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expeople1 [14]
2 years ago
13

The most commonly used method to connect to a WAN is through the telephone system. To do so, what piece of equipment would you r

equire?
Computers and Technology
2 answers:
Step2247 [10]2 years ago
8 0

Modems create an analog signal that carries digital data on it,
and strip the digital data from an analog signal that they receive. 
That's what's needed to connect through the telephone system,
since the telephone system is still one big analog system.


JulijaS [17]2 years ago
3 0
Modem or router -  the device needs to be able to remove the data information from the audio information.
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What advantage do ExpressCard modules and USB adapters offer over expansion cards?
ss7ja [257]
<span>ExpressCard modules and USB adapters are faster and smaller. They are easier to plug into a computer and allow a person to add memory, wired and wireless communications, multimedia, and security features by inserting the small card or adapter into a small slot in the computer.</span>
3 0
1 year ago
Write a function string middle(string str) that returns a string containing the middle character in str if the length of str is
Katen [24]

Answer:

function getMiddle(s) {

return s.length % 2 ? s.substr(s.length / 2, 1) : s.substr((s.length / 2) - 1, 2);

}

// I/O stuff

document.getElementById("submit").addEventListener("click", function() {

input = document.getElementById("input").value;

document.getElementById("output").innerHTML = getMiddle(input);

});

Explanation:

// >>> is an unsigned right shift bitwise operator. It's equivalent to division by 2, with truncation, as long as the length of the string does not exceed the size of an integer in Javascript.

// About the ~ operator, let's rather start with the expression n & 1. This will tell you whether an integer n is odd (it's similar to a logical and, but comparing all of the bits of two numbers). The expression returns 1 if an integer is odd. It returns 0 if an integer is even.

// If n & 1 is even, the expression returns 0.

// If n & 1 is odd, the expression returns 1.

// ~n & 1 inverts those two results, providing 0 if the length of the string is odd, and 1 if the length of the sting is even. The ~ operator inverts all of the bits in an integer, so 0 would become -1, 1 would become -2, and so on (the leading bit is always the sign).

// Then you add one, and you get 0+1 (1) characters if the length of the string is odd, or 1+1 (2) characters if the length of the string is even.

6 0
1 year ago
c++ You are given an array A representing heights of students. All the students are asked to stand in rows. The students arrive
Lilit [14]

The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.

#include<stdio.h>

#include<string.h>

 int* uniqueValue(int input1,int input2[])

 {

   int left, current;

   static int arr[4] = {0};

   int i      = 0;

     for(i=0;i<input1;i++)

      {

         current = input2[i];

         left    = 0;

         if(current > 0)

         left    = arr[(current-1)];

      if(left == 0 && arr[current] == 0)

       {

       arr[current] = input1-current;

       }

       else

   {

       for(int j=(i+1);j<input1;j++)

       {

           if(arr[j] == 0)

           {

               left = arr[(j-1)];

               arr[j] = left - 1;

           }

       }

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4 0
2 years ago
Assume the availability of class named IMath that provides a static method, toThePowerOf which accepts two int arguments and ret
geniusboy [140]

Answer:

cubeVolume = IMath.toThePowerOf(cubeSide, 3);

Explanation:

Following is the explanation for above statement:

Left side:

cubeVolume is a variable with data-type int, it will store the integer value that is the output from right side.

Right side:

  • IMath is the class name.
  • toThePowerOf is the built-in function that takes two arguments of data type int. First is the base and second is the power(exponent) separated by comma. In place of first argument that is the base variable we will pass the variable cubeSide that has been declared and initialize.
  • Now the output will be stored in the variable cubeVolume.

i hope it will help you!

4 0
2 years ago
A file named data.txt contains an unknown number of lines, each consisting of a single integer. Write some code that creates two
Damm [24]

Answer:

I am doing it with python.

Explanation:

nums = '9 -8 -7 -6 -5 -4 -2 0 1 5 9 6 7 4'

myfile = open('data.txt', 'w')

myfile.write(nums)

myfile.close()

myfile = open('data.txt', 'r')

num1 = (myfile.read())

num1 = num1.split()

print(num1)

print(type(num1))

for x in num1:

   x = int(x)

   if x < 0:

       minus = open('dataminus.txt', 'a')

       minus.write(str(x) + ' ')

       minus.close()

   elif x>= 0:

       plus = open('dataplus.txt', 'a')

       plus.write(str(x)+' ')

       plus.close()

3 0
2 years ago
Read 2 more answers
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