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andrezito [222]
1 year ago
14

What technology gets its name from the notion that it ignores the traditional A, B, and C class designations for IP addresses?

Computers and Technology
1 answer:
goblinko [34]1 year ago
3 0

Answer:

Classless Inter-Domain Routing

Explanation:

Classless Inter-Domain Routing (CIDR), pronounced “cider” or “sidder,” gets its name from the notion that it ignores the traditional A, B, and C class designations for IPv4 addresses and sets the network-host ID boundary wherever it wants to, in a way that simplifies routing across the resulting IP address spaces.

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Under what category of programs and apps do databases and enterprise computing fall?
Evgesh-ka [11]
Answer is productivity

Sometimes called the office or personal productivity software, productivity software is dedicated to producing databases, spreadsheets, charts, graphs, documents, graphs, digital video and worksheets. Reason behind the name productivity is due to the fact that it increases productivity in office work.

6 0
1 year ago
An expression containing the operator && is true either or both of its operands are true. True/False
Luba_88 [7]

Answer:

True.

Explanation:

An expression containing the && and  operator is only true if both of the operands present in the expression are true otherwise it will give the result as false if either one of them is false or both of them are false.In the question it states that the expression in true either or both of it's operand are true.

Hence the answer is true.

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1 year ago
g Fill the validateForm function to check that the phone number is 10 characters long and that the user name is less than 11 cha
Rom4ik [11]

Answer:

function validateForm(event)

{

event.preventDefault();

var phoneNumber = form.phoneNumber.value;

var userName = form.userName.value;

if(phoneNumber.length!=10)

console.log("Phone Number is Invalid");

if(userName.length<11)

console.log("User Name is Invalid"); }

8 0
1 year ago
Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we c
boyakko [2]

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

\lambda (N) = \ lcm( \lambda  (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)  where \lambda is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from 1and gcd(E,  \lambda (N) ) = 1; that is E \ \ and  \ \ \lambda (N).  D was its complex number equivalent to E (modulo \lambda (N) ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo \lambda (N) ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and \lambda (N) will also be confined as they can be used in measuring D. The Euler totient operates \varphi (N) = (P-1)(Q - 1) however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because \varphi (N), which can always be split into  \lambda (N), and thus any D satisfying DE ≡ 1, it can also satisfy (mod  \lambda (N)). It works because \varphi (N), will always be divided by \varphi (N),. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   \lambda (N) ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   \lambda (N). if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  \lambda (N).

As there are common threads (P− 1) and (Q – 1) which are present throughout the N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1)), it's also possible, if there are any, for all the common factors (P -1) \ \ \ and \ \ (Q - 1)to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module \varphi (N)) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

8 0
1 year ago
Another solution to minimize resonance is to ________ the bridge.
lakkis [162]
I believe the answer is d
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