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34kurt
1 year ago
12

Please answer this a due tomorrow!!!

Computers and Technology
1 answer:
dem82 [27]1 year ago
5 0

Answer:  

4-Well first of all for the "VR" problem it could be a problem, because people could forget about there actual life and not be able to much of anything when needed.

1-the first one you are going to have to answer.

2-If you have different files then you aren't stumbling through multiple different links and could have trouble with finding what is needed.

3-the third one you are going to have to answer.

5-If I were you I would help them the best way you could so they can actually know how to do their job.

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#Write a function called fancy_find. fancy_find should have #two parameters: search_within and search_for. # #fancy_find should
Inessa05 [86]

Answer:

Here is the Python program:

def fancy_find(search_within , search_for):  # function definition of fancy_find function that takes two parameters

   index = 0  #to store the index of search_within where the search_for string is found

   if search_for in search_within:  #checks if the string search_for is present in string search_within

       sf = search_for[0]  #points to the first character of the search_for

       for sw in search_within:  #iterates through search_within

           if sw == sf:  #if the first character of search_for is equal to the character at sw index of search_within

               if search_within[index:index+len(search_for)] == search_for:  #checks if the value of search_for is found in search_within

                   print(search_for,"found at index",index,"!")  #if above condition is true prints the message "[search_for] found at index [index]!", with [search_for] and [index] replaced by the value of search_for and the index at which it is found

                   return ""  

           index += 1  #increments value of index at each iteration

   print(search_for,"is not found within", search_within)  #if search_for is not found within search_within, prints message "[search_for] was not found within [search_within]!" with the values of search_for and search_within.

   return ""    

#following two statements are used to test the working of above function

print(fancy_find("ABCDEF", "DEF"))  #calls fancy_find() passing "ABCDEF" as search_within and "DEF" as search_for

print(fancy_find("ABCDEF", "GHI")) #calls fancy_find() passing "ABCDEF" as search_within and "GHI" as search_for

Explanation:

The program is well explained in the comments. I will explain the working of the function with the help of an example:

Suppose

search_within = "ABCDEF"

search_for = "DEF"

We have to find if search_for i.e. DEF is present in search_within i.e. ABCDEF

if search_for in search_within statement checks using in operator that if DEF is included in ABCDEF. Here this condition evaluates to true so the next statement sf = search_for[0]  executes which sets the first element of search_for i.e. D to sf. So sf = 'D'

for sw in search_within this statement has a for loop that iterates through ABCDEF and works as following:

At first iteration:

sw contains the first character of search_within  i.e. A

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. A. Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes 1. Hence index=1

At second iteration:

sw contains the second character of search_within  i.e. B

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. B Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  2. Hence index=2

At third iteration:

sw contains the third character of search_within  i.e. C

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. C Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  3. Hence index=3

At fourth iteration:

sw contains the third character of search_within  i.e. D

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. D. Its true so so the program control moves to this statement:

  if search_within[index:index+len(search_for)] == search_for:

current value of index=3

len(search_for) returns the length of DEF i.e. 3

So the if condition checks for the search_for in search_within. The statement becomes:

if search_within[3:3+3] == search_for:

search_within[3:3+3]  means from 3rd index position of search_within to 6-th index position of the search_within. This means from 4th element of search_within i.e. D to the last. Hence search_within[3:3+3] is equal to DEF.

search_for = DEF so

if search_within[3:3+3] == search_for: checks if

search_within[3:3+3] = DEF is equals to search_for = DEF

Yes it is true so

print(search_for,"found at index",index,"!") statement is executef which prints the following message:

DEF found at index 3!

This output is because search_for = "DEF" and index=3

5 0
2 years ago
Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating charac
elena-s [515]

Answer:

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate \lambda = 24 customers per hour or 0.4 customers per minute

Service rate \mu​ = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system , P0 = 1 - \lambda / \mu

= 1 - (24/36) = 1/3 = 0.3333

b.) The average number of customers waiting

Lq = \lambda^2 / [\mu(\mu - \lambda)] = 242 / [36 * (36 - 24)] = 1.33

c.) The average number of customers in the system.

L = Lq + \lambda / \mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = \lambda / [\mu(\mu - \lambda)] = 24 / [36 * (36 - 24)] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1/\mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667

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The term load is often used to describe opening a page in a ____. Answer
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The answer is b web page
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Two career fields that lack minority professionals and thus offer many grant opportunities to students are education and _____.
Ainat [17]
My answer is nursing hopes this helps

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