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ludmilkaskok [199]
2 years ago
10

Data is: a. Information endowed with relevance and purpose b. Set of specific objective facts or observations c. Some informatio

n d. All of the above e. Only a and c
Computers and Technology
1 answer:
Maru [420]2 years ago
4 0

Answer: b) Set of specific objective facts or observations

Explanation: Data is referred as the information that consumes the facts and figures . These facts and figure information is usually viewed or observed in the form of images, text, facts, graphs,reports etc.Data of any sort has to be stored for any use or analyzing in future so it is generally stored in the computer and other devices.Therefore,option(b) is the correct option.

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Each of these is a basic type of a touch screen, except ________.
Oksanka [162]
<span>A touch screen gives response and acts simply with a touch on the screen area. Reflective screen is not a basic type of touch screen. The reflection can be reduced for the touch screen when it is combined with the LCD and the screen still be very visible. These screens can be anti glare and safe to the eyes.</span>
8 0
2 years ago
Read 2 more answers
The given SQL creates a Movie table with an auto-incrementing ID column. Write a single INSERT statement immediately after the C
Snowcat [4.5K]

Answer:

INSERT INTO Movie(Title,Rating,ReleaseDate)

VALUES("Raiders of the Lost ArkPG",'PG',DATE '1981-06-15'),

("The Godfaher",'R',DATE '1972-03-24'),

("The Pursuit of Happyness",'PG-13',DATE '2006-12-15');

Explanation:

The SQL statement uses the "INSERT" clause to added data to the movie table. It uses the single insert statement to add multiple movies by separating the movies in a comma and their details in parenthesis.

3 0
1 year ago
In database software, a record is a
Rzqust [24]

Answer:

In database software a record is a group of related data held within the same structure.

4 0
2 years ago
Taylor and Rory are hosting a party. They sent out invitations, and each one collected responses into dictionaries, with names o
disa [49]

Answer:

Following are the code to this question:

def combine_guest(guest1, guest2):#defining a method combine_guest that accepts two dictionary

   guest2.update (guest1)#use dictionary guest2 that use update method to update guest2 dictionary

   return guest2#return guest2 dictionary values

Rory_guest= { "Ada":2, "Ben":3, "Dav":1, "Jo":3, "Charry":2, "Terry":1, "bob":4}#defining a dictionary and add value

Taylor_guest = { "Dav":4, "Nan":1, "bobert":2, "Ada":1, "Samantha":3, "Chr":5}#defining a dictionary and add value

print(combine_guest(Rory_guest,Taylor_guest))#calling the combine_guest method

Output:

{'Nan': 1, 'Samantha': 3, 'Ada': 2, 'bob': 4, 'Terry': 1, 'Jo': 3, 'Ben': 3, 'Dav': 1, 'Charry': 2, 'bobert': 2, 'Chr': 5}

Explanation:

In the code a method, "combine_guest" is defined, that accepts two dictionaries "guest1, guest2" inside the method, in which the "guest2" dictionary uses the update method to combine the value of the guest1 dictionary and use a return keyword to return guest2 values.

In the next step, two dictionaries are declared, that holds some values and use a print method to call the "combine_guest" method and prints its return values.  

7 0
1 year ago
Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their
vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.6)+ \frac{0.6}{k} }  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

7 0
2 years ago
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