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choli [55]
2 years ago
6

Our new catalog contains an eclectic collection of items

Computers and Technology
1 answer:
Cloud [144]2 years ago
7 0

Answer: .

Explanation: .

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Write a copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *thi
Olin [163]

The following cose will be used to copy assignment operator for CarCounter

<u>Explanation:</u>

Complete Program:

#include <iostream>

using namespace std;

class CarCounter

{

public:

CarCounter();

CarCounter& operator=(const CarCounter& objToCopy);

void SetCarCount(const int setVal)

{

 carCount = setVal;

}

int GetCarCount() const

{

 return carCount;

}

private:

int carCount;

};

CarCounter::CarCounter()

{

carCount = 0;

return;

}

// FIXME write copy assignment operator

/* Your solution goes here */

CarCounter& CarCounter::operator=(const CarCounter& objToCopy)

{

if(this != &objToCopy)

 carCount = objToCopy.carCount;

return *this;

}

int main()

{

CarCounter frontParkingLot;

CarCounter backParkingLot;

frontParkingLot.SetCarCount(12);

backParkingLot = frontParkingLot;

cout << "Cars counted: " << backParkingLot.GetCarCount();

cout << endl << endl;

system("pause");

return 0;

}

5 0
2 years ago
Write a loop to populate the list user_guesses with a number of guesses. The variable num_guesses is the number of guesses the u
Masja [62]

Answer:

num_guesses = int(input())

user_guesses = []

for i in range(num_guesses):

    x = int(input())

    user_guesses.append(x)

   

print(user_guesses)

Explanation:

This solution is provided in Python

This line prompts the user for a number of guesses

num_guesses = int(input())

This line initializes an empty list

user_guesses = []

This loop lets user input each guess

for i in range(num_guesses):

This line takes user input for each guess

    x = int(input())

This appends the input to a list

    user_guesses.append(x)

This prints the user guesses    

print(user_guesses)

6 0
1 year ago
What is the output of 1101 x 10 == 11000 + 10?
Marta_Voda [28]
== is an operator that returns a boolean if both operand are equal.

1101 * 10 is 11010

11000 + 10 is 11010


11010 == 11010

Thus the output would be True.
5 0
2 years ago
Mobile computing has two major characteristics that differentiate it from other forms of computing. What are these two character
olya-2409 [2.1K]

Answer:

mobility and broad reach  

Explanation:

The two major characteristics of mobile computing are:

Mobility: It basically refers to the portability. Mobility means that users can carry their mobile device wherever they go. This facilitates real-time communication with other devices. Users can take a mobile device anywhere and can contact with other devices and systems via a wireless network for example a user, wherever he happens to be, can log in to his email account to check his emails using his mobile phone.

Broad Reach: It basically means that the mobile device users can be reached at any time. This means that the users of an open mobile device can be instantaneously contacted. Having an open mobile device means that it can be reached by or connected to other mobile networks. However mobile users also have options to restrict specific messages or calls.

6 0
2 years ago
#A year is considered a leap year if it abides by the #following rules: # # - Every 4th year IS a leap year, EXCEPT... # - Every
lara [203]

Answer:

To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.

Similarly check for 400th year and multiple 0f 4. The following C program describes the function.

#include<stdio.h>

#include<stdbool.h>

bool is_leap_year(int year);

void main()

{

int y;

bool b;

 

printf("Enter the year in yyyy format: e.g. 1999 \n");

scanf("%d", &y);     // taking the input year in yyyy format.

 

b= is_leap_year(y);  //calling the function and returning the output to b

if(b==true)

{

 printf("Thae given year is a leap year \n");

}

else

{

 printf("The given year is not a leap year \n");

}

}

bool is_leap_year(int year)

{

if(year%100==0)   //every 100th year

{

 if(year%400==0)   //every 400th year

 {

  return true;

 }

 else

 {

  return false;

 }

}

if(year%4==0)  //is a multiple of 4

{

 return true;

}

else

{

 return false;

}

}

Explanation:

Output is given as image

5 0
2 years ago
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