noOfEggs/12;

units = noOfEggs % 12;

}

else

{

dozen = 0;

units = noOfEggs;

}

total = dozen * 3.25 + (units * 45)/100;

System.out.print("You ordered "+noOfEggs+" eggs.\n");

System.out.print("That's "+dozen+" dozen at $3.25 per dozen and "+units+" loose eggs at 45 cents each for a total of $"+total);

}

}

}

7 0
2 years ago
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