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V125BC [204]
2 years ago
15

python A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun

. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year.
Computers and Technology
2 answers:
Lesechka [4]2 years ago
4 0

Answer:

i_year=int(input(""))

#check leap year

if((i_year % 4 == 0 and i_year % 100 != 0) or (i_year % 400 == 0)):

  print("{} is a leap year.".format(i_year))

else:

  print("{} is not a leap year.".format(i_year))

Explanation:

e-lub [12.9K]2 years ago
3 0

Answer:

// program in Python.

#read year

i_year=int(input("Please Enter a year:"))

#check leap year

if((i_year % 4 == 0 and i_year % 100 != 0) or (i_year % 400 == 0)):

   print("{} is a leap year.".format(i_year))

else:

   print("{} is not a leap year.".format(i_year))

Explanation:

Read year from user and assign it to variable "year".If year is completely divisible by 4 and not divisible by 100 or year is completely divisible by 400 then year is leap year otherwise year is not a leap year.

Output:

Please Enter a year:2003                                                                                                          

2003 is not a leap year.

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Assign max_sum with the greater of num_a and num_b, PLUS the greater of num_y and num_z. Use just one statement. Hint: Call find
Gnoma [55]

Answer:

def find_max(num_1, num_2):

   max_val = 0.0

   if (num_1 > num_2): # if num1 is greater than num2,

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   else: # Otherwise,

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max_sum = 0.0

num_a = float(input())

num_b = float(input())

num_y = float(input())

num_z = float(input())

max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)

print('max_sum is:', max_sum)

Explanation:

I added the missing part. Also, you forgot the put parentheses. I highlighted all.

To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)

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You resurrected an old worksheet. It appears to contain most of the information that you need, but not all of it. Which step sho
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Answer:

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Explanation:

Since the worksheet contains most of the data that you need, there is a decent possibility that it also contains the data that you are missing. Therefore, you should check for data you have previously hidden. Sometimes, some data in a worksheet may become irrelevant in a given moment, and instead of deleting it since it may be useful later most people tend to make that data hidden. So checking for previously hidden data may be the best solution in this scenario.

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Answer:

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Explanation:

Because when the user configures the record type, Then, they can help that user to configure the value of the picklist fields for the page layout. So, The type and the lead source opportunity is available for the standard field that configure straightly in the type of record. That's why the following option is correct.

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Answer:

The solution code is written in Python 3 as below:

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Explanation:

To create a simple text file in Python, we can use Python built-in function, <em>open()</em>. There are two parameters needed for the open() function,

  1. the file name and
  2. a single keyword "w". "w" denote "write". This keyword will tell our program to create a file if the file doesn't exist.

The statement <em>open("greeting.txt", "w")</em> will create a text file named "<em>greeting.txt</em>" (Line 1)

To fill up the content in the greeting.txt, we use <em>write()</em> method. Just include the content string as the argument of the <em>write()</em> method. (Line 2)

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