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1 year ago

What company built its first computer from a wooden box

Computers and Technology

2 answers:

Blizzard [7]1 year ago

7 0

Apple built the Apple 1 in 1976. The personal computer had a circuit board that was placed into a wooden box, to become the first computer built by Steve Jobs and Steve Wozniak. This was the company’s first personal computer.

tatyana61 [14]1 year ago

6 0

Answer:

Apple Computers

Explanation:

In 1976 Apple was founded, with partners Steve Jobs (still active today) and Steve Wozniak, who, while not as well-known as the partner, did almost all the hard work of development. A curiosity is that Apple was only founded because the Apple I project (developed by the two in their spare time) was rejected by Atari and HP.

The Apple I was sold already assembled. The board was sold “naked”, mounted on a wooden board and packed in a cardboard box, so it was common for Apple I to be installed inside handcrafted wooden boxes.

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1. Discuss why it is so important for all application builders to always check data received from unknown sources, such as Web a

Ivan

Answer:

1. It is so important for all application builders to always check data received from unknown sources before using that data. This is because of the Security related reasons and vulnerabilities .For example the data received might contain harmful hidden viruses. Web applications are accessed by internet and these are the most vulnerable to attacks by hacker or intruders using harmful data containing malware. This can cause security breaches due to the security flaws or bugs in Web applications. So to overcome such security risks which can cause damage in the Web applications, data from unknown sources should be checked.

Explanation:

2. When the Website is being used and running, there is a room for possible glitches or other bugs and issues. To understand, handle and address issues successfully, the website operators carefully and consistently patch and configure their systems. The administrators collect the user data which enables them to have enough data in order to make the requisite alterations or improvements in the website. This also helps to improve the website performance. The patching and configuring of systems fix problems in the website which reduces the risk of website damage and the website works smoothly this way. Moreover it identifies vulnerabilities, solve configuration issues and upgrades in website features provide additional capabilities to the website.

8 0

1 year ago

Write a program whose input is two integers and whose output is the two integers swapped. Place the values in an array, where x

Aliun [14]

Answer:

import java.util.Arrays;

public class swap{

public static void main(String []args){

int [] arr = {2,4};

swapValues(arr);

}

public static void swapValues(int[] values){

int temp;

System.out.println(Arrays.toString(values));

temp=values[0];

values[0]=values[1];

values[1] =temp;

System.out.println(Arrays.toString(values));

}

Explanation:

In the program above, we created the method swapValues that receives an array of integers as parameters. in the method definition, we created a temp variable that is used to swapp the element at index 0 and index 1. Java's Arrays.to string method is used to print the array before and after the swap.

7 0

2 years ago

Drag each tile to the correct box.

garri49 [273]

I think select the video insert select the movie option under illustrations resize the video player then select the insert tab i’m not 100 percent sure tho

8 0

2 years ago

Read 2 more answers

Program documentation _____. Group of answer choices describes the inputs, outputs, and processing logic for all program modules

valentinak56 [21]

Answer:

In the given question the first line is correct, i.e. "Describes the inputs, outputs, and processing logic for all program modules".

Explanation:

The documentation is a recorded text or image, which is preceding or in the code base of the programs, whether it describes how well the program works and how it is being used, and things in various positions can be influenced by people, and the wrong option can be described as follows:

In the documentation, it can't consist of rules and data.
In can't include a dictionary, flow maps, screen designs and device requests that began the program.
In can't provide links within the program.

6 0

2 years ago

For the (pseudo) assembly code below, replace X, Y, P, and Q with the smallest set of instructions to save/restore values on the

Dimas [21]

Answer:

Explanation:

Let us first consider the procedure procA; the caller in the example given.

Some results: $s0,$s1,$s2, $t0,$t1 and $t2 are being stored by procA. Out of these registers, few registers are accessing by procA after a call to procB. But, procB might over-write these registers.

Thus, procA need to save some registers into stack first before calling procB, .

only $s1,$t0 and $t1 are being used after return from procB in the given example,

Caller saves and restores only values in $t0-$t9, according to MIPS guidelines for caller-saved and callee-saved registers, .

Thus, procA needs to save only $t0 and $t1.

jal instruction overwrites the register $ra by writing the address, to which the control should jump back, after completing the instructions of procB, when procB is called,.

Therefore, procA also need to save $ra into stack.

ProcA is writing new values into $a0,$a2, procA must save $a0 and $a1 first before calling procB, .

In the given example, after return from procB, only $a0 is being used. It is therefore enough to save $a0.

Also, procA needs to save frame pointer, which points the start of the stack space for each procedure.

Generally, as soon as the procedure begins, frame pointer is set to the current value of the stack pointer,.

Let us consider the procedure procB; the callee in the given example.

The callee is responsible for saving values in $s0-$s7 and restoring them before returning to caller, this is according to MIPS guidelines for caller-saved and callee-saved registers,

procB is expected to over-write the registers $s2 and $t0. Nonetheless, in the first two lines, procB might over-write the registers $s0 and $s1.

Thus, procB is responsible for saving and restoring $s0,$s1 and $s2.

We need to create space for 5 values on the stack since procA needs to save $a0,$ra,$t0,$t1 and $fp(frame pointer), . Each value(word) takes 4 bytes.

$sp = $sp – 20 # on the stack, create space for 5 values

sw $a0, 16($sp) # store the result in $a0 into the memory address

# indicated by $sp+20

sw $ra, 12($sp) # save the second value on stack

sw $t0, 8($sp) # save the third value on stack

sw $t1, 4($sp) # save the fourth value on stack

sw $fp, 0($sp) # To the stack pointer, save the frame pointer

$fp = $sp # To the stack pointer, set the frame pointer

lw $fp, 0($sp) # from stack, start restoring values

lw $t1, 4($sp)

lw $t0, 8($sp)

lw $ra, 12($sp)

lw $a0, 16($sp)

$sp = $sp + 20 # decrease the size of the stack

$sp = $sp – 12 # for three values, create space on the stack

sw $s0, 0($sp) # save the value in $s0

sw $s1, 0($sp) # save the value in $s1

sw $s2, 0($sp) # save the value in $s2

lw $s0, 0($sp) # from the stack, restore the value of $s0

lw $s1, 0($sp) # from the stack, restore the value of $s1

lw $s2, 0($sp) # from the stack, restore the value of $s2

$sp = $sp + 12 # decrease the stack size

8 0

2 years ago