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ira [324]
2 years ago
14

Write a program that simulates flipping a coin to make decisions. The input is how many decisions are needed, and the output is

either heads or tails. Assume the input is a value greater than 0.
Computers and Technology
1 answer:
Nataly [62]2 years ago
7 0

Answer:

import random

decisions = int(input("How many decisions: "))

for i in range(decisions):

   number = random.randint(0, 1)

   if number == 0:

       print("heads")

   else:

       print("tails")

Explanation:

*The code is in Python.

import the random to be able to generate random numbers

Ask the user to enter the number of decisions

Create a for loop that iterates number of decisions times. For each round; generate a number between 0 and 1 using the randint() method. Check the number. If it is equal to 0, print "heads". Otherwise, print "tails"

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The new Director of Information Technology has asked you to recommend a strategy to upgrade the servers on their network. Recomm
borishaifa [10]

Answer:

servers to be upgraded are : APPLICATION AND LOAD BALANCING SERVERS

servers still appropriate to use : DNS AND DHCP SERVERS

Explanation:

The recommendations to be made in line with what the new director of information is asking for includes :

1 ) For the servers to be upgraded : The servers that requires upgrades  includes the APPLICATION SERVER and LOAD BALANCING SERVER. this is because these two servers are critical to the growth/expansion of any business, and they handle large volume of data

Recommendations on the servers upgrade includes:

Hardware : 2.3 GHz Intel Xeon Gold 5118 12-Core

CPU chip set :  Socket: FCLGA3647, Type: NSBM

Speed : processor 3.2 GHz

caching:   > 100 Gb

2)  For servers that do not necessarily need to be upgraded : The servers that do not need immediate upgrade are DNS and DHCP

6 0
2 years ago
A half-life is the amount of time it takes for a substance or entity to fall to half its original value. Caffeine has a half-lif
Ivan

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

 // variable

float n;  

cout<<"Enter the initial value:";

//Read the input from the user  

cin>>n;

//Declare variables for storing values at 6, 12 and 18 hours

float hours_6, hours_12, hours_18;  

//Set precision level of floating point number

cout << fixed;

    cout << setprecision(6);

 //calculate values at 6, 12 and 18 hours

hours_6 = n / 2.0;

hours_12 = hours_6 / 2.0;

hours_18 = hours_12 / 2.0;

//display the output

cout<<"After 6 hours: "<<hours_6<<"mg"<<endl;

cout<<"After 12 hours: "<<hours_12<<"mg"<<endl;

cout<<"After 18 hours: "<<hours_18<<" mg"<<endl;

return 0;

}

Explanation:

Read an input from the user. Set the precision to 6 for displaying the result up to 6 decimal places. The first half life at 6 hours can be calculated by dividing the input by 2. The half life at 12 hours can be found out by dividing the half life value at 6 hours by 2. Similarly at 18 hours, we find the half life value by dividing the half life value at 12 hours by 2.

Output:

Enter the initial value:100                                                                                                

After 6 hours: 50.000000 mg                                                                                                

After 12 hours: 25.000000 mg                                                                                              

After 18 hours: 12.500000 mg  

5 0
2 years ago
9. Which of the following are true for all regular languages and all homomorphisms? (a) h (L1 ∪ L2)= h (L1) ∩ h (L2). (b) h (L1
mixer [17]

Answer:

h (L1 ∪ L2)= h (L1) ∩ h (L2).

This is true.

There will be w ∈  (L1 ∪ L2) for any s ∈ h (L1 ∪ L2) in such a way that s=h(w)

we can assume that w ∈ L1

So In this case h(w) ∈ L (S1). Hence s ∈ L(S1)

for any s ∈ h (L1) U h(L2)

We can assume that s ∈ L(S1)

There exists w ∈ L1 such that s= h(w)

In this case it is w ∈ L1 U L2 as well.

Hence , s ∈ h (L1 U L2)

Explanation

consider  = 0,1 and  = a,b and h(0) = a , h(1) = ab

(a) Consider L1 = 10,01 and L2 = 00,11

   Now L1 ∪ L2 = 00,01,10,11

   h (L1 ∪ L2) = h(00) , h(01) , h(10) , h(11) = h(0)h(0) , h(0)h(1) , h(1)h(0) , h(1)h(1)

  = aa, aab , aba , abab

Hence h (L1 ∪ L2) = aa, aab , aba , abab .

Here h (L1) = h(10) , h(01) = h(1)h(0) , h(0)h(1) = aba , aab

Hence h (L1) = aba , aab .

Here h (L2) = h(00) , h(11) = h(0)h(0), h(1)h(1) = aa, abab

Hence h(L2) = aa, abab.

Finally Hence , h (L1 ∪ L2)= h (L1) ∩ h (L2).

5 0
2 years ago
Janis needs to select all the text in a single bullet point. Which action describes the easiest method to perform this task?
olganol [36]

Answer:

Triple-click the text in the bullet item is the easiest  way to select all text

Explanation:

5 0
2 years ago
A laptop gets replaced if there's a hardware issue. Which stage of the hardware lifecycle does this scenario belong to?
Ilya [14]

Answer: Maintenance. This is the stage where software is updated and hardware issues are fixed if and when they occur. Retirement. In this final stage, hardware becomes unusable or no longer needed and it needs to be properly removed from the fleet

Explanation:

3 0
2 years ago
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