Answer:
// here is code in java.
import java.util.*;
// class definition
class Main
{
// method that return total fare
public static double fare(double dis)
{
// calculate the total fare
double tot_fare=(4+((dis*1000)/140)*0.25);
return the fare
return tot_fare;
}
//driver method
public static void main (String[] args) throws java.lang.Exception
{
try{
// scanner object to read input string
Scanner s=new Scanner(System.in);
// variable
double dis;
System.out.print("please enter the distance in KM: ");
//read the number
dis=s.nextDouble();
// call the function with "dis" parameter
double ride_fare=fare(dis);
// print the total fare
System.out.println("total fare is: "+ride_fare);
}catch(Exception ex){
return;}
}
}
Explanation:
Read the distance from user with the help of scanner class.Call the function with parameter "dis".Here it will calculate the total fare as (4+((dis*1000)/140)*0.25). Here base fare is $4 and $0.25 for every 140 meter.Then function will return the total fare.
Output:
please enter the distance in KM: 7
total fare is: 16.5
Answer:
JPG / JPEG best choice and work well on websites
Explanation:
JPEGs contains millions of colors, so this type of file is ideal for photographs.
Best choice for posting on social media channels
Answer:g
public static int addOddMinusEven(int start, int end){
int odd =0;
int even = 0;
for(int i =start; i<end; i++){
if(i%2==0){
even = even+i;
}
else{
odd = odd+i;
}
}
return odd-even;
}
}
Explanation:
Using Java programming language:
- The method addOddMinusEven() is created to accept two parameters of ints start and end
- Using a for loop statement we iterate from start to end but not including end
- Using a modulos operator we check for even and odds
- The method then returns odd-even
- See below a complete method with a call to the method addOddMinusEven()
public class num13 {
public static void main(String[] args) {
int start = 2;
int stop = 10;
System.out.println(addOddMinusEven(start,stop));
}
public static int addOddMinusEven(int start, int end){
int odd =0;
int even = 0;
for(int i =start; i<end; i++){
if(i%2==0){
even = even+i;
}
else{
odd = odd+i;
}
}
return odd-even;
}
}
Answer: A :is concerned with defending users’ freedom of use
C:makes source code available for editing
Explanation:
