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Kipish [7]
2 years ago
13

1. (1 point) Which flag is set when the result of an unsigned arithmetic operation is too large to fit into the destination? 2.

(1 point) Which flag is set when the result of a signed arithmetic operation is either too large or too small to fit into the destination? 3. (1 point) Which flag is set when an arithmetic or logical operation generates a negative result?
Computers and Technology
1 answer:
patriot [66]2 years ago
8 0

Answer:

(1) Carry flag (2) Overflow flag (3) Sign or negative Flag

Explanation:

Solution

(1) The carry flag : It refers to the adding or subtracting. a two registers has a borrow or carry bit

(2) The over flow flag: This flag specify that a sign bit has been modified during subtracting or adding of operations

(3) The sign flag: This is also called a negative sign flag is a single bit status in a register that specify whether the last mathematical operations  generated a value to know if the most significant bit was set.

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Replace any alphabetic character with '_' in 2-character string passCode. Ex: If passCode is "9a", output is: 9_
oksian1 [2.3K]

Answer:

if(isalpha(passCode[0]))

{

passCode[0] = '_';

}

if(isalpha(passCode[1]))

{

passCode[1] = '_';  

}

         

Explanation:

The first if statement uses isalpha() function which checks if the character passed in this function is an alphabet. If the character stored in 0-th position (which is the first position whose index is 0) of the variable passCode is an alphabet then it is replaced with the '_'

The next if statement checks if the second character in the passCode variable is an alphabet. This means the function isalpha() checks if the character stored in second position (index 1) of the variable passCode is an alphabet then it is replaced with the '_'

The  complete activity with this chunk of code added and the output is attached in a screen shot.

4 0
2 years ago
Modify the TimeSpan class from Chapter 8 to include a compareTo method that compares time spans by their length. A time span tha
My name is Ann [436]

Answer:

Check the explanation

Explanation:

Here is the modified code for

TimeSpan.java and TimeSpanClient.java.

// TimeSpan.java

//implemented Comparable interface, which has the compareTo method

//and can be used to sort a list or array of TimeSpan objects without

//using a Comparator

public class TimeSpan implements Comparable<TimeSpan> {

   private int totalMinutes;

   // Constructs a time span with the given interval.

   // pre: hours >= 0 && minutes >= 0

   public TimeSpan(int hours, int minutes) {

        totalMinutes = 0;

        add(hours, minutes);

   }

   // Adds the given interval to this time span.

   // pre: hours >= 0 && minutes >= 0

   public void add(int hours, int minutes) {

        totalMinutes += 60 * hours + minutes;

   }

   // Returns a String for this time span such as "6h15m".

   public String toString() {

        return (totalMinutes / 60) + "h" + (totalMinutes % 60) + "m";

   }

   // method to compare this time span with other

   // returns a negative value if this time span is shorter than other

   // returns 0 if both have same duration

   // returns a positive value if this time span is longer than other

   public int compareTo(TimeSpan other) {

        if (this.totalMinutes < other.totalMinutes) {

            return -1; // this < other

        } else if (this.totalMinutes > other.totalMinutes) {

            return 1; // this > other

        } else {

            return 0; // this = other

        }

   }

}

// TimeSpanClient.java

public class TimeSpanClient {

   public static void main(String[] args) {

        int h1 = 13, m1 = 30;

        TimeSpan t1 = new TimeSpan(h1, m1);

        System.out.println("New object t1: " + t1);

        h1 = 3;

        m1 = 40;

        System.out.println("Adding " + h1 + " hours, " + m1 + " minutes to t1");

        t1.add(h1, m1);

        System.out.println("New t1 state: " + t1);

        // creating another TimeSpan object, testing compareTo method using the

        // two objects

        TimeSpan t2 = new TimeSpan(10, 20);

        System.out.println("New object t2: " + t2);

        System.out.println("t1.compareTo(t2): " + t1.compareTo(t2));

        System.out.println("t2.compareTo(t1): " + t2.compareTo(t1));

        System.out.println("t1.compareTo(t1): " + t1.compareTo(t1));

   }

}

/*OUTPUT*/

New object t1: 13h30m

Adding 3 hours, 40 minutes to t1

New t1 state: 17h10m

New object t2: 10h20m

t1.compareTo(t2): 1

t2.compareTo(t1): -1

t1.compareTo(t1): 0

4 0
2 years ago
What are some ways to accomplish full-duplex (FDX) digital communications on guided medium at the physical layer (OSI Layer 1)?
labwork [276]

Answer:

d. All of the above

Explanation:

Physical layer is the lowest layer of the OSI reference model that deals with the setup of physical connection to the network and with transmission and reception of signals.

Full duplex (FDx) is a bidirectional type of communication system where two end nodes send and receive data signals at the same time, and a single carrier is simultaneously used for dual communication.

To send or receive data, the participating nodes in a Full Duplex system do not have to wait for a free carrier/medium. It employs a medium that has at least two internal channels - one for sending and one for receiving.

Based on the above explanations, options A, B and C are valid and are correct ways to accomplish full-duplex (FDX) digital communications on guided medium at the physical layer (OSI Layer 1). There all of them are correct.

6 0
2 years ago
The tuna marketers' task in the "tunathewonderfish.com" website and related campaign was to ________.
Wewaii [24]
The answer to this question is "to monitor all the elements of the marketing mix for a Oregon winery". This is the main task of the tuna marketer's task in the emailing or website which is very known s tunwonderfish.com and this compaign was exclusively related to the elements of mixing in a large Oregon winery but not including the production.
4 0
2 years ago
Multiply each element in origList with the corresponding value in offsetAmount. Print each product followed by a semicolon (no s
Pavlova-9 [17]

Answer:

Replace /* Your code goes here */  with

for(i =0; i<NUM_VALS; i++) {

    printf("%d", origList[i]*offsetAmount[i]);

printf(";");

}

Explanation:

The first line is an iteration statement iterates from 0 till the last element in origList and offsetAmount

for(i =0; i<NUM_VALS; i++) {

This line calculates and print the product of element in origList and its corresponding element in offsetAmount

    printf("%d", origList[i]*offsetAmount[i]);

This line prints a semicolon after the product has been calculated and printed

printf(";");

Iteration ends here

}

5 0
2 years ago
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