If I execute the expression x <- 4L in R, what is the class of the object `x' as determined by the `class()' function?
1 answer:
Answer:
integer
Explanation:
The expression can be implemented as follows:
x <- 4L
class(x)
Here x is the object. When this expression is executed in R, the class "integer" of object 'x' is determined by the class() function. R objects for example x in this example have a class attribute determines the names of the classes from which the object inherits. The output of the above expression is:
"integer"
Here function class prints the vector of names of class i.e. integer that x inherits from. In order to declare an integer, L suffix is appended to it. Basically integer is a subset of numeric. If L suffix is not appended then x<-4 gives the output "numeric". Integers in R are identified by the suffix L while all other numbers are of class numeric independent of their value.
You might be interested in
Answer:
Answer is in the provided screenshot! This was a lot of fun to make!
Explanation:
We need to create a new Array which has to be the size of amount * original - as we now that we are going to have that many elements. Then we just iterate through all the values of the new array and set them equal to each of the elements in order.
Ignore the code in my main function, this was to print to the terminal the working code - as you can see from the output at the bottom!
