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Paha777 [63]
2 years ago
12

Write a function named max that accepts two integer values as arguments and returns the value that is the greater of the two. Fo

r example, if 7 and 12 are passed as arguments to the function, the function should return 12. Use the function in a program that prompts the user to enter two integer values. The program should display the value that is the greater of the two
Computers and Technology
1 answer:
RoseWind [281]2 years ago
6 0

Answer:

The solution code is written in Python

  1. def max(a, b):
  2.    if(a > b):
  3.        return a  
  4.    else:
  5.        return b
  6. num1 = int(input("Please input the first number: "))
  7. num2 = int(input("Please input the second number: "))
  8. print(max(num1, num2))

Explanation:

Firstly create a function max that accepts two input, a and b, as required by question (Line 1). In the function, create if statement to check if a greater than b return a and vice versa (Line 2 -5).

In the main program (Line 7 - 10), prompt user to input two numbers (Line 7 - 8). At last call the function by passing num1 and num2 as arguments and print the result (Line 10).

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The fourth choice is correct.
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Susie works for an architectural firm and the partners have always drawn the plans for projects by hand. Though Susie learned ho
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Answer:

The correct answer to the following question will be CAD.

Explanation:

CAD - It stands for Computer-aided Design. CAD is a software used for creating some 3D designs, creative drawing or some technical illustrations and is basically used by the engineers and artists.

Many projects based on electronic can be designed with the help of this software, electronic parts like circuit boards, etc.

Various types of CAD are as follows :

  • 2D (Two dimensional)
  • 3D (Three dimensional)
  • 3D wire frame
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This enables efficiency in design's quality, also increase in engineer and artist's productivity. So, many of the computer programs should recommend the Computer-aided design software to there project partners for some 3D and effective look on their project.

3 0
2 years ago
You cannot change data directly in the PivotTable. Instead, you must edit the Excel table, and then ____, or update, the PivotTa
Fudgin [204]

Answer:

d. refresh

Explanation:

The Excel software does not allow a user to change values/data directly in the Pivottable. You will get an error message like "Cannot change this part of a PivotTable report" when you try to type data directly.  You will have to edit the Excel Table and then refresh to reflect the updated data.

5 0
2 years ago
Read 2 more answers
Given 4 integers, output their product and their average, using integer arithmetic.
solmaris [256]

Answer:

see explaination

Explanation:

Part 1:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

int avg=0, pro=1;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4;

pro = num1*num2*num3*num4;

System.out.println(pro+" "+avg);

}

}

------------------------------------------------------------------

Part 2:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

double avg=0, pro=1; //using double to store floating point numbers.

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4.0; //if avg is declared as a float, then use 4.0f

pro = num1*num2*num3*num4;

System.out.println((int)pro+" "+(int)avg); //using type conversion only integer part

System.out.printf("%.3f %.3f\n",pro,avg);// \n is for newline

}

}

8 0
2 years ago
Create the class named SortFile. The class will have a single attribute, which is an ArrayList of integers. The class will have
S_A_V [24]

Answer:

See explaination

Explanation:

//SortFile.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

public class SortFile {

// array list of integers to store the numbers

private ArrayList<Integer> list;

// default constructor

public SortFile() {

// initializing list

list = new ArrayList<Integer>();

// reading file name using a scanner

Scanner sc = new Scanner(System.in);

System.out.print("Enter file name: ");

String filename = sc.nextLine();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

// opening file

sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

// closing file

sc.close();

} catch (FileNotFoundException e) {

// exception occurred.

System.err.println(e);

}

}

// constructor taking a file name

public SortFile(String filename) {

// initializing list

list = new ArrayList<Integer>();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

Scanner sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

sc.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

}

// method to return a sorted array of integers containing unique elements

// from list

public int[] sort() {

// creating an array of list.size() size

int arr[] = new int[list.size()];

// count of unique (non duplicate) numbers

int count = 0;

// looping through the list

for (int i = 0; i < list.size(); i++) {

// fetching element

int element = list.get(i);

// if this element does not appear before on list, adding to arr at

// index=count and incrementing count

if (!list.subList(0, i).contains(element)) {

arr[count++] = element;

}

}

// now reducing the size of arr to count, so that there are no blank

// locations

arr = Arrays.copyOf(arr, count);

// using selection sort algorithm to sort the array

int index = 0;

// loops until index is equal to the array length. i.e the whole array

// is sorted

while (index < arr.length) {

// finding the index of biggest element in unsorted array

// initially assuming index as the index of biggest element

int index_max = index;

// looping through the unsorted part of array

for (int i = index + 1; i < arr.length; i++) {

// if current element is bigger than element at index_max,

// updating index_max

if (arr[i] > arr[index_max]) {

index_max = i;

}

}

// now we simply swap elements at index_max and index

int temp = arr[index_max];

arr[index_max] = arr[index];

arr[index] = temp;

// updating index

index++;

// now elements from 0 to index-1 are sorted. this will continue

// until whole array is sorted

}

//returning sorted array

return arr;

}

//code for test-run

public static void main(String[] args) {

//initializing SortFile using default constructor

SortFile sortFile = new SortFile();

//displaying sorted array

System.out.println(Arrays.toString(sortFile.sort()));

}

6 0
2 years ago
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