Answer:
- m = 3
- n = 20
-
- triList = []
- current = 0
- for i in range(1, n + 1):
- current = current + i
- if(current >= m and current <= n):
- triList.append(current)
-
- print(triList)
Explanation:
The solution code is written in Python 3.
Firstly, create variable m and n and set the value 3 and 20 to the variables (Line 1 -2)
Create a triangle number list (Line 4) and another variable current to hold the value of current total of triangle number (Line 5).
Create a for loop and iterate through the number between m and n (Line 6). Calculate the current total of triangle number (Line 7) and proceed to check if the current triangle number is bigger or equal to m and smaller and equal to n, add the current triangle number to triList (Line 8-9).
Print the triList (Line 11) and we shall get [3, 6, 10, 15]
The sheave wheel is a pulley wheel that sits above the mine shaft. The hoist cable passes over the sheave wheel and then down the shaft of the mine.
(copied from google)
Well, integrity is a must if you are reading anything. So it would be any website that has either a .edu or a .gov at the end of a URL.
I never suggest Wikipedia for brief, since 100's of people will edit one topic at a time, the answer to what he is looking for is buried in 18 pages about one settler in the United States!
Microwave transmission is ideal for long distance communication. It is so good that it is used for satellite and space probe communication.
Answer:
Python file with appropriate comments given below
Explanation:
#Take the input file name
filename=input('Enter the input file name: ')
#Open the input file
inputFile = open(filename,"r+")
#Define the dictionary.
list={}
#Read and split the file using for loop
for word in inputFile.read().split():
#Check the word to be or not in file.
if word not in list:
list[word] = 1
#increment by 1
else:
list[word] += 1
#Close the file.
inputFile.close();
#print a line
print();
#The word are sorted as per their ASCII value.
fori in sorted(list):
#print the unique words and their
#frequencies in alphabetical order.
print("{0} {1} ".format(i, list[i]));
