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zalisa [80]
2 years ago
15

"online privacy alliance (opa) is an organization of companies dedicated to protecting online privacy. members of opa agree to c

reate a privacy policy for a customer that is easy to read and understand. which of the following provisions is not included in the policy?
(a) the option of choosing who sees
(b) the datatypes of data collected
(c) how data is used
(d) how collected data is secured
Computers and Technology
1 answer:
AleksAgata [21]2 years ago
3 0

Answer:

Option A.

Explanation:

It is a business association working to protect your online privacy. Opa members agree to establish a User privacy Policy that is readable and understandable. So, the option of choosing who sees the data  is the provision is not available in the policy because It has data types policy gathered and how data collected is protected.

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The ratio of Chris an iood Dom's ages is
irinina [24]

Answer:

28 years

Explanation:

Let's represent present age of Chris and Dom as C and D respectively. Then since ratio of present age of Chris and Dom is 3:4. Therefore,

\frac{C}{D}=\frac{3}{4}

C=\frac{3}{4}D   ...(1)

Now, it is given that in 7 years their age ratio will become 4:5. Therefore,

\frac{C+7}{D+7}=\frac{4}{5}

5C+35=4D+28\\

Using value of C from equation(1),

5\times\frac{3}{4}D-4D=28-35

15D-16D=-28\\-D=-28\\ D=28

Thus, present age of Dom is 28 years.

8 0
3 years ago
What is one effective way for employees to keep their skillsets current?
lys-0071 [83]
They are probably looking for B.  subscribing to journals is a good way of keeping up with what's happening in any field.

Of course, a very carefully curated professional network online is great for this too (but they said "personal" so that's not the answer)

Employers generally prefer that employees WORK as often as possible, so even though JUDICIOUS use of social media is a great way to keep current, D isn't the answer either.

Blogging about personal experiences is not necessarily going to teach you anything about work, though blogging professionally can be useful in gathering response from your readership
4 0
2 years ago
Read 2 more answers
Define a structure type auto_t to represent an automobile. Include components for the make and model (strings), the odometer rea
yulyashka [42]

Answer:

see explaination

Explanation:

#include <stdio.h>

#include <string.h>

#define BUFSIZE 1000

struct auto_t scan_auto(char *);

struct date_t {

char day[2];

char month[2];

char year[4];

};

struct tank_t {

char tankCapacity[10];

char currentFuelLevel[10];

};

struct auto_t {

char make[50];

char model[50];

char odometerReading[10];

struct date_t manufactureDate;

struct date_t purchaseDate;

struct tank_t gasTank;

};

int main(int argc, char *argv[]) {

/* the first command-line parameter is in argv[1]

(arg[0] is the name of the program) */

FILE *fp = fopen(argv[1], "r"); /* "r" = open for reading */

char buff[BUFSIZE]; /* a buffer to hold what you read in */

struct auto_t newAuto;

/* read in one line, up to BUFSIZE-1 in length */

while(fgets(buff, BUFSIZE - 1, fp) != NULL)

{

/* buff has one line of the file, do with it what you will... */

newAuto = scan_auto(buff);

printf("%s\n", newAuto.make);

}

fclose(fp); /* close the file */

}

struct auto_t scan_auto(char *line) {

int spacesCount = 0;

int i, endOfMake, endOfModel, endOfOdometer;

for (i = 0; i < sizeof(line); i++) {

if (line[i] == ' ') {

spacesCount++;

if (spacesCount == 1) {

endOfMake = i;

}

else if (spacesCount == 2) {

endOfModel = i;

}

else if (spacesCount == 3) {

endOfOdometer = i;

}

}

}

struct auto_t newAuto;

int count = 0;

for (i = 0; i < endOfMake; i++) {

newAuto.make[count++] = line[i];

}

newAuto.make[count] = '\0';

count = 0;

for (i = endOfMake+1; i < endOfModel; i++) {

newAuto.model[count++] = line[i];

}

newAuto.model[count] = '\0';

count = 0;

for (i = endOfModel+1; i < endOfOdometer; i++) {

newAuto.odometerReading[count++] = line[i];

}

newAuto.odometerReading[count] = '\0';

return newAuto;

}

8 0
2 years ago
Given an n-element array X, algorithm D calls algorithm E on each element X[i]. Algorithm E runs in O(i) time when it is called
krek1111 [17]

Answer:

O(n^2)

Explanation:

The number of elements in the array X is proportional to the algorithm E runs time:

For one element (i=1) -> O(1)

For two elements (i=2) -> O(2)

.

.

.

For n elements (i=n) -> O(n)

If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)  

5 0
2 years ago
The __________ contains a list of all the resources owned by the library.
Ira Lisetskai [31]

The catalog contains a list of all the resources owned by the library.

- Mabel <3

5 0
2 years ago
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