If I execute the expression x <- 4L in R, what is the class of the object `x' as determined by the `class()' function?
1 answer:
Answer:
integer
Explanation:
The expression can be implemented as follows:
x <- 4L
class(x)
Here x is the object. When this expression is executed in R, the class "integer" of object 'x' is determined by the class() function. R objects for example x in this example have a class attribute determines the names of the classes from which the object inherits. The output of the above expression is:
"integer"
Here function class prints the vector of names of class i.e. integer that x inherits from. In order to declare an integer, L suffix is appended to it. Basically integer is a subset of numeric. If L suffix is not appended then x<-4 gives the output "numeric". Integers in R are identified by the suffix L while all other numbers are of class numeric independent of their value.
You might be interested in
Solution :
class Employee:
#Define the
#constructor.
def ____(
, ID_number,
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict