Answer:
C. bachelor’s degree in filmmaking
Explanation:
Because Andy wants to become a multimedia producer, the degree that would best help him achieve his goal is a bachelor's degree in filmmaking.
Multimedia has to do with both audio, video and graphics or animations because it encompasses multiple media files.
Filmmaking has to do with the various forms of making and producing films. Filmmaking has to do with multiple media (multimedia) and it would help him achieve his goal.
Answer:
Written in Java
public static void printArray(int myarr[], String s){
for(int i = 0; i<myarr.length;i++){
System.out.print(myarr[i]+s);
}
}
Explanation:
This defines the static method alongside the array and the string variable
public static void printArray(int myarr[], String s){
The following iteration iterates through the elements of the array
for(int i = 0; i<myarr.length;i++){
This line prints each element of the array followed by the string literal
System.out.print(myarr[i]+s);
}
}
The method can be called from main using:
<em>printArray(myarr,s);</em>
Where myarr and s are local variables of the main
Answer:
2^7= 128
Explanation:
An instruction format characterizes the diverse part of a guidance. The fundamental segments of an instruction are opcode and operands. Here are the various terms identified with guidance design: Instruction set size tells the absolute number of guidelines characterized in the processor. Opcode size is the quantity of bits involved by the opcode which is determined by taking log of guidance set size. Operand size is the quantity of bits involved by the operand. Guidance size is determined as total of bits involved by opcode and operands.
Answer:
I get 0x55 and this the linking address of the main function.
use this function to see changes:
/* bar6.c */
#include <stdio.h>
char main1;
void p2()
{
printf("0x%X\n", main1);
}
Output is probably 0x0
you can use your original bar6.c with updaated foo.c
char main;
int main() // error because main is already declared
{
p2();
//printf("Main address is 0x%x\n",main);
return 0;
}
Will give u an error
again
int main()
{
char ch = main;
p2(); //some value
printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()
printf("Char value is 0x%x\n",ch); //last two digit of previous line output
return 0;
}
So the pain in P2() gets the linking address of the main function and it is different from address of the function main.
Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...
Explanation:
Hello <span>Pouerietzach
Question: </span><span>Which of the following are recommended techniques for protecting computer files and data? Check all of the boxes that apply.
</span><span>
Answer: A, B, D, E, G
Hope That Helps
-Chris</span>
