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sleet_krkn [62]
2 years ago
7

A two-dimensional array can have elements of ________ data type(s).

Computers and Technology
1 answer:
Igoryamba2 years ago
4 0
The answer is "One". The number of dimensions is the representation of the array and has nothing to do with the data types the array can contain.

All array's can only hold one data type, the type it was initialized with.
You might be interested in
Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:
horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed.  So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

          = 0.00833 * 100

          = 0.833 ms

So there is  1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d)  Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0
1 year ago
JAVA Write a program that first asks the user to type a letter grade and then translates the letter grade into a number grade. L
ale4655 [162]

Answer:

Follows are the code to this question:

import java.util.*;//import package for user input

class GradePrinter//defining class GradePrinter

{

double numericValue = 0;//defining double variable

String grade = "";//defining String variable

GradePrinter()//defining default constructor  

{

Scanner xb = new Scanner(System. in );//defining Scanner  class object

System.out.print("Enter Grade: ");//print message

grade = xb.nextLine();//input string value  

}

double getNumericGrade()//defining double method getNumericGrade

{

if (grade.equals("A+") || grade.equals("A"))//defining if block that check input is A+ or A

{

numericValue = 4.0;//using  numericValue variable that hold float value 4.0

}

else if (grade.equals("A-"))//defining else if that check grade equals to A-

{

numericValue = 3.7;//using  numericValue variable that hold float value 3.7

}

else if (grade.equals("B+"))//defining else if that check grade equals to B-

{

numericValue = 3.3;//using  numericValue variable that hold float value 3.3

}

else if (grade.equals("B"))//defining else if that check grade equals to B

{

numericValue = 3.0;//using  numericValue variable that hold float value 3.0

}

else if (grade.equals("B-"))//defining else if that check grade equals to B-  

{

numericValue = 2.7;//using  numericValue variable that hold float value 2.7

}

else if (grade.equals("C+"))//defining else if that check grade equals to C+  

{

numericValue = 2.3; //using  numericValue variable that hold float value 2.3

}

else if (grade.equals("C")) //defining else if that check grade equals to C  

{

numericValue = 2.0; //using numericValue variable that hold float value 2.0

}

else if (grade.equals("C-")) //defining else if that check grade equals to C-  

{

numericValue = 1.7;//using umericValue variable that hold float value 1.7

}

else if (grade.equals("D+"))//defining else if that check grade equals to D+  

{

numericValue = 1.3;//using umericValue variable that hold float value 1.3

}

else if (grade.equals("D"))//defining else if that check grade equals to D

{

numericValue = 1.0;//using umericValue variable that hold float value 1.0

}

else if (grade.equals("F"))//defining else if that check grade equals to F

{

numericValue = 0;//using umericValue variable that hold value 0

}

else//defining else block

{

System.out.println("Letter not in grading system");//print message

}

return numericValue;//return numericValue

}

}

class Main//defining a class main

{

public static void main(String[] args)//defining main method

{

GradePrinter ob = new GradePrinter();// creating class GradePrinter object

double numericGrade = ob.getNumericGrade();//defining double variable numericGrade that holds method Value

System.out.println("Numeric Value: "+numericGrade); //print Value numericgrade.

}

}

Output:

Enter Grade: B

Numeric Value: 3.0

Explanation:

In the above-given code, a class "GradePrinter" is defined inside the class a string, and double variable "grade and numericValue" is defined, in which the grade variable is used for input string value from the user end.

After input, the sting value a method getNumericGrade is defined, which uses multiple conditional statements is used, which holds double value in the which is defined in the question.

In the main class, the "GradePrinter" object is created and defines a double variable "numericGrade", that calling method and store its value, and also use print method to print its value.

4 0
2 years ago
Design a BCD-to-Gray code decoder. Your decoder will have 4 inputs: A, B, C and D, representing a 4-bit BCD code (A being the MS
ra1l [238]

Answer:

Binary to Gray Code Converter

The logical circuit which converts the binary code to equivalent gray code is known as binary to gray code converter. An n-bit gray code can be obtained by reflecting an n-1 bit code about an axis after 2n-1 rows and putting the MSB (Most Significant Bit) of 0 above the axis and the MSB of 1 below the axis.

The 4 bit binary to gray code conversion table is given in attached file.

3 0
1 year ago
Read 2 more answers
Each frame is composed of a number of colors recorded in digital format; we call these pixels. What information does the number
Nookie1986 [14]
I'd say the size of the frame.

The size, quantity and color combination of pixels is measured in terms of display resolution. A resolution, however, is the number of pixels in an image and is identified by the width and the height. How you’ve set the resolution for the display screen will determine the specific size of the pixels.






7 0
2 years ago
You resurrected an old worksheet. It appears to contain most of the information that you need, but not all of it. Which step sho
shtirl [24]

Answer:

a)

Explanation:

Since the worksheet contains most of the data that you need, there is a decent possibility that it also contains the data that you are missing. Therefore, you should check for data you have previously hidden. Sometimes, some data in a worksheet may become irrelevant in a given moment, and instead of deleting it since it may be useful later most people tend to make that data hidden. So checking for previously hidden data may be the best solution in this scenario.

7 0
1 year ago
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