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Ne4ueva [31]
2 years ago
14

A file named data.txt contains an unknown number of lines, each consisting of a single integer. Write some code that creates two

files, dataplus.txt and dataminus.txt, and copies all the lines of data1.txt that have positive integers to dataplus.txt, and all the lines of data1.txt that have negative integers to dataminus.txt. Zeros are not copied anywhere.
Computers and Technology
2 answers:
slavikrds [6]2 years ago
6 0

Answer:

#section 1

data = open('data.txt', 'r')

num = (data.read())

num = num.split()

data.close()

#section 2  

for x in num:

   x = int(x)

   if x < 0:

       minus = open('dataminus.txt', 'a')

       minus.write(str(x) + ' ')

       minus.close()

   elif x > 0:

       plus = open('dataplus.txt', 'a')

       plus.write(str(x)+' ')

       plus.close()

Explanation:

#section 1

A file data.txt containing an unknown number of lines each containing a single integer is opened.

The data is read from it and split to form a list from which the code will iterate over with a FOR loop and some conditional statements will be used to determine if the number is positive or negative.

#section 2

In this section two new files are created/ opened dataplus.txt and dataminus.txt and all the positive integers are stored in the dataplus.txt and the negative integers in the dataminus.txt.

The IF statement and elif statement used ensures that zero(0) is not captured ensuring that the code fulfills all the requirements in your question.

Damm [24]2 years ago
3 0

Answer:

I am doing it with python.

Explanation:

nums = '9 -8 -7 -6 -5 -4 -2 0 1 5 9 6 7 4'

myfile = open('data.txt', 'w')

myfile.write(nums)

myfile.close()

myfile = open('data.txt', 'r')

num1 = (myfile.read())

num1 = num1.split()

print(num1)

print(type(num1))

for x in num1:

   x = int(x)

   if x < 0:

       minus = open('dataminus.txt', 'a')

       minus.write(str(x) + ' ')

       minus.close()

   elif x>= 0:

       plus = open('dataplus.txt', 'a')

       plus.write(str(x)+' ')

       plus.close()

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Import java.util.scanner; public class sumofmax { public double findmax(double num1, double num2) { double maxval; // note: if-e
jeyben [28]

Here you go,


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   public static double findMax(double num1, double num2) {

       double maxVal = 0.0;

       // Note: if-else statements need not be understood to

       // complete this activity

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       }

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   public static void main(String[] args) {

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       double numB = 10.0;

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       double maxSum = 0.0;

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The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Please find the attached question.

Answer:

a) SQL Query:

SELECT population

FROM bsg_planets

WHERE name='Caprica';

b) SQL Query:

SELECT fname, lname, age

FROM bsg_people

WHERE lname!='Adama';

c) SQL Query:

SELECT name, population

FROM bsg_planets

WHERE population > 2600000000

d) SQL Query:

SELECT fname, lname, age

FROM bsg_people

WHERE age IS NULL;

Explanation:

a) Write a SQL query to find the population of the planet named 'Caprica'

Syntax:

SELECT  Column

FROM TableName

WHERE Condition;

For the given case,

Column = population

TableName  = bsg_planets

Condition = name='Caprica'

SQL Query:

SELECT population

FROM bsg_planets

WHERE name='Caprica';

Therefore, the above SQL query finds the population of the planet named 'Caprica' from the table bsg_planets.

b) Find the first name, last name, and age of people from bsg_people whose last name is not 'Adama'

Syntax:

SELECT  Column1, Column2, Column3

FROM TableName

WHERE Condition;

For the given case,

Column1 = fname

Column2 = lname

Column3 = age

TableName  = bsg_people

Condition = lname!='Adama'

SQL Query:

SELECT fname, lname, age

FROM bsg_people

WHERE lname!='Adama';

Therefore, the above SQL query finds the first name, last name and age of people whose last name is not 'Adama' from the table bsg_people.

c) Find the name and population of the planets with a population larger than 2,600,000,000

Syntax:

SELECT  Column1, Column2

FROM TableName

WHERE Condition;

For the given case,

Column1 = name

Column2 = population

TableName  = bsg_planets

Condition = population > 2600000000

SQL Query:

SELECT name, population

FROM bsg_planets

WHERE population > 2600000000

Therefore, the above SQL query finds the name and population of the planets with a population larger than 2,600,000,000 from the table bsg_planets.

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Syntax:

SELECT  Column1, Column2, Column3

FROM TableName

WHERE Condition;

For the given case,

Column1 = fname

Column2 = lname

Column3 = age

TableName  = bsg_people

Condition = age IS NULL

SQL Query:

SELECT fname, lname, age

FROM bsg_people

WHERE age IS NULL;

Therefore, the above SQL query finds the first name, last name and age of people whose age is NULL from the table bsg_people.

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Answer:

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Explanation:

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