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2 years ago

13

What helps companies and organizations to target masses of people, provide 24/7 services, and deliver better marketing in a chea

per and easier way?

Computers and Technology

2 answers:

Rus_ich [418]2 years ago

8 1

Answer:

i think its "Smartphones"

Explanation:

Guest

1 year ago

your wrong

VLD [36.1K]2 years ago

5 1

Simple. Advertising fits all of the criteria listed.

Guest

1 year ago

your wrong

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3.A customer has a system with a Gigabyte B450 Aorus Pro motherboard. He wants to upgrade the processor from the AMD Athlon X4 9

Burka [1]

Answer:

The upgrade is possible and it will yield a remarkable increase in performance

Explanation:

It is a newer product, there is tendency of having a better application compatibility/performance

It has much higher multi threaded performance which is around 522% higher. This allows for higher performance in professional applications like encoding and heavy multitasking compared to the previous.

When considering gaming, it has higher performance compared to the previous.

5 0

2 years ago

Which of the following is an object such as a field which can be inserted into a document

ivanzaharov [21]

Answer:

SORRY but U have to make a new question.

Explanation:

bc u put which is the following is ..... u did not put the following

cant help on this one.

8 0

2 years ago

Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times

otez555 [7]

Answer:

The program written in python is as follows

def countchr(phrase, char):

count = 0

for i in range(len(phrase)):

if phrase[i] == char:

count = count + 1

return count

phrase = input("Enter a Phrase: ")

char = input("Enter a character: ")

print("Occurence: ",countchr(phrase,char))

Explanation:

To answer this question, I made use of function

This line defines function countchr

def countchr(phrase, char):

This line initializes count to 0

count = 0

This line iterates through each character of input phrase

for i in range(len(phrase)):

This line checks if current character equals input character

if phrase[i] == char:

The count variable is incremented, if the above condition is true

count = count + 1

The total number of occurrence is returned using this line

return count

The main method starts here; This line prompts user for phrase

phrase = input("Enter a Phrase: ")

This line prompts user for a character

char = input("Enter a character: ")

This line prints the number of occurrence of the input charcater in the input phrase

print("Occurence: ",countchr(phrase,char))

4 0

2 years ago

Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing

Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

$t=\frac{1 }{(S + (1- S)/N) }$

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

$t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671$

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

$t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181$

Speedup gain is 1.81 times.

8 0

2 years ago

Given 4 integers, output their product and their average, using integer arithmetic.

solmaris [256]

Answer:

see explaination

Explanation:

Part 1:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

int avg=0, pro=1;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4;

pro = num1*num2*num3*num4;

System.out.println(pro+" "+avg);

}

}

------------------------------------------------------------------

Part 2:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

double avg=0, pro=1; //using double to store floating point numbers.

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4.0; //if avg is declared as a float, then use 4.0f

pro = num1*num2*num3*num4;

System.out.println((int)pro+" "+(int)avg); //using type conversion only integer part

System.out.printf("%.3f %.3f\n",pro,avg);// \n is for newline

}

}

8 0

2 years ago