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ira [324]
2 years ago
9

Match the following technologies with their applications.

Computers and Technology
1 answer:
kap26 [50]2 years ago
7 0

Answer:

3d printing

Explanation:

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Design a GUI program to find the weighted average of four test scores. The four test scores and their respective weights are giv
Alexus [3.1K]

<u>Answer:</u>

I am writing <em>partial code in</em> <em>c++ to calculate weighted average</em>. The weighted average should be calculated based on multiplying the test score and its <em>respective weight and finally add all the test score.</em>

<u>Explanation:</u>

<em>int arrtestscore[100];</em>

<em>int arrweight[100];</em>

<em>int n;</em>

<em>double weightedavg;</em>

<em>cout<<”Enter the number of test score for which weighted average needs to be calculated”;</em>

<em>cin>>n;</em>

<em>for(int x = 0; x <n;x++)</em>

<em>{</em>

<em> cout<<”Enter test score :” + (x+1) ;</em>

<em> cin>>arrtestscore[x];</em>

<em> count<<”Enter the respective weight:”;</em>

<em> cin>>arrweight[x];</em>

<em>}</em>

<em>for (int i=0; i<n;i++)</em>

<em>{</em>

<em> weightedavg = weightedavg + (arrtestscore[i] * arrweight[i])</em>

<em>}</em>

<em>cout<<”weighted average = “ <<weightedavg; </em>

3 0
1 year ago
Write a copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *thi
Olin [163]

The following cose will be used to copy assignment operator for CarCounter

<u>Explanation:</u>

Complete Program:

#include <iostream>

using namespace std;

class CarCounter

{

public:

CarCounter();

CarCounter& operator=(const CarCounter& objToCopy);

void SetCarCount(const int setVal)

{

 carCount = setVal;

}

int GetCarCount() const

{

 return carCount;

}

private:

int carCount;

};

CarCounter::CarCounter()

{

carCount = 0;

return;

}

// FIXME write copy assignment operator

/* Your solution goes here */

CarCounter& CarCounter::operator=(const CarCounter& objToCopy)

{

if(this != &objToCopy)

 carCount = objToCopy.carCount;

return *this;

}

int main()

{

CarCounter frontParkingLot;

CarCounter backParkingLot;

frontParkingLot.SetCarCount(12);

backParkingLot = frontParkingLot;

cout << "Cars counted: " << backParkingLot.GetCarCount();

cout << endl << endl;

system("pause");

return 0;

}

5 0
2 years ago
Consider a disk that rotates at 3600 rpm. The seek time to move the head between adjacent tracks is 2 ms. There are 32 sectors p
jasenka [17]

Answer:

19.71 ms

Explanation:

The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.

Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms

Head movement time from track 8 to track  9 = seek time = 2 ms

rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms

The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms

3 0
1 year ago
+10 points~~~Which option is used in emails to inform the recipient that they should exercise discretion in accordance with shar
Alexxx [7]

Answer:

Sensitivity Levels

Explanation:

Sensitivity Level is option use in email to inform the recipient that they should exercise discretion in accordance with sharing the content of the message.

8 0
2 years ago
Which of the following best reflects why lighting systems are used when filming on location outdoors? (Select all that apply.)
cupoosta [38]
<h2>All the given answers are right</h2>

Explanation:

  • Lighting is one of the key factor which is essential to do cinematography
  • It will help to cut off the shadows that is created using natural light
  • It can depict the mood of the scene that is shoot
  • We can adjust manually brightness and darkness according to the need, which is not possible in the natural light.
  • It can boost the quality of the footage
  • We can shoot anytime irrespective of the weather condition
  • The light from the camera alone is not enough to shoot the best picture
8 0
1 year ago
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