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masya89 [10]
1 year ago
9

What is the value of x after each of the following statements is encountered in a computer program, if x=1 before the statement

is reached? Please, justify your answer.
a) if (1+2=3) then x:=x+1
b) if ((1+1=3) OR (2+2=3)) then x:=x+1
c) if ((2+3=5) AND (3+4=7)) then x:=x+1
Computers and Technology
1 answer:
steposvetlana [31]1 year ago
5 0

Answer:

x=2

x=1

x=2

Explanation:

a)

This if statement if (1+2=3) checks if the addition of two numbers 1 and 2 is true. Here the addition of 1 and 2 is 3 which is true. So the condition becomes true.

Since the condition is true x:=x+1 statement is executed. This statement means that the value of x is incremented by 1.

The value of x was 1 before the if statement is reached. So x:=x+1 statement will add 1 to that value of x.

x:=x+1 means x=x+1 which is x=1+1 So x=2

Hence value of x is 2 (x=2) after the execution of x:=x+1

b)

In statement b the value of x will be 1 because both the mathematical operations in the if statement evaluate to false.

which means in b, x:=x+1 will not be executed and value of x remains unchanged i.e x=1

In (c) the value x will be 2 because the condition in the if statement is true. Both mathematical expressions 2+3=5 and 3+4=7 are true. Therefore x:=x+1 will be executed and value of x will be incremented by 1. Hence x=2

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Write a public static method named printArray, that takes two arguments. The first argument is an Array of int and the second ar
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Answer:

Written in Java

public static void printArray(int myarr[], String s){

       for(int i = 0; i<myarr.length;i++){

           System.out.print(myarr[i]+s);

       }

   }

Explanation:

This defines the static method alongside the array and the string variable

public static void printArray(int myarr[], String s){

The following iteration iterates through the elements of the array

       for(int i = 0; i<myarr.length;i++){

This line prints each element of the array followed by the string literal

           System.out.print(myarr[i]+s);

       }

   }

The method can be called from main using:

<em>printArray(myarr,s);</em>

Where myarr and s are local variables of the main

5 0
2 years ago
An administrator has been working within an organization for over 10 years. He has moved between different IT divisions within t
rodikova [14]

Answer:

User roles and access authorization

(Explanation of this question is given below in the explanation section.

Explanation:

As noted in question that a terminated employee comeback in office and installed some malicious script on a computer that was scheduled to run a logic bomb on the first day of the following month. And, that script will change administrator passwords, delete files, and shut down over 100 servers in the data center.

The following problem can be with that account

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The user may be given unauthorized access to system resources. If a user has unauthorized access to system resource then he can modify or destroy the system function easily.

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The firewall should be enabled to detect such types of attack from unauthorized access to the system

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2 years ago
When this program is compiled and executed on an x86-64 Linux system, it prints the string 0x48\n and terminates normally, even
Alexxandr [17]

Answer:

I get 0x55 and this the linking address of the main function.

use this function to see changes:

/* bar6.c */

#include <stdio.h>

char main1;

void p2()

{

printf("0x%X\n", main1);

}

Output is probably 0x0

you can use your original bar6.c with updaated foo.c

char main;

int main() // error because main is already declared

{

  p2();

   //printf("Main address is 0x%x\n",main);

  return 0;

}

Will give u an error

again

int main()

{

  char ch = main;

  p2(); //some value

  printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()

  printf("Char value is 0x%x\n",ch); //last two digit of previous line output

  return 0;

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So the pain in P2() gets the linking address of the main function and it is different from address of the function main.

Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...

Explanation:

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1 year ago
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Answer:

robux

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robux

8 0
1 year ago
Read 2 more answers
Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re
aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)    

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=2.938

The sample deviation calculated s=0.472

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.78

Now we have everything in order to replace into formula (1):

2.938-2.78\frac{0.472}{\sqrt{5}}=2.351    

2.938+2.78\frac{0.472}{\sqrt{5}}=3.525    

So on this case the 95% confidence interval would be given by (2.351;3.525)    

5 0
2 years ago
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