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2 years ago

Return 1 if ptr points to an element within the specified intArray, 0 otherwise.

Computers and Technology

1 answer:

Paladinen [302]2 years ago

4 0

Answer:

int withinArray(int * intArray, int size, int * ptr) {

if(ptr == NULL) // if ptr == NULL return 0

return 0;

// if end of intArr is reached

if(size == 0)

return 0; // element not found

else

{

if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr

return 1; // return 1

return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements

}

Explanation:

Above is the completion of the program.

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Explain how abstraction is used in a GPS system

Pavlova-9 [17]

Answer

Abstraction enables GPS system to facilitate the utilization of well defined interfaces while offering room to add additional levels of functionality which are complex to handle.

Explanation

GPS system applies abstraction to be able to arrange level of complexity on which a user will interact with the system. For example, it establishes a link of satellite positioned and timed systems to allow a radio receiver obtain a signal in four dimension after synchronizing the data of latitude, longitude, attitude and time.

7 0

1 year ago

Read 2 more answers

When this program is compiled and executed on an x86-64 Linux system, it prints the string 0x48\n and terminates normally, even

Alexxandr [17]

Answer:

I get 0x55 and this the linking address of the main function.

use this function to see changes:

/* bar6.c */

#include <stdio.h>

char main1;

void p2()

{

printf("0x%X\n", main1);

}

Output is probably 0x0

you can use your original bar6.c with updaated foo.c

char main;

int main() // error because main is already declared

{

p2();

//printf("Main address is 0x%x\n",main);

return 0;

}

Will give u an error

again

int main()

{

char ch = main;

p2(); //some value

printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()

printf("Char value is 0x%x\n",ch); //last two digit of previous line output

return 0;

}

So the pain in P2() gets the linking address of the main function and it is different from address of the function main.

Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...

Explanation:

5 0

1 year ago

Consider the following scenario: "You are an assistant to the accounting manager for a small company that sells sports equipment

Rzqust [24]

Answer:

1. Microsoft Excel helps data analysis through different spreadsheet queries and operations options.

2. Input data to the analysis of sales by product is required for the development of formula and extracting results.

3. The information of data source and frequency of report is required to start the work.

Explanation:

1. Microsoft Excel tool can be used to calculate the results of equipment. Obtained results can be displayed in charts and graphs from the excel.

2. Information like the quantity of sold items, remaining items are required to produce accurate, useful analysis.

Before starting assignment accounting manager will be asked the following questions.

1) Where does the input data come from?

2) Is analysis required on a daily basis or once for all provided data?

3) Is Summary is in the form of tabular data, Graphical data, or Both?

4 0

2 years ago

Lynn runs the locate command and the results include many files from a directory that she doesn't want to include in her search.

Zinaida [17]

Answer:

C) /etc/updatedb.conf

Explanation:

The locate command actually uses the configuration file located at /etc/updated.conf.

5 0

1 year ago

Read 2 more answers

What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C

Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100 -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70 -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice) -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref) -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80 -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20 -> This line adds 20 to the value of Cost and assigns the result to Cost variable

End Subprogram -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e. Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80

7 0

1 year ago