Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.
- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance
<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that
<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>
Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.
A burn-in test is a test which is usually performed on a system or component by running it for a long time in order to bring out any errors or system failures etc.
While doing it on CPU the data must be backed up as any kind of error or failure may result in the loss of data, at time systems can be repaired to retrieve data but still there is no guarantee, backing up is the best option.
#include <stdio.h>
int main(void) {
// your code goes here
//unsigned a =float_times_four(0x80000000);
unsigned float_times_four(unsigned uf){
unsigned expn = (uf >> 23) & 0xFF;
printf(expn);
unsigned sign = uf & 0x80000000;
unsigned frac = uf & 0x007FFFFF;
if(expn == 255 ||(expn == 0 && frac ==0))
return uf;
if(expn){
expn<<2;
}else if(frac == 0x007FFFFF){
//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute
frac>>2;
expn<<2;
}else{
frac<<=2;
}
return (sign) | (expn <<23) | (frac);
}
return 0;
}
Answer:
B. The storage structure requires a clock input.
Explanation:
Logic circuits are circuits in electronics that give output based on the logic gate principle and its inputs. It can be a sequential logic circuit or a combinational logic circuit.
Decoders RS latches are combinational logic circuits because they both comprise of a combination of several sequential circuits to make their systems. The difference between decoders and RS latches is that the RS is a storage structure which is made up of flip-flops which require a clock input
Answer:
(1) Carry flag (2) Overflow flag (3) Sign or negative Flag
Explanation:
Solution
(1) The carry flag : It refers to the adding or subtracting. a two registers has a borrow or carry bit
(2) The over flow flag: This flag specify that a sign bit has been modified during subtracting or adding of operations
(3) The sign flag: This is also called a negative sign flag is a single bit status in a register that specify whether the last mathematical operations generated a value to know if the most significant bit was set.
