Answer:
Binary to Gray Code Converter
The logical circuit which converts the binary code to equivalent gray code is known as binary to gray code converter. An n-bit gray code can be obtained by reflecting an n-1 bit code about an axis after 2n-1 rows and putting the MSB (Most Significant Bit) of 0 above the axis and the MSB of 1 below the axis.
The 4 bit binary to gray code conversion table is given in attached file.
Answer:
Since the attack impacts the client SANS Critical Security Controls. This act affects the Inventory of authorized and unauthorized software running on the victim's machine.
Answer:
True.
Explanation:
An expression containing the && and operator is only true if both of the operands present in the expression are true otherwise it will give the result as false if either one of them is false or both of them are false.In the question it states that the expression in true either or both of it's operand are true.
Hence the answer is true.
Additional resource needed for the projects
Additional time needed for the project
<u>Explanation:</u>
In any project handing their will expected diversion and add on requirement, so to complete a project additional time and additional resource is required to finish a project.
As advice due the project details, end user has keep enough buffer for deviations on resource of man power and additional times taken to finish the project.
While design the project each scope of work is measure with additional time to complete the task
Each scope of work is considered as task in project management.
Answer:
Explanation:
import java.util.Scanner;
public class KboatTriangleAngle
{
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
System.out.print("Enter first angle: ");
int a1 = in.nextInt();
System.out.print("Enter second angle: ");
int a2 = in.nextInt();
System.out.print("Enter third angle: ");
int a3 = in.nextInt();
int angleSum = a1 + a2 + a3;
if (angleSum == 180 && a1 > 0 && a2 > 0 && a3 > 0) {
if (a1 < 90 && a2 < 90 && a3 < 90) {
System.out.println("Acute-angled Triangle");
}
else if (a1 == 90 || a2 == 90 || a3 == 90) {
System.out.println("Right-angled Triangle");
}
else {
System.out.println("Obtuse-angled Triangle");
}
}
else {
System.out.println("Triangle not possible");
}
}
}
OUTPUT: