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givi [52]
2 years ago
12

Write a program that calculates taxi fare at a rate of $1.50 per mile. Your pro-gram should interact with the user in this manne

r:TAXI FARE CALCULATOREnter beginning odometer reading=> 78602.5Enter ending odometer reading=> 78622.7You traveled a distance of 20.2 miles. At $1.50 per mile,your fare is $30.30.
Computers and Technology
1 answer:
NISA [10]2 years ago
8 0

Answer:

print("TAXI FARE CALCULATOR\n")

beginning = float(input("Enter beginning odometer reading => "))

ending = float(input("Enter ending odometer reading => "))

distance = ending - beginning

fare = 1.50 * distance

print("You traveled a distance of %.1f" % distance + " miles. At $1.50 per mile, your fare is $ %.2f" % fare)

Explanation:

*The code is in Python.

Print the title

Ask the user to enter beginning and ending of the odometer reading. Calculate the distance by subtracting these values

Calculate the fare, multiply the distance by 1.50

Print the distance and fare in required format

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A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen
Nina [5.8K]

Answer:

C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

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Suppose you are given an unknown chip which could be any one of the of the following: 7400, 7402, 7404, 7408, 7410, 7420, 7427,
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Tyler wants to upgrade his very old operating system to the latest mac or microsoft operating system, but he cannot seem to inst
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Create a list words = ['is', 'NLP', 'fun', '?']. Use a series of assignment statements (e.g. words[1] = words[2]) and a temporar
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Answer:

words = ['is', 'NLP', 'fun', '?']

tmp = words[1]

words[1] = words[0]

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