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1 year ago

Return 1 if ptr points to an element within the specified intArray, 0 otherwise.

Computers and Technology

1 answer:

Paladinen [302]1 year ago

4 0

Answer:

int withinArray(int * intArray, int size, int * ptr) {

if(ptr == NULL) // if ptr == NULL return 0

return 0;

// if end of intArr is reached

if(size == 0)

return 0; // element not found

else

{

if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr

return 1; // return 1

return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements

}

Explanation:

Above is the completion of the program.

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in a small office, there are 5 computers, a network printer, and a broadband connection to the internet. what devices are needed

Nataly [62]

Answer:

Ethernet cables, Network Adapters, Modem, Routers, Switches.

Explanation:

The devices that are required in setting up a wired network for the 5 computer comprises of the following devices

Ethernet Cables
Network Adapters
Modem/Router
Network Switch

Ethernet cables: They are called network cables or RJ-45 cables used to in connecting two or more computers together. it has different categories called, the untwisted pair and twisted pair Ethernet, with a speed from 10-1000

Network Adapters : This adapters allows a computer device to connect and interface with a network computer

Modem/Routers : A router is a device that that sits in the middle between your local computers and modems. it takes receives information or gets information from the modem and delivers it to the computer

Network switch: it connects more than two computers together to a network and share data among themselves and other devices on the network

6 0

2 years ago

8.Change the following IP addresses from binary notation to dotted-decimal notation: a.01111111 11110000 01100111 01111101 b.101

Andrews [41]

Answer:

a. 01111111 11110000 01100111 01111101 dotted decimal notation:

(127.240.103.125)

b. 10101111 11000000 11111000 00011101 dotted decimal notation: (175.192.248.29)

c. 11011111 10110000 00011111 01011101 dotted decimal notation:

(223.176.31.93)

d. 11101111 11110111 11000111 00011101 dotted decimal notation:

(239.247.199.29)

a. 208.34.54.12 class is C

b. 238.34.2.1 class is D

c. 242.34.2.8 class is E

d. 129.14.6.8 class is B

a.11110111 11110011 10000111 11011101 class is E

b.10101111 11000000 11110000 00011101 class is B

c.11011111 10110000 00011111 01011101 class is C

d.11101111 11110111 11000111 00011101 class is D

Explanation:

8 a. 01111111 11110000 01100111 01111101

we have to convert this binary notation to dotted decimal notation.

01111111 = 0*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1*4 + 1*2 + 1

= 64 + 32 + 16 + 8 + 4 + 2 + 1

= 127

11110000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

= 1*128 + 1*64 + 1*32 + 16 + 0 + 0 + 0 + 0

= 128 + 64 + 32 + 16

= 240

01100111 = 0*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 0 + 1*64 + 1*32 + 0 + 0 + 4 + 2 + 1

= 64 + 32 + 4 + 2 + 1

= 103

01111101 = 0*2^7 + 1*2^6 + 1*2^5+ 1*2^4 +1*2^3 +1*2^2 + 0*2^1 + 1*2^0

= 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1* 4 + 0 + 1

= 64 + 32 + 16 + 8 + 4 + 1

= 125

So the IP address from binary notation 01111111 11110000 01100111 01111101 to dotted decimal notation is : 127.240.103.125

b) 10101111 11000000 11111000 00011101

10101111 = 1*2^7 + 0*2^6 + 1*2^5 + 0*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 175

11000000 = 1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

= 192

11111000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +1*2^3 + 0*2^2 + 0*2^1 + 0*2^0

= 248

00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

= 29

So the IP address from binary notation 10101111 11000000 11111000 00011101 to dotted decimal notation is : 175.192.248.29

c) 11011111 10110000 00011111 01011101

11011111 = 1*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 223

10110000 = 1*2^7 + 0*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

= 176

00011111 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 31

01011101 = 0*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

= 93

So the IP address from binary notation 11011111 10110000 00011111 01011101 to dotted decimal notation is :223.176.31.93

d) 11101111 11110111 11000111 00011101

11101111 = 1*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 239

11110111 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 247

11000111 = 1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

= 199

00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

= 29

So the IP address from binary notation 11101111 11110111 11000111 00011101 to dotted decimal notation is : 239.247.199.29

9. In order to the find the class check the first byte of the IP address which is first 8 bits and check the corresponding class as follows:

Class A is from 0 to 127

Class B is from 128 to 191

Class C is from 192 to 223

Class D is from 224 to 239

Class E is from 240 to 255

a. 208.34.54.12

If we see the first byte of the IP address which is 208, it belongs to class C as class C ranges from 192 to 223.

b. 238.34.2.1

If we see the first byte of the IP address which is 238, it belongs to class D as Class D ranges from 224 to 239.

c. 242.34.2.8

If we see the first byte of the IP address which is 242, it belongs to class E as Class E ranges from 240 to 255.

d. 129.14.6.8

If we see the first byte of the IP address which is 129, it belongs to class B as Class B ranges from 128 to 191.

10. In order to find the class of the IP addresses in easy way, start checking bit my bit from the left of the IP address and follow this pattern:

0 = Class A

1 - 0 = Class B

1 - 1 - 0 = Class C

1 - 1 - 1 - 0 = Class D

1 - 1 - 1 - 1 = Class E

a. 11110111 11110011 10000111 11011101

If we see the first four bits of the IP address they are 1111 which matches the pattern of class E given above. So this IP address belongs to class E.

b. 10101111 11000000 11110000 00011101

If we see the first bit is 1, the second bit is 0 which shows that this is class B address as 1 0 = Class B given above.

c. 11011111 10110000 00011111 01011101

The first bit is 1, second bit is 1 and third bit is 0 which shows this address belongs to class C as 110 = Class C given above.

d. 11101111 11110111 11000111 00011101

The first bit is 1, the second bit is also 1 and third bit is also 1 which shows that this address belongs to class D.

3 0

1 year ago

Cooper Technologies is a technology company that offers many IT services in Chicago. The company's services and products include

yuradex [85]

Answer:

d. broad needs and few customers.

Explanation:

This strategy is based on creation of unique and valuable persons.

Broad needs and few customers (Wealth Management )

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2 years ago

Value is always _____________ aligned in a cell.

Nadya [2.5K]

Answer:

Right

Explanation:

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1 year ago

A packet analyzer is a program that can enable a hacker to do all of the following EXCEPT ________. Select one: A. assume your i

bonufazy [111]

Answer:

Option (B) is the correct answer of this question.

Explanation:

Packet analyzer is a software application or set of infrastructure capable of unencrypted and recording communication that travels through a virtual system of a computer system.A packet analyzer used to detect network activity is recognized as a broadband monitoring system.

A packet analyzer is a code application that is used for monitoring, intercepting, and recording http requests with the help of a virtual interface.

Other options are incorrect because they are not related to the given scenario.

8 0

2 years ago