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2 years ago

Using python,

Computers and Technology

1 answer:

Levart [38]2 years ago

4 0

Answer:

Explanation:

We can use for-loop in python to calculate the tuition amount in the next 5 years. If the tuition is increasing 3% each year, in each loop we can multiply the amount by 1.03

tuition = 8000

for year in range(1,6):

tuition *= 1.03

print("The tuition amount after " + str(year) + " year(s) is $" + str(tuition))

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Write an expression that executes the loop body as long as the user enters a non-negative number. Note: If the submitted code ha

Delicious77 [7]

Answer:

Following are the program in C++ language

#include <iostream> // header file

using namespace std; // namespace

int main() // main function

{

int number=0; // variable declaration

while(number>-1) // iterating the while loop

{

cout<<"body"<<endl; // dsiplay the statement

cin>>number; // Read the value by the user

}

cout<<endl<<"Done";// dsiplay the statement

return 0;

}

Output:

body

-8

Done

Explanation:

Following are the description of the statement

Declared a variable "number" of int type and initialized with 0 to them
iterating the while loop. In this loop print the message "body" and Read the value by the user in the "number" variable. This loop will be executed repeatedly until the user do not read the negative value.
After the execution of the while loop, it prints the message "Done".

4 0

2 years ago

"Create a Python program named detect_column_level_data_entry_errors. When complete, you will run this program to produce a diag

11111nata11111 [884]

Answer:

See explaination

Explanation:

Code for detect_column_level_data_entry_errors.py:

# File: detect_column_level_data_entry_errors.py

# The program will produce a diagnostic report that shows data entry errors that cause column

# totals in the data to be out of balance. Will need to fix cleaned_data.txt until errors resolved.

def main():

input_filename = input('Please enter the input filename: ')

infile = open(input_filename, 'r', encoding='utf8')

total_males = 0

total_females = 0

sum_total = 0

print('\n{0:^40}'.format('Column-Level Data Entry Errors'))

print('\n{0:<10}{1:>10}{2:>10}{3:>10}'.format(

'Age Group', 'Males', 'Females', 'Total'))

for line in infile:

age_group, males, females, total = line.split()

males = int(males)

females = int(females)

total = int(total)

print('{0:<10}{1:>10,}{2:>10,}{3:>10,}'.format(

age_group, males, females, total))

if age_group != 'Total':

total_males = males + total_males

total_females = females + total_females

sum_total = total + sum_total

else:

print('{0:<10}{1:>10,}{2:>10,}{3:>10,}'.format(

'Error', (males-total_males), (females-total_females), (total-sum_total)))

infile.close()

main()

8 0

2 years ago

Assume the availability of class named IMath that provides a static method, toThePowerOf which accepts two int arguments and ret

geniusboy [140]

Answer:

cubeVolume = IMath.toThePowerOf(cubeSide, 3);

Explanation:

Following is the explanation for above statement:

Left side:

cubeVolume is a variable with data-type int, it will store the integer value that is the output from right side.

Right side:

IMath is the class name.
toThePowerOf is the built-in function that takes two arguments of data type int. First is the base and second is the power(exponent) separated by comma. In place of first argument that is the base variable we will pass the variable cubeSide that has been declared and initialize.
Now the output will be stored in the variable cubeVolume.

i hope it will help you!

4 0

2 years ago

Allie is choosing a URL for her band’s website, which is the best method of making the URL easy to understand? creating a URL wi

gayaneshka [121]

URL stands for Uniform Resource Locator. It identifies the location of a file on the internet and is used in order the web browser to know where to look. The entire address www.brainly.com is called the URL.
The best method of making the URL easy to understand is creating humam-readable URL.

7 0

2 years ago

Read 2 more answers

Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer

NeTakaya

Answer:

Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

Explanation:

The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

for the case i = n-2, invariant p is product of a[0], a[1], a[2] .... a[n-3].a[n-2]. It is the product of (n-1) terms. In while loop, incrementing the value of i, so i=n-1

And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

If i = n , n - i = 0 , it will violate condition of while loop, so, the while loop will terminate at i = n at this time loop invariant P = a[0].a[1].a[2]....a[n-2].a[n-1]

6 0

2 years ago