answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
baherus [9]
2 years ago
5

your monthly living expenses are $1500 on an income of $1,650 per month. your goal is to have an emergency fund of 4 times your

monthly living expenses. your emergency fund savings account has $2,400 and you put the remainder of your monthly income into the emergency fund each month. how much more money would you have to save each month to complete your emergency fund in 12 months?
Computers and Technology
1 answer:
Varvara68 [4.7K]2 years ago
8 0
You will need 6000$ in your Ef. You already got 2400 so now u need 3600$. 3600/12= 300$ , which is the amount of money you need to save, you are already saving 150$ so now you need to save 150 more.
You might be interested in
Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating charac
elena-s [515]

Answer:

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate \lambda = 24 customers per hour or 0.4 customers per minute

Service rate \mu​ = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system , P0 = 1 - \lambda / \mu

= 1 - (24/36) = 1/3 = 0.3333

b.) The average number of customers waiting

Lq = \lambda^2 / [\mu(\mu - \lambda)] = 242 / [36 * (36 - 24)] = 1.33

c.) The average number of customers in the system.

L = Lq + \lambda / \mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = \lambda / [\mu(\mu - \lambda)] = 24 / [36 * (36 - 24)] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1/\mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667

3 0
2 years ago
Write a program that simulates flipping a coin to make decisions. The input is how many decisions are needed, and the output is
Nataly [62]

Answer:

import random

decisions = int(input("How many decisions: "))

for i in range(decisions):

   number = random.randint(0, 1)

   if number == 0:

       print("heads")

   else:

       print("tails")

Explanation:

*The code is in Python.

import the random to be able to generate random numbers

Ask the user to enter the number of decisions

Create a for loop that iterates number of decisions times. For each round; generate a number between 0 and 1 using the randint() method. Check the number. If it is equal to 0, print "heads". Otherwise, print "tails"

7 0
2 years ago
Create a single list that contains the following collection of data in the order provided:
ivann1987 [24]

Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

 For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

8 0
2 years ago
Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Xelga [282]

Answer:

The JAVA program to implement for loop for given scenario is shown below.

public class MyProgram {

   public static void main(String args[]) {    

     int len = 5;

     int[] lowerScores = new int[len];      

     lowerScores[0] = 5;

     lowerScores[1] = 0;

     lowerScores[2] = 2;

     lowerScores[3] = -3;      

     System.out.println("The original elements of array are ");

     for(int i=0; i<len; i++)

     {

         System.out.print(lowerScores[i]+" ");

     }      

     System.out.println();

     System.out.println("The modified elements of array are ");

     for(int i=0; i<len; i++)

     {

         // if element is 0 or negative, 0 is assigned to this index

         if(lowerScores[i] <= 0)

           lowerScores[i] = 0;

       // 1 is subtracted from every non zero and positive element

         else

           lowerScores[i] = lowerScores[i] - 1;

           

       System.out.print(lowerScores[i]+" ");

     }

   }

}

OUTPUT

The original elements of array are  

5 0 2 -3 0  

The modified elements of array are  

4 0 1 0 0

Explanation:

The integer array is declared as shown.

int[] lowerScores = new int[len];

The length of the array is given by integer variable len. As per the question, we have taken four elements and size of 5 for the given array.

int len = 5;

The elements of the array are initialized inside the program with the elements given in the question.

lowerScores[0] = 5;

      lowerScores[1] = 0;

The values of the array can be changed to test the program. Also, the size of the array can be changed for testing.

As per the given scenario, if the element is greater than zero, 1 is subtracted from this element. For elements less than or equal to zero, that particular element is assigned the value of 0.

The given program implements if else statement inside for loop for this purpose.

for(int i=0; i<len; i++)

     {

         // if element is 0 or negative, 0 is assigned to this index

         if(lowerScores[i] <= 0)

           lowerScores[i] = 0;

       // 1 is subtracted from every non zero and positive element

         else

           lowerScores[i] = lowerScores[i] - 1;

     }  

5 0
1 year ago
Read 2 more answers
If you want more blank white space around the text in a document, you should increase the ____________.
Hatshy [7]

If you want more blank white space around the text in a document, you should increase the margin.  Correct answer: B

The margin is the area between the main content of a page (in this case that is the text) and the page edges. One-inch page margin is set automatically around each page. However,  you can customize or choose predefined margin settings.

3 0
2 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP!! WILL GIVE BRAINLIEST!!
    15·2 answers
  • array of String objects, words, has been properly declared and initialized. Each element of words contains a String consisting o
    11·1 answer
  • Server farms such as Google and Yahoo! provide enough compute capacity for the highest request rate of the day. Imagine that mos
    12·1 answer
  • In cell E6, create a formula to calculate the percentage of total sales accounted for by DVDs. The formula will divide DVD sales
    15·1 answer
  • What does the binary odometer show about representing large numbers​
    15·1 answer
  • Calvin is an aspiring graphic designer. He wants to achieve Adobe Certified Expert certification in software that will be helpfu
    9·1 answer
  • Match the following technologies with their applications.
    9·1 answer
  • Describe the output when the following code executes in 64-bit mode: .data dividend_hi QWORD 00000108h dividend_lo QWORD 3330002
    12·1 answer
  • 2. BIOS is contained in ROM and not in RAM. Can you guess why?​
    15·1 answer
  • Where can the Field Service Manual containing Critical Callout, Disassembly and Reassembly instructions be found?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!