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borishaifa [10]
2 years ago
6

A network design engineer has been asked to design the IP addressing scheme for a customer network. The network will use IP addr

esses from the 192.168.30.0/24 network. The engineer allocates 254 IP addresses for the hosts on the network but excludes 192.168.30.0/24 and 192.168.30.255/24 IP addresses. Why must the engineer exclude these two IP addresses?
Computers and Technology
1 answer:
Lilit [14]2 years ago
7 0

Answer:

192.168.30.0/24 is the network IP address and 192.168.30.255/24 is the IP broadcast  address.

Explanation:

The first IP (192.168.30.0/24) address of your subnet is the network address,  the last IP (192.168.30.255/24) address of your subnet is your broadcast address and the available usable IP addresses in your subnet are subnet size -2, because network address and broadcast address cannot be allocated to a system.

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