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masya89 [10]
2 years ago
9

What is the value of x after each of the following statements is encountered in a computer program, if x=1 before the statement

is reached? Please, justify your answer.
a) if (1+2=3) then x:=x+1
b) if ((1+1=3) OR (2+2=3)) then x:=x+1
c) if ((2+3=5) AND (3+4=7)) then x:=x+1
Computers and Technology
1 answer:
steposvetlana [31]2 years ago
5 0

Answer:

x=2

x=1

x=2

Explanation:

a)

This if statement if (1+2=3) checks if the addition of two numbers 1 and 2 is true. Here the addition of 1 and 2 is 3 which is true. So the condition becomes true.

Since the condition is true x:=x+1 statement is executed. This statement means that the value of x is incremented by 1.

The value of x was 1 before the if statement is reached. So x:=x+1 statement will add 1 to that value of x.

x:=x+1 means x=x+1 which is x=1+1 So x=2

Hence value of x is 2 (x=2) after the execution of x:=x+1

b)

In statement b the value of x will be 1 because both the mathematical operations in the if statement evaluate to false.

which means in b, x:=x+1 will not be executed and value of x remains unchanged i.e x=1

In (c) the value x will be 2 because the condition in the if statement is true. Both mathematical expressions 2+3=5 and 3+4=7 are true. Therefore x:=x+1 will be executed and value of x will be incremented by 1. Hence x=2

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STatiana [176]

Answer:

24 customers

Explanation:

Given

Customers = 96

p = 25\% --- proportion to sign up

Required

The number of customers to sign up

This is calculated as:

n = p * Customers

So, we have:

n = 25\% * 96

n = 24

5 0
2 years ago
python (Business: check ISBN-10) An ISBN-10 (International Standard Book Number) consists of 10 digits: d1d2d3d4d5d6d7d8d9d10. T
iogann1982 [59]

Answer:

<em>The programming language is not stated;</em>

<em>However, I'll answer this question using C++ programming language</em>

<em>The program uses few comments; See explanation section for more detail</em>

<em>Also, the program assumes that all input will always be an integer</em>

#include<iostream>

#include<sstream>

#include<string>

using namespace std;

int main()

{

string input;

cout<<"Enter the first 9 digits of an ISBN as a string: ";

cin>>input;

//Check length

if(input.length() != 9)

{

 cout<<"Invalid input\nLength must be exact 9";

}

else

{

 int num = 0;

//Calculate sum of products

for(int i=0;i<9;i++)

{

 num += (input[i]-'0') * (i+1);    

}

//Determine checksum

if(num%11==10)

{

 input += "X";

 cout<<"The ISBN-10 number is "<<input;

}

else

{

 ostringstream ss;

 ss<<num%11;

 string dig = ss.str();

 cout<<"The ISBN-10 number is "<<input+dig;

}

}  

 return 0;

}

Explanation:

string input;  -> This line declares user input as string

cout<<"Enter the first 9 digits of an ISBN as a string: ";  -> This line prompts the user for input

cin>>input;  -> The user input is stored here

if(input.length() != 9)  { cout<<"Invalid input\nLength must be exact 9";  }  -> Here, the length of input string is checked; If it's not equal to then, a message will be displayed to the screen

If otherwise, the following code segment is executed

else  {

int num = 0; -> The sum of products  of individual digit is initialized to 0

The sum of products  of individual digit is calculated as follows

for(int i=0;i<9;i++)

{

num += (input[i]-'0') * (i+1);

}

The next lines of code checks if the remainder of the above calculations divided by 11 is 10;

If Yes, X is added as a suffix to the user input

Otherwise, the remainder number is added as a suffix to the user input

if(num%11==10)  {  input += "X";  cout<<"The ISBN-10 number is "<<input; }

else

{

ostringstream ss;

ss<<num%11;

string dig = ss.str();

cout<<"The ISBN-10 number is "<<input+dig;

}

}  

5 0
2 years ago
Given two integers as user inputs that represent the number of drinks to buy and the number of bottles to restock, create a Vend
ivann1987 [24]

Answer:

In C++:

#include <iostream>

using namespace std;

class VendingMachine {

 public:

   int initial = 20;};

int main() {

 VendingMachine myMachine;

   int purchase, restock;

   cout<<"Purchase: ";  cin>>purchase;

   cout<<"Restock: ";  cin>>restock;

   myMachine.initial-=(purchase-restock);

   cout << "Inventory: "<<myMachine.initial<<" bottles";  

   return 0;}

Explanation:

This question is incomplete, as the original source file is not given; so, I write another from scratch.

This creates the VendingMachine class

class VendingMachine {

This represents the access specifier

 public:

This initializes the inventory to 20

   int initial = 20;};

The main begins here

int main() {

This creates the object of the VendingMachine class

 VendingMachine myMachine;

This declares the purchase and the restock

   int purchase, restock;

This gets input for purchase

   cout<<"Purchase: ";  cin>>purchase;

This gets input for restock

   cout<<"Restock: ";  cin>>restock;

This calculates the new inventory

   myMachine.initial-=(purchase-restock);

This prints the new inventory

   cout << "Inventory: "<<myMachine.initial<<" bottles";  

   return 0;}

8 0
2 years ago
Define a structure type auto_t to represent an automobile. Include components for the make and model (strings), the odometer rea
yulyashka [42]

Answer:

see explaination

Explanation:

#include <stdio.h>

#include <string.h>

#define BUFSIZE 1000

struct auto_t scan_auto(char *);

struct date_t {

char day[2];

char month[2];

char year[4];

};

struct tank_t {

char tankCapacity[10];

char currentFuelLevel[10];

};

struct auto_t {

char make[50];

char model[50];

char odometerReading[10];

struct date_t manufactureDate;

struct date_t purchaseDate;

struct tank_t gasTank;

};

int main(int argc, char *argv[]) {

/* the first command-line parameter is in argv[1]

(arg[0] is the name of the program) */

FILE *fp = fopen(argv[1], "r"); /* "r" = open for reading */

char buff[BUFSIZE]; /* a buffer to hold what you read in */

struct auto_t newAuto;

/* read in one line, up to BUFSIZE-1 in length */

while(fgets(buff, BUFSIZE - 1, fp) != NULL)

{

/* buff has one line of the file, do with it what you will... */

newAuto = scan_auto(buff);

printf("%s\n", newAuto.make);

}

fclose(fp); /* close the file */

}

struct auto_t scan_auto(char *line) {

int spacesCount = 0;

int i, endOfMake, endOfModel, endOfOdometer;

for (i = 0; i < sizeof(line); i++) {

if (line[i] == ' ') {

spacesCount++;

if (spacesCount == 1) {

endOfMake = i;

}

else if (spacesCount == 2) {

endOfModel = i;

}

else if (spacesCount == 3) {

endOfOdometer = i;

}

}

}

struct auto_t newAuto;

int count = 0;

for (i = 0; i < endOfMake; i++) {

newAuto.make[count++] = line[i];

}

newAuto.make[count] = '\0';

count = 0;

for (i = endOfMake+1; i < endOfModel; i++) {

newAuto.model[count++] = line[i];

}

newAuto.model[count] = '\0';

count = 0;

for (i = endOfModel+1; i < endOfOdometer; i++) {

newAuto.odometerReading[count++] = line[i];

}

newAuto.odometerReading[count] = '\0';

return newAuto;

}

8 0
2 years ago
Return 1 if ptr points to an element within the specified intArray, 0 otherwise.
Paladinen [302]

Answer:

int withinArray(int * intArray, int size, int * ptr) {

      if(ptr == NULL) // if ptr == NULL return 0

            return 0;

      // if end of intArr is reached

      if(size == 0)

          return 0; // element not found

  else  

          {

            if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr

                   return 1; // return 1

            return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements

         }

}

Explanation:

Above is the completion of the program.

4 0
2 years ago
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