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Anuta_ua [19.1K]
2 years ago
11

Frequency of failure and network recovery time after a failure are measures of the _______ of a network.

Computers and Technology
1 answer:
coldgirl [10]2 years ago
8 0
Frequency of a failure and network recovery time after a failure are measures of the Reliability of a network
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Strlen("seven"); what is the output?
Leokris [45]

Answer:

A is your answer hope this helps

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What are the set of rules to move data from one computer to another?
ss7ja [257]
I don't believe that there are rules.
Hope I helped,
 Ms. Weasley
4 0
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Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255
maxonik [38]

Answer:

Follows are the code to this question:

#include <iostream>//defining a header file

using namespace std; //using namespace

int main() //defining main method

{

int red,green,blue,s; //defining integer variable

cout<<"Enter value: \n ";//print message

cin>>red>>green>>blue; //input value

if(red<green && red<blue)//defining if block that checks red value

s=red;//store red variable value to s variable

else if(green<blue)//defining else if block that checks green value less then blue

s=green;//store green variable value in s variable

else//defining else block

s=blue; //store blue variable value in s variable

//calculating red, green, blue value

red=red-s;//store red value

green=green-s;//store green value

blue=blue-s;//store blue value

cout<<red<<" "<<green<<" "<<blue;

}

Output:

Enter value:

130  

50

130

80 0 80

Explanation:

In the above code, inside the Main method, four integer variable "red, green, blue, and s" is defined, in which "red, green, and blue" is used for input the value from the user end.

  • In the next step, a conditional statement is used, that checks the red variable value, if the condition is true, it will store its value in the "s" variable, otherwise, it will go to else if block.
  • In this block, the green variable checks its value less than then blue variable value, if the condition is true, it will store the green value in the "s" variable, otherwise, it will goto else block.
  • In this block, it will store the blue variable value in the "s" variable, and subtract the value of "red, green, and blue" value from "s" and store its value, and at the last, it will print its value.    
4 0
2 years ago
American company Software Unlimited is planning to expand its operations to the Bangor Republic where the group is the primary u
FinnZ [79.3K]

Answer:E. Employees will achieve close cooperation with others.

Explanation: Employees will close cooperation with others as a result of the expansion of the company to the Bangor Republic where the group is the primary unit of social organisation, When a company expands to new locations it boosts employment morale and corporation as they find it as a form of expansion and overall good of the employees and their employer, most of expand as a result of favourable economic climates.

7 0
2 years ago
There are N bulbs numbered from 1 to N, arranged in a row. The first bulb is plugged into the power socket and each successive b
Ksivusya [100]

Answer:

The code is given below with appropriate comments

Explanation:

// TestSolution class implementation

import java.util.Arrays;

public class TestSolution

{

  // solution function implementation

  public static int solution(int[] arr)

  {

      // declare the local variables

      int i, j, count = 0;

      boolean shines;

     

      // use the nested loops to count the number of moments for which every turned on bulb shines

      for (i = 0; i < arr.length; i++)

      {

          shines = true;

          for (j = i + 1; j < arr.length && shines; j++)

          {

              if (arr[i] > arr[j])

                  shines = false;

          }

          if (shines)

              count++;

      }

      // return the number of moments for which every turned on bulb shines

      return count;

     

  } // end of solution function

 

  // start main function

  public static void main(String[] args)

  {

      // create three arrays named A, B, and C

      int[] A = {2, 1, 3, 5, 4};

      int[] B = {2, 3, 4, 1, 5};

      int[] C = {1, 3, 4, 2, 5};

     

      // generate a random number N within the range range[1..100000]

      int N = 1 + (int)(Math.random() * 100000);

     

      // create an array named D of size N

      int[] D = new int[N];

     

      // fill the array D with the distinct random numbers within the range [1..N]

      int i = 0;

      while(i < N)

      {

          int num = 1 + (int)(Math.random() * N);          

          boolean found = false;

          for(int j = 0; j < i && !found; j++)

          {

              if(D[j] == num)

                  found = true;

          }

         

          if(!found)

          {

              D[i] = num;

              i++;

          }

      }          

     

      // print the elements and number of moments of the arrays A, B, and C

      System.out.println("Array A: " + Arrays.toString(A) + " and Moments: " + solution(A));

      System.out.println("Array B: " + Arrays.toString(B) + " and Moments: " + solution(B));

      System.out.println("Array C: " + Arrays.toString(C) + " and Moments: " + solution(C));

     

      // print the size and number of moments of the array D

      System.out.println("Size(N) of Array D: " + N + " and Moments: " + solution(D));

     

  } // end of main function

} // end of TestSolution class

3 0
2 years ago
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