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jeyben [28]
2 years ago
10

In cell B16, enter a function to calculate the total attendance for the years 2014 through 2018 using the totals in the range B1

2:F12.
Computers and Technology
1 answer:
Burka [1]2 years ago
3 0

Answer:

The function to be entered in the cell B16 to calculate the total attendance for the years 2014 through 2018 is; =sum

Explanation:

In Ms. Excel the Sum function is used to calculate the totals of particular cell range. Simply type in; =sum in the cell B16 then highlight the cell range  B12:F12. Upon pressing enter, the spreadsheet will return the total attendance for the years 2014 through 2018.

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Please help, Tech class!!
IRISSAK [1]

Answer:

Explanation:

1=A

2=A

3=A

4=True

5=A

6=D

7=D

8=B

9=True

10=C

3 0
2 years ago
Animated graphics that are displayed on the screen after a set of time when the computer is unattended.​
yan [13]

Answer:

Tab b. CTRL+A c. Alt d. Enter 18. Animated graphics that are displayed on the screen after a set of time when the computer is unattended. a. Screen Saver b. Title Bar c. Scroll Bar d.

Explanation:

Tab b. CTRL+A c. Alt d. Enter 16. Animated graphics that are displayed on the screen after a set of time when the computer is unattended

Computer-generated motion graphics[edit]. Before computers were widely available, motion graphics were costly and time-consuming, limiting their use to high-budget filmmaking and ...

7 0
1 year ago
Redo Programming Exercise 16 of Chapter 4 so that all the named constants are defined in a namespace royaltyRates. PLEASE DONT F
Komok [63]

Answer:

Code is given below and output is attached in the diagram:

Explanation:

//Use this header file while using visual studio.

#include "stdafx.h"

//Include the required header files.

#include<iostream>

//Use the standard naming convention.

using namespace std;

//Define a namespace royaltyRates.

namespace royaltyRates

{

    //Declare and initialize required named constants.

    const double PAY_ON_DELIVERY_OF_NOVAL = 5000;

    const double PAY_ON_PUBLISH_OF_NOVAL = 20000;

    const double PER_ON_NET_PRICE_SECOND_OPTION =

    0.125;

    const double PER_ON_NET_PRICE_FIRST_4000 = 0.1;

    const double PER_ON_NET_PRICE_OVER_4000 = 0.14;

};

//Start the execution of main() method.

int main()

{

    //Declare and initialize the required variables

    //which are going to be used to calculate

    //royalities under each option.

    float net_price;

    int num_copies;

    float royaltyUnderOption1, royaltyUnderOption2,

    royaltyUnderOption3;

    royaltyUnderOption1 = royaltyUnderOption2

    = royaltyUnderOption3 = 0;

    //Prompt the user to enter the net price of each

    //novel.

    cout << "Please enter the net price for each ";

    cout << "copy of the novel : ";

    cin >> net_price;

    //Prompt the user to enter the estimated number

    //of copies of the novels to be sold.

    cout << "Please enter the estimated number ";

    cout << "of copies to be sold : ";

    cin >> num_copies;

    //Display the required details and royalty

    //calculated under option 1.

    cout << "\n*** Option 1: ****" << endl;

    cout << "Net price of each novel: $" << net_price;

    cout << endl;

    cout << "Estimated number of copies to be sold ";

    cout << "is: " << num_copies << endl;

    cout << "$";

    cout << royaltyRates::PAY_ON_DELIVERY_OF_NOVAL;

    cout << " is paid to author for the delivery of ";

    cout << "the final manuscript and $";

    cout << royaltyRates::PAY_ON_PUBLISH_OF_NOVAL;

    cout << " is paid for the publication of ";

    cout << "novel." << endl;

    royaltyUnderOption1 =

    royaltyRates::PAY_ON_DELIVERY_OF_NOVAL +

    royaltyRates::PAY_ON_PUBLISH_OF_NOVAL;

    cout << "Total amount of royalty under option 1 ";

    cout << "is $" << royaltyUnderOption1 << endl;

    //Display the required details and royalty

    //calculated under option 2.

    cout << "\n*** Option 2: ****" << endl;

    cout << "Net price of each novel: $";

    cout << net_price << endl;

    cout << "Estimated number of copies to be sold ";

    cout << "is: " << num_copies << endl;

    royaltyUnderOption2 =

   (royaltyRates::PER_ON_NET_PRICE_SECOND_OPTION *

    net_price)* num_copies;

    cout << "Total amount of royalty under option 2 ";

    cout << "is $" << royaltyUnderOption2 << endl;

    //Display the required details and royalty

    //calculated under option 3.

    cout << "\n*** Option 3: ****" << endl;

    cout << "Net price of each novel: $" << net_price;

    cout << endl;

    cout << "Estimated number of copies to be sold ";

    cout << "is: " << num_copies << endl;

    //If the number of copies is greater than 4000.

    if (num_copies > 4000)

    {

         //Total amount of royalty will be 10% of net

         //price of first 4000 copies and 14 % of net

         //price of copies sold over 4000.

         royaltyUnderOption3 =

         (royaltyRates::PER_ON_NET_PRICE_FIRST_4000 *

         net_price) * 4000 +

         (royaltyRates::PER_ON_NET_PRICE_OVER_4000 *

         net_price) * (num_copies - 4000);

    }

    //Otherwise,

    else

    {

         //Total amount of royalty will be 10% of net

         //price of first 4000 copies.

         royaltyUnderOption3 =

         (royaltyRates::PER_ON_NET_PRICE_FIRST_4000 *

         net_price) * num_copies;

    }

    cout << "Total amount of royalty under option 3 ";

    cout << "is $" << royaltyUnderOption3 << endl;

    //If the royalty under option 1 is greater than

    //royalty under option 2 and 3, then option 1 is

    //best option.

    if (royaltyUnderOption1 > royaltyUnderOption2 &&

    royaltyUnderOption1 > royaltyUnderOption3)

    {

         cout << "\nOption 1 is the best option that ";

         cout << "author can choose." << endl;

    }

    //If the royalty under option 2 is greater than

    //royalty under option 1 and 3, then option 2 is

    //best option.

    else if (royaltyUnderOption2 > royaltyUnderOption1

    && royaltyUnderOption2 > royaltyUnderOption3)

    {

         cout << "\nOption 2 is the best option that ";

         cout << "author can choose." << endl;

    }

    //If the royalty under option 3 is greater than

    //royalty under option 1 and 2, then option 3 is

    //best option.

    else

    {

         cout << "\nOption 3 is the best option that ";

         cout << "author can choose." << endl;

    }

    //Use this command while using visual studio.

    system("pause");

    return 0;

}

5 0
2 years ago
Which of the following reflects Moore's law? Multiple Choice The doubling of computer chip performance per dollar every two year
Katena32 [7]

Answer:

The correct answer is A.

Explanation:

Moore's Law states/predicts that the maximum number of transistors that can be used on integrated circuits (processors etc.) will be doubled every two years so it basically predicts an exponential growth in terms of transistors used.

Doubling the number of transistors used means that it will almost certainly increase the performance of the processors. Of course there are a lot of other variables that the performance depends on but Moore's Law is proven to be true and  is being used since 1960's. The answer given in option A is the one that best reflects on this law.

I hope this answer helps.

4 0
2 years ago
Write three functions in C/C++: one that declares a large array statically, one that declares the same large array on the stack,
Nikolay [14]

Answer:

See explaination

Explanation:

#include<iostream>

#include<stack>

#include <algorithm> // std::make_heap, std::pop_heap, std::push_heap, std::sort_heap

#include <vector> // std::vector

using namespace std;

void StaticArray()

{

unsigned int array[64536];

for(unsigned int i=0;i<64536;i++)

array[i]=i;

}

void Stack()

{

stack<unsigned int> mystack;

for(unsigned int i=0;i<64536;i++)

mystack.push(i);

}

void Heap()

{

unsigned int myints[64536];

for(unsigned int i=0;i<64536;i++)

myints[i]=i;

vector<unsigned int> v(myints,myints+64535);

make_heap (v.begin(),v.end());

push_heap (v.begin(),v.end());

}

int main()

{

StaticArray();

Stack();

Heap();

return 0;

}

7 0
2 years ago
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