Answer:
Answer is in the provided screenshot! This was a lot of fun to make!
Explanation:
We need to create a new Array which has to be the size of amount * original - as we now that we are going to have that many elements. Then we just iterate through all the values of the new array and set them equal to each of the elements in order.
Ignore the code in my main function, this was to print to the terminal the working code - as you can see from the output at the bottom!
Answer:
B. until another thread issues a notify on the semaphore.
Explanation:
A semaphore is a variable that is shared between threads and is not negative. It also acts as a calling mechanism that uses two atomic operations wait and signal for synchronization of processes.
A thread that is waiting for a process can be signaled by another thread.
A semaphore puts a thread to sleep until another thread issues a notify on the semaphore.
The wait operation will get a semaphore or otherwise wait if the busy S semaphore is available.
The signal operation will release a semaphore or wake a process if there is a thread waiting for S.
Answer:
import java.util.Scanner;
public class Speed{
int speed;
public Speed(int speed){
this.speed = speed;
}
public void checkSpeed(){
if(speed >= 24 || speed <= 56){
System.out.println("Speed is normal");
}
else
System.out.println("Speed is abnormal");
}
public static void main(String...args){
Scanner input = new Scanner(System.in);
int userSpeed = 0;
System.out.println("Enter a speed: ");
userSpeed = input.nextInt();
Speed obj1 = new Speed(userSpeed)
obj1.checkSpeed();
}
Explanation:
Answer:
SORRY but U have to make a new question.
Explanation:
bc u put which is the following is ..... u did not put the following
cant help on this one.
To answer your question the answer would be B compatible browsers