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expeople1 [14]
2 years ago
13

The most commonly used method to connect to a WAN is through the telephone system. To do so, what piece of equipment would you r

equire?
Computers and Technology
2 answers:
Step2247 [10]2 years ago
8 0

Modems create an analog signal that carries digital data on it,
and strip the digital data from an analog signal that they receive. 
That's what's needed to connect through the telephone system,
since the telephone system is still one big analog system.


JulijaS [17]2 years ago
3 0
Modem or router -  the device needs to be able to remove the data information from the audio information.
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Modify the closest pair of points algorithm so that the separating line L now separates the first n/4 points (sorted according t
Nutka1998 [239]

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

3 0
2 years ago
The web development team is having difficulty connecting by ssh to your local web server, and you notice the proper rule is miss
joja [24]

Answer:

Option b (Port 22) seems to the appropriate choice.

Explanation:

<u>Below seem to be some measure you should take to correct this mistake.</u>

  • Verify whether Droplet's host IP address seems to be right.  
  • Verify existing connection supports communication over all the utilized SSH port. Any access points can be able to block port 22 and sometimes customized SSH. For illustration, you could do this by checking different hosts who used the same port, using only a recognized working SSH connection. These could help you identify unless the current problem is not particular to clients' Droplet.
  • Authenticate the Droplet configuration settings. Verify that they're not being configured to DROP 's preferred policy, and do not apply the port to require connectivity.

The SSH server also operates on port 22, by default.  

Other choices don't apply to the specified scenario. So that the argument presented above will be appropriate.

7 0
2 years ago
Write a class with a constructor that accepts a String object as its argument. The class should have a method that returns the n
mote1985 [20]

Answer:

import java.util.Scanner;

public class VowelsAndConsonantsDemo {

   /**

   The printMenu methods displays a menu to the user

    */

   public static void printMenu() {

       System.out.println("Please select an option: ");

       System.out.println();

       System.out.print("a. Count the number of vowels in the string.\n"

               + "b. Count the number of consonants in the string.\n"

               + "c. Count both the vowels and consonants in the string.\n"

               + "d. Enter another string.\n"

               + "e. Exit the program\n");

   }

   public static void main(String[] args) {

       String input;      // to hold the user's input

       String option;     // to hold the user's input

       char choice;       // to hold a single character

       char exit;         // user chooses 'e' to exit the program

       char letter;       //the Y or N from the user's decision to exit

       // create a Scanner object to read keyboard input.

       //  Scanner keyboard = new Scanner(System.in);

       Scanner keyboard;

       do {

           keyboard = new Scanner(System.in);

           // ask user to enter string

           System.out.print("Enter a string: ");

           input = keyboard.nextLine();

           input = input.toLowerCase();

           System.out.println();

           printMenu();

           option = keyboard.nextLine();

           choice = option.charAt(0);

           VowelsAndConsonants words = new VowelsAndConsonants(input);

           switch (choice) {

               case 'a':

               case 'A':

                   System.out.println("Number of Vowels: " + words.getVowels());

                   break;

               case 'b':

               case 'B':

                   System.out.println("Number of Consonants: " + words.getConsonants());

                   break;

               case 'c':

               case 'C':

                   System.out.println("Number of Vowels & Consonants: " + words.getConsonants()

                           + words.getVowels());

                   break;

               case 'd':

               case 'D':

                   System.out.println("Enter a string: ");

                   break;

               case 'e':

               case 'E':

                   System.exit(0);

                   break;

               default:

                   System.out.println("You did not enter a valid choice.");

           }

           //

           // keyboard.nextLine();    //consumes the new line character after the choice

           // String answer = keyboard.nextLine();

           // letter = answer.charAt(0);

       } while (true);

   }

}

4 0
1 year ago
Identify the articulation site that allows us to nod our head ""yes"".
Luden [163]

Answer:

Occipital bone-atlas

Explanation:

The occipital bone is a bone that covers the back of your head; an area called the occiput. The occipital bone is the only bone in your head that connects with your cervical spine (neck).  The occipital bone surrounds a large opening known as the foramen magnum.

The foramen magnum allows key nerves and vascular structures passage between the brain and spine. Namely, it is what the spinal cord passes through to enter the skull. The brainstem also passes through this opening.

The foramen magnum also allows 2 key blood vessels traversing through the cervical spine, called the vertebral arteries, to enter the inner skull and supply blood to the brain

8 0
2 years ago
Let's assume that the smallest possible message is 64 bytes (including the 33-byte overhead). if we use 100base-t, how long (in
Ostrovityanka [42]

As we know that 10-bAse data travels at the rate of 10 mbps, therefore at 1 sec we have 10240 bytes.

We have to calculate for 64 bytes travelling in one second. Multiply both sides by 64.

64 sec = 10240 x 64 bytes

64 bytes = 64 / 10240 sec

Now we have to calculate for light of speed

1 sec = 186000 miles

Substitute this value to the formula above

64 bytes = 64 / 10240 x 1 sec = 64 / 10240 x 186000 miles = 64 / 10240 x 186000 x 5280 feet = 6138x10^3 feet

Therefore, 64 bytes is equal to 6138 x 10^3 feet long message

3 0
2 years ago
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