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2 years ago

If I execute the expression x <- 4L in R, what is the class of the object `x' as determined by the `class()' function?

Computers and Technology

1 answer:

FinnZ [79.3K]2 years ago

7 0

Answer:

integer

Explanation:

The expression can be implemented as follows:

x <- 4L

class(x)

Here x is the object. When this expression is executed in R, the class "integer" of object 'x' is determined by the class() function. R objects for example x in this example have a class attribute determines the names of the classes from which the object inherits. The output of the above expression is:

"integer"

Here function class prints the vector of names of class i.e. integer that x inherits from. In order to declare an integer, L suffix is appended to it. Basically integer is a subset of numeric. If L suffix is not appended then x<-4 gives the output "numeric". Integers in R are identified by the suffix L while all other numbers are of class numeric independent of their value.

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laiz [17]

Answer:

FileOutputStream out = new FileOutputStream("ObjectData.dat");

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ostream.writeObject(r);

Explanation:

For object serialization, we can use the writeObject method of java.io.ObjectOutputStream class.

The complete code fragment is as follows:

import java.io.*;

class Demo{

public static void main(String args[]){

try{

r = <Reference to Object to be serialized> ;

FileOutputStream out = new FileOutputStream("ObjectData.dat");

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ostream.writeObject(r);

ostream.close();

} catch(Exception e){

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}

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2 years ago

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lorasvet [3.4K]

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2 years ago

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Elis [28]

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Explanation:

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2 years ago

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Luden [163]

Answer:

The answer is "False"

Explanation:

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blsea [12.9K]

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7 0

1 year ago