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zalisa [80]
2 years ago
14

Modify the closest pair of points algorithm so that the separating line L now separates the first n/4 points (sorted according t

o their r coordinates) from the remaining 3n/4 points. Write the recurrence relation that gives the running time of the modified algorithm. Is the running time of your algorithm still O(nlog n)? Specify the best asymptotic running time you can get for your algorithm and briefly justify.
Now let the line L separate the first √ n points (according to their x- coordinates) from the remaining n - √ n points. Write the recurrence relation that gives the running time of this modification of the algorithm. Is the running time of your algorithm still O(n log n)? If your answer is yes, provide a brief justification; if your answer is no, provide a (asymptotic) lower bound on the running time of the modified algorithm that should be enough to justify your answer.

Computers and Technology
1 answer:
Nutka1998 [239]2 years ago
3 0

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

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Explanation:

In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.

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