<u>Answer:</u>
I am writing <em>partial code in</em> <em>c++ to calculate weighted average</em>. The weighted average should be calculated based on multiplying the test score and its <em>respective weight and finally add all the test score.</em>
<u>Explanation:</u>
<em>int arrtestscore[100];</em>
<em>int arrweight[100];</em>
<em>int n;</em>
<em>double weightedavg;</em>
<em>cout<<”Enter the number of test score for which weighted average needs to be calculated”;</em>
<em>cin>>n;</em>
<em>for(int x = 0; x <n;x++)</em>
<em>{</em>
<em> cout<<”Enter test score :” + (x+1) ;</em>
<em> cin>>arrtestscore[x];</em>
<em> count<<”Enter the respective weight:”;</em>
<em> cin>>arrweight[x];</em>
<em>}</em>
<em>for (int i=0; i<n;i++)</em>
<em>{</em>
<em> weightedavg = weightedavg + (arrtestscore[i] * arrweight[i])</em>
<em>}</em>
<em>cout<<”weighted average = “ <<weightedavg; </em>
Answer:
hours = 50
full_days = int(hours / 24)
print("The number of full days in " + str(hours) + " hours is " + str(full_days))
Explanation:
Initialize the hours
Since there are 24 hours in a full day, divide the hours by 24. Note that you need to typecast it to the int, because the result is a decimal value by default
Print the values as requested
The correct answer is
A. the incorporation of technology into objects we use regularly
#Platogang
Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.
- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance
<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that
<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>
Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.
Answer:
public static void PrintShampooInstructions(int numberOfCycles){
if (numberOfCycles<1){
System.out.println("Too Few");
}
else if(numberOfCycles>4){
System.out.println("Too many");
}
else
for(int i = 1; i<=numberOfCycles; i++){
System.out.println(i +": Lather and rinse");
}
System.out.println("Done");
}
Explanation:
I have used Java Programming language to solve this
Use if...elseif and else statement to determine and print "Too Few" or "Too Many".
If within range use a for loop to print the number of times
