The correct answer for this question is this one: " c.huge initial investment"
<span>Ethan is a systems developer. He is working on a system where he will implement independent solutions for different processes. The possible drawback of using such a system is that </span><span><u>huge initial investment</u>
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Hope this helps answer your question and have a nice day ahead.
Answer:
Written in Java
public static void printArray(int myarr[], String s){
for(int i = 0; i<myarr.length;i++){
System.out.print(myarr[i]+s);
}
}
Explanation:
This defines the static method alongside the array and the string variable
public static void printArray(int myarr[], String s){
The following iteration iterates through the elements of the array
for(int i = 0; i<myarr.length;i++){
This line prints each element of the array followed by the string literal
System.out.print(myarr[i]+s);
}
}
The method can be called from main using:
<em>printArray(myarr,s);</em>
Where myarr and s are local variables of the main
Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
Answer:
The middle node has a data –250. ... Write The Pseudocode To Replace The Middle Node Of The Linked List With ... Assume That The List's Head Pointer Is Called Head_ptr And The Data For The New Node Is Called Entry ... Assume that the list's head pointer is called head_ptr and the data for the new node is called entry ...
Explanation: